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止于盛夏 2025-02-20 21:38:18

手动运行一个任务以包含所有刺激控制器

包括您在app/javascript/controllers/index.js文件中手动创建的新刺激控制器,您可以运行:

rails stimulus:manifest:update

自动包括新创建的刺激控制器

当您使用发电机从终端创建刺激控制器时,Rails将自动运行清单:更新命令,因此包括您的控制器在JS构建中。

rails generate stimulus controllerName

观看刺激控制器的实时文件更改

以观察刺激控制器的现场更改,需要额外的手表过程。安装Esbuild后,此附加的手表过程将附加到procfile.dev文件。

# Procfilde.dev

web: rails s -p 3000
css: yarn build:css --watch
js: yarn build --watch

纱线构建-Watch命令触发Packacke.json文件中指定的构建命令。

{
  "name": "myapplication",
  "scripts": {
    "build": "esbuild app/javascript/*.* --bundle --outdir=app/assets/builds"
   }
}

Manually running a task to include all stimulus controllers

To include a new stimulus controller that you manually created in the app/javascript/controllers/index.js file, you can run:

rails stimulus:manifest:update

Automatically including a newly created stimulus controller

When you create a stimulus controller from the terminal with the generator, rails will automatically run the manifest:update command and so include your controller in js build.

rails generate stimulus controllerName

Watching for live file changes to stimulus controllers

To watch for live changes to your stimulus controllers, an additional watch process is needed. This additional watch process is appended to the Procfile.dev file after installing esbuild.

# Procfilde.dev

web: rails s -p 3000
css: yarn build:css --watch
js: yarn build --watch

The yarn build --watch command triggers the build command specified in the packacke.json file.

{
  "name": "myapplication",
  "scripts": {
    "build": "esbuild app/javascript/*.* --bundle --outdir=app/assets/builds"
   }
}

如何将所有JS控制器文件自动加载在Rails 7中,将Esbuild作为JavaScript Bundler加载

止于盛夏 2025-02-20 03:47:36

您需要使用getElementById()访问输入元素,然后确保修剪字符串以摆脱任何空间:

function validateform() {  
  var name = document.getElementById("email").value;
  var password = document.getElementById("pass").value;

  if (name.trim() == null || name.trim() == "") {
    alert("Name can't be blank");
    return false;
  } else if (password.trim().length < 6) {
    alert("Password must be at least 6 characters long.");
    return false;
  }
}
<form name="login" onsubmit="return validateform()" method="post" action="/login_process">
  <label for="email">BCBS outlook email</label>
  <br>
  <input type="email" name="email" id="email" text="BCBS outlook email">
  <br>
  <label for="pass">Password</label>
  <br>
  <input type="password" name="pass" id="pass">
  <br>
  <input type="submit" value="submit">
</form>

You need to access the input elements using getElementById(), then make sure you trim your strings to get rid of any spaces:

function validateform() {  
  var name = document.getElementById("email").value;
  var password = document.getElementById("pass").value;

  if (name.trim() == null || name.trim() == "") {
    alert("Name can't be blank");
    return false;
  } else if (password.trim().length < 6) {
    alert("Password must be at least 6 characters long.");
    return false;
  }
}
<form name="login" onsubmit="return validateform()" method="post" action="/login_process">
  <label for="email">BCBS outlook email</label>
  <br>
  <input type="email" name="email" id="email" text="BCBS outlook email">
  <br>
  <label for="pass">Password</label>
  <br>
  <input type="password" name="pass" id="pass">
  <br>
  <input type="submit" value="submit">
</form>

无法使用JS验证形式

止于盛夏 2025-02-19 19:09:26
ID <- c("A", "B", "C", "D", "E", "F")
Q0 <- c(0, 0, 0, 0, 0, 0)
Q1 <- c(0, 1, 0, 0, NA, 1) 
Q2 <- c(0, NA, 1, 0, NA, 1) 
Q3 <- c(0, NA, NA, 1, NA, 1) 
Q4 <- c(0, NA, NA, 1, NA, 1)

df <- data.frame(ID, Q0, Q1, Q2, Q3, Q4)

df[-1] <- t(apply(df[-1], 1, function(x) +(dplyr::cumany(x == 1))))
df
#>   ID Q0 Q1 Q2 Q3 Q4
#> 1  A  0  0  0  0  0
#> 2  B  0  1  1  1  1
#> 3  C  0  0  1  1  1
#> 4  D  0  0  0  1  1
#> 5  E  0 NA NA NA NA
#> 6  F  0  1  1  1  1

ID <- c("A", "B", "C", "D", "E", "F")
Q0 <- c(0, 0, 0, 0, 0, 0)
Q1 <- c(0, 1, 0, 0, NA, 1) 
Q2 <- c(0, NA, 1, 0, NA, 1) 
Q3 <- c(0, NA, NA, 1, NA, 1) 
Q4 <- c(0, NA, NA, 1, NA, 1)

df <- data.frame(ID, Q0, Q1, Q2, Q3, Q4)

df[-1] <- t(apply(df[-1], 1, function(x) +(dplyr::cumany(x == 1))))
df
#>   ID Q0 Q1 Q2 Q3 Q4
#> 1  A  0  0  0  0  0
#> 2  B  0  1  1  1  1
#> 3  C  0  0  1  1  1
#> 4  D  0  0  0  1  1
#> 5  E  0 NA NA NA NA
#> 6  F  0  1  1  1  1

Created on 2022-07-04 by the reprex package (v2.0.1)

从一列到下一个给定条件的复制值

止于盛夏 2025-02-19 17:46:38

在下面的Promula-

=IF(ISNUMBER(MATCH(A1,$C$1:$C$10,0)),1,0)

Try below formula-

=IF(ISNUMBER(MATCH(A1,$C$1:$C$10,0)),1,0)

enter image description here

如果语句参考多个带有字符串的单元格

止于盛夏 2025-02-19 01:31:54

那是多填充。可以在此处找到.NET 6.0的修复:

It was the polyfill. Fix for .NET 6.0 can be found here: #41394 (comment)

大风拖动在.NET Core 3.0和.NET 6.0之间折断

止于盛夏 2025-02-18 10:02:58

使用绑定可以解决问题:

single { it } bind it.javaClass.kotlin

Using bind can solve the issue:

single { it } bind it.javaClass.kotlin

Koin Singleton中的显式类型分配

止于盛夏 2025-02-17 13:55:42

例如,使用最终确定。或tap,如果您希望在每个发射中发生事情(编辑:和/或如果您对发射值感兴趣)而不是完成(如果这样做任何区别)。

const stream1$ = this.job1().pipe(
    finalize(() => this.jodb1Completed = true)
);

const stream2$ = this.job1().pipe(
    finalize(() => this.jodb2Completed = true)
);

forkJoin([stream1$, stream2$]).subscribe(this.finalJob);

With finalize, for example. Or tap, if you want things to happen on every emission (edit: and/or if you are interested in the emitted values), not on completion (and if that makes any difference).

const stream1$ = this.job1().pipe(
    finalize(() => this.jodb1Completed = true)
);

const stream2$ = this.job1().pipe(
    finalize(() => this.jodb2Completed = true)
);

forkJoin([stream1$, stream2$]).subscribe(this.finalJob);

RXJ在多个可观察到完成后完成工作

止于盛夏 2025-02-17 11:26:23

如果我正确阅读了问题,则有列:query_string and Dictionary(这是正确的吗?)。
然后将colpus_id和得分存储在该词典中。

您与大熊猫的第一个目标应该是以熊猫友好的方式工作。避免嵌套词典,将值直接存储在列中。之后,您可以使用有效的熊猫操作。

索引列表并不是您慢的。如果正确执行此操作,则可以是全表合并/加入,并且不需要逐行应用程序和词典查找。

第1步。如果这样做:

target_corpus = pd.Series(sentence_list_2, name="target_corpus")

那么您有一个索引系列的一个语料库(以前是“列表查找”)。

步骤2。获取scorecoldus_id的列在您的主dataFrame

步骤3中。使用 pd.merge cold> coldus_id上加入输入语料库,而的索引> target_corpus并使用how =“ left”(仅与现有colpus_id匹配的项目是相关的)。这应该是一种有效的方法,并且是整个数据帧操作。

开发并测试溶液与一个小子集(1K)以迭代快速生长。

If I read the question correctly, you have the columns: Query_String and dictionary (is this correct?).
And then corpus_id and score are stored in that dictionary.

Your first target with pandas should be to work in a pandas-friendly way. Avoid the nested dictionary, store values directly in columns. After that, you can use efficient pandas operations.

Indexing a list is not what is slow for you. If you do this correctly it can be a whole-table merge/join and won't need any slow row-by-row apply and dictionary lookups.

Step 1. If you do this:

target_corpus = pd.Series(sentence_list_2, name="target_corpus")

Then you have an indexed series of one corpus (formerly the "list lookup").

Step 2. Get columns of score and corpus_id in your main dataframe

Step 3. Use pd.merge to join the input corpus on corpus_id vs the index of target_corpus and using how="left" (only items that match an existing corpus_id are relevant). This should be an efficient way to do it, and it's a whole-dataframe operation.

Develop and test the solution vs a small subset (1K) to iterate quicky then grow.

有没有办法加快通过其索引位置从列表中提取的熊猫功能?

止于盛夏 2025-02-17 08:55:16

查看CSS-tricks中的淘汰文字的帖子
在下面使用它是类似于您的片段。

.gradient {
  overflow: hidden;
  height: 92vh;
  width: 100vw;
  display: flex;
  justify-content: center;
  align-items: center;
  background: linear-gradient(to right, red, red 5%, #fff);
 }
.wall {
  overflow: hidden;
  height: 88vh;
  width: 98vw;
  display: flex;
  justify-content: center;
  align-items: center;
  background-color: #000000;
  color: transparent;
  
  color: white;
  mix-blend-mode: multiply;
 }
<div class='gradient'>
    <p class="wall">Wall Text</p>
</div>

check out the post for Knockout text from css-tricks
using that below is a snippet similar to yours.

.gradient {
  overflow: hidden;
  height: 92vh;
  width: 100vw;
  display: flex;
  justify-content: center;
  align-items: center;
  background: linear-gradient(to right, red, red 5%, #fff);
 }
.wall {
  overflow: hidden;
  height: 88vh;
  width: 98vw;
  display: flex;
  justify-content: center;
  align-items: center;
  background-color: #000000;
  color: transparent;
  
  color: white;
  mix-blend-mode: multiply;
 }
<div class='gradient'>
    <p class="wall">Wall Text</p>
</div>

CSS-继承祖父母Div的颜色的透明文本

止于盛夏 2025-02-16 20:22:34

我使用输出选项作为输入选项并通过音频过滤器有一个函数

ffmpeg(mp3FilePath)
    .audioFilters('highpass=f=300, lowpass=f=3400'
    )
    .outputOptions([
        "-ar 8000",
        '-ac 1'
    ])
    .output(wavFilePath)
    .on('error', (err) => {
        console.log('An error occurred: ' + err.message);
        resolve("failed");
    })
    .on('progress', (progress) => {
        console.log('Processing: ' + progress.targetSize + ' KB converted');
    })
    .on('end', () => {
        console.log('Processing finished !');
    }).run();

I was using output options as input options and to pass audio filter there is a function

ffmpeg(mp3FilePath)
    .audioFilters('highpass=f=300, lowpass=f=3400'
    )
    .outputOptions([
        "-ar 8000",
        '-ac 1'
    ])
    .output(wavFilePath)
    .on('error', (err) => {
        console.log('An error occurred: ' + err.message);
        resolve("failed");
    })
    .on('progress', (progress) => {
        console.log('Processing: ' + progress.targetSize + ' KB converted');
    })
    .on('end', () => {
        console.log('Processing finished !');
    }).run();

输入格式“ HighPass = F = 300,无法流利的FFMPEG NPM

止于盛夏 2025-02-16 19:28:44

设置为百分比

function onEdit(e) {
  const sh = e.range.getSheet();
  if(sh.getName() == "Your sheet name" && e.range.columnStart == 1 && e.range.rowStart == 1 && e.value == "Percentage") {
    sh.getRange("A2").setNumberFormat("0.00%");
  }
  if(sh.getName() == "Your sheet name" && e.range.columnStart == 1 && e.range.rowStart == 1 && e.value != "Percentage") {
    sh.getRange("A2").setNumberFormat("0.################");
  }
}

演示:

“在此处输入图像描述”

Set To Percentage

function onEdit(e) {
  const sh = e.range.getSheet();
  if(sh.getName() == "Your sheet name" && e.range.columnStart == 1 && e.range.rowStart == 1 && e.value == "Percentage") {
    sh.getRange("A2").setNumberFormat("0.00%");
  }
  if(sh.getName() == "Your sheet name" && e.range.columnStart == 1 && e.range.rowStart == 1 && e.value != "Percentage") {
    sh.getRange("A2").setNumberFormat("0.################");
  }
}

Demo:

enter image description here

基于数据验证值的格式单元格

止于盛夏 2025-02-16 17:58:56

您需要在地图div上设置非零高度
高度:100%导致地图div的0px高度。

这些规则之一将起作用。

  • 身高:100VH;
  • 身高:400px;
  • 身高:50REM;

You need to set a non-zero height on the map div.
height: 100% results in a 0px height for your map div.

One of these rules will work.

  • height: 100vh;
  • height: 400px;
  • height: 50rem;

空白的网络地图结果页面 - 无代码错误

止于盛夏 2025-02-16 05:54:25

您可以使用Julia解释器的 command-noreferrer“> command-line”选项 shell中的代码> -v :

julia -v

此系统命令也可以使用eg subprocess从python中调用,

version_output = subprocess.check_output(['julia', '-v'])
print(version_output)

请参见运行shell命令并捕获输出

You can use the julia interpreter's command-line option -v in the shell:

julia -v

This system command can also be invoked from within Python using e.g. subprocess:

version_output = subprocess.check_output(['julia', '-v'])
print(version_output)

See Running shell command and capturing the output

从Python脚本获取Julia版本

止于盛夏 2025-02-16 02:40:05

来自文档

Mariadb从10.7.0开始
为MySQL兼容性添加了For Channel关键字。这与Change Master之后直接使用Channel_name相同。

所以你应该写

CHANGE MASTER 'master1_test116' TO MASTER_HOST='192.168.56.116', MASTER_PORT=3306, MASTER_USER='replica1', MASTER_PASSWORD='pass@123', MASTER_LOG_FILE='mysql-bin.000002', MASTER_LOG_POS=327;

From the documentation:

MariaDB starting with 10.7.0
The FOR CHANNEL keyword was added for MySQL compatibility. This is identical to using the channel_name directly after CHANGE MASTER.

So you should write

CHANGE MASTER 'master1_test116' TO MASTER_HOST='192.168.56.116', MASTER_PORT=3306, MASTER_USER='replica1', MASTER_PASSWORD='pass@123', MASTER_LOG_FILE='mysql-bin.000002', MASTER_LOG_POS=327;

MariaDB服务器版本用于右边的语法,用于靠近频道&#x27; master1_test116&#x27&#x27;&#x27;&#x27;在第1行

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