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走过海棠暮 2024-08-29 04:15:51

不幸的是,快速回答是否定的。但是,您可以非常接近合理的语法:

"""
   You are $compliment!
"""
.replace('$compliment', 'awesome');

至少它比 String.format 更具可读性和可预测性!

The quick answer is no, unfortunately. However, you can come pretty close to a reasonable syntaks:

"""
   You are $compliment!
"""
.replace('$compliment', 'awesome');

It's more readable and predictable than String.format, at least!

字符串格式中的命名占位符

走过海棠暮 2024-08-29 03:37:00

不,他们不是。只有 using 子句中明确列出的变量集才会被自动处理。

No they are not. Only the set of variables explicitly listed in the using clause will be automatically disposed.

using 块中实例化的所有一次性对象是否都已处理?

走过海棠暮 2024-08-29 02:11:26

任何输出到文件/控制台的内容都会产生一些 I/O 开销。在每个垃圾收集事件上增加几毫秒的延迟肯定会对性能产生一些影响。

但实际上,您的应用程序必须经历很多这些过程,并且在您注意到之前承受相当大的负载。不经过测试很难判断。

Anything that outputs to file/console will incur some I/O overhead. Tacking an extra couple ms latency onto every garbage collection event certainly could have some effect on performance.

Realistically speaking though, your application would have to be going through a lot of them and be under quite some load before you'd notice. It's very hard to tell without testing.

Java -verbose:gc 性能影响?

走过海棠暮 2024-08-29 00:47:43

这是因为numpy.multiply.reduce()将范围列表转换为numpy.int32类型的数组,并且reduce操作溢出了可以存储在32位中的内容某些点:

>>> type(numpy.multiply.reduce(range(1, 50, 2)))
<type 'numpy.int32'>

正如 Mike Graham 所说,您可以使用 dtype 参数来使用 Python 整数而不是默认值:

>>> res = numpy.multiply.reduce(range(1, 50, 2), dtype=object)
>>> res
58435841445947272053455474390625L
>>> type(res)
<type 'long'>

但是在这种情况下使用 numpy 处理 python 对象是没有意义的,最好的解决方案是 KennyTM 的:

>>> import functools, operator
>>> functools.reduce(operator.mul, range(1, 50, 2))
58435841445947272053455474390625L

This is because numpy.multiply.reduce() converts the range list to an array of type numpy.int32, and the reduce operation overflows what can be stored in 32 bits at some point:

>>> type(numpy.multiply.reduce(range(1, 50, 2)))
<type 'numpy.int32'>

As Mike Graham says, you can use the dtype parameter to use Python integers instead of the default:

>>> res = numpy.multiply.reduce(range(1, 50, 2), dtype=object)
>>> res
58435841445947272053455474390625L
>>> type(res)
<type 'long'>

But using numpy to work with python objects is pointless in this case, the best solution is KennyTM's:

>>> import functools, operator
>>> functools.reduce(operator.mul, range(1, 50, 2))
58435841445947272053455474390625L

Python的multiply()和prod()结果错误

走过海棠暮 2024-08-28 22:45:19

正如迈克所说,这取决于环境。在 .NET 中,有“Hello {0}”,多种语言使用“Hello %s”,使用 MooTools 的 JavaScript 使用“Hello {name}”等等。 “{0}”和“%s”都取决于参数的顺序(这可能是一个缺点)。

如果您对如何自己实现它感兴趣,这里有一个在 javascript 中使用正则表达式的示例:

// Variables should be an object at the current form:
// {name: 'John', age: 13}
function substitute(string, variables)
{
    var result = string.replace(/\\?\{([^{}]+)\}/g, function(match, name) {
        if(match.charAt(0) == '\\') return match.slice(1); //If there was a backslash before the first {, just return it as it was.
        return (variables[name] != undefined) ? variables[name] : '';
    });
    return result;
}

不应该硬移植到支持正则表达式的其他语言。

As Mike said it depends on the environment. In .NET you have "Hello {0}", several languages uses "Hello %s", JavaScript using MooTools uses "Hello {name}" and so on, and so on. Both the "{0}" and "%s" depends on the order of the arguments (which might be a disadvantage).

If you're interested in how to implement it by yourself here is an example using regular expressions in javascript:

// Variables should be an object at the current form:
// {name: 'John', age: 13}
function substitute(string, variables)
{
    var result = string.replace(/\\?\{([^{}]+)\}/g, function(match, name) {
        if(match.charAt(0) == '\\') return match.slice(1); //If there was a backslash before the first {, just return it as it was.
        return (variables[name] != undefined) ? variables[name] : '';
    });
    return result;
}

It shouldn't bee to hard porting to other languages which support regular expressions.

在文本中嵌入数据字段的最佳方式?

走过海棠暮 2024-08-28 22:30:16

Todd 的脚本非常出色,但无法解决您的问题,即您的浏览器在 SMTP 之前超时。这就是为什么您只能看到页面的一半,并且看不到任何可用于调试 SMTP 设置的错误消息。

解决办法是直接运行PHP脚本。没有超时。

如果由于 ISP 不提供 shell 访问权限而无法执行此操作,请创建一个每分钟运行一次的 cron 作业。 Cron 会将输出通过电子邮件发送给您,其中包含完整的调试详细信息。

Todd's script is excellent, but will not solve your problem which is that your browser times out before the SMTP does. That is why you only see half your page and are not seeing any error messages that you can use to debug your SMTP settings.

The solution is to run the PHP script directly. No timeout.

If you can't do that because your ISP doesn't give you shell access, create a cron job to run every minute. Cron will email the output to you which will have full debug details.

PHP PEAR 邮件的问题

走过海棠暮 2024-08-28 21:00:15
public class XYZ extends Activity {

    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        //setContentView(R.layout.main);

        Calendar c = Calendar.getInstance();
        System.out.println("Current time => "+c.getTime());

        SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
        String formattedDate = df.format(c.getTime());
        // formattedDate have current date/time
        Toast.makeText(this, formattedDate, Toast.LENGTH_SHORT).show();


      // Now we display formattedDate value in TextView
        TextView txtView = new TextView(this);
        txtView.setText("Current Date and Time : "+formattedDate);
        txtView.setGravity(Gravity.CENTER);
        txtView.setTextSize(20);
        setContentView(txtView);
    }

}

在此处输入图像描述

public class XYZ extends Activity {

    /** Called when the activity is first created. */
    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        //setContentView(R.layout.main);

        Calendar c = Calendar.getInstance();
        System.out.println("Current time => "+c.getTime());

        SimpleDateFormat df = new SimpleDateFormat("yyyy-MM-dd HH:mm:ss");
        String formattedDate = df.format(c.getTime());
        // formattedDate have current date/time
        Toast.makeText(this, formattedDate, Toast.LENGTH_SHORT).show();


      // Now we display formattedDate value in TextView
        TextView txtView = new TextView(this);
        txtView.setText("Current Date and Time : "+formattedDate);
        txtView.setGravity(Gravity.CENTER);
        txtView.setTextSize(20);
        setContentView(txtView);
    }

}

enter image description here

在 Android 应用程序中显示当前时间和日期

走过海棠暮 2024-08-28 17:46:32

这个 ApplyCurrentValues in EF 4 问题有答案。

应该是

db.Countries.Attach(db.Countries.Single(c => c.ID == countryToEdit.ID));

如果您附加一个空白存根对象,则布尔字段将初始化为 false。 ApplyCurrentValues 调用发现存根和编辑对象之间的布尔值没有变化。

上面的代码添加了另一个数据库查询,但我可以接受。

This ApplyCurrentValues in EF 4 question has the answer.

It should be

db.Countries.Attach(db.Countries.Single(c => c.ID == countryToEdit.ID));

If you attach a blank stub object the boolean fields are initialised to false. The ApplyCurrentValues call sees no change in the boolean value between the stub and the editied object.

The code above adds another DB query, but I can live with that.

实体框架 4 - 并不总是使用 ApplyCurrentValues 更新布尔属性

走过海棠暮 2024-08-28 16:39:03

您的旋转者从事不同的活动吗?

如果是,那么您可以通过 Intent(请参阅 putExtra 部分)并从下一个活动中检索值,以便您可以相应地设置下一个微调器。

编辑:

这是一个更改第二个和第三个微调器中所选项目的示例。 更新侦听器(onItemSelected 方法)

使用您的逻辑Activity

private Spinner s;
private Spinner s2;
private Spinner s3;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    setContentView(R.layout.main);
    String[] myList = new String[] { "Hello", "World", "Foo", "Bar" };
    String[] myList2 = new String[] { "Hello2", "World2", "Foo2", "Bar2" };
    String[] myList3 = new String[] { "Hello3", "World3", "Foo3", "Bar3" };

    s = (Spinner) findViewById(R.id.spinner1);
    s2 = (Spinner) findViewById(R.id.spinner2);
    s3 = (Spinner) findViewById(R.id.spinner3);

    s.setAdapter(new ArrayAdapter<String>(this,android.R.layout.simple_spinner_item, myList));
    s2.setAdapter(new ArrayAdapter<String>(this,android.R.layout.simple_spinner_item, myList2));
    s3.setAdapter(new ArrayAdapter<String>(this,android.R.layout.simple_spinner_item, myList3));


    s.setOnItemSelectedListener(new OnItemSelectedListener(){

        @Override
        public void onItemSelected(AdapterView<?> parent, View v,
                int pos, long id) {
            s2.setSelection(pos);
            s3.setSelection(pos);
        }

        @Override
        public void onNothingSelected(AdapterView<?> arg0) {


        }});
}

: main.xml:

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout android:layout_width="fill_parent" xmlns:android="http://schemas.android.com/apk/res/android"
         android:layout_height="wrap_content"
        android:orientation="vertical">
<Spinner android:id="@+id/spinner1" android:layout_height="wrap_content" android:layout_width="fill_parent" />
<Spinner android:id="@+id/spinner2" android:layout_height="wrap_content" android:layout_width="fill_parent" />
<Spinner android:id="@+id/spinner3" android:layout_height="wrap_content" android:layout_width="fill_parent" />
</LinearLayout>

Are your spinners in different activities?

If they are, so you can just pass the selected value of the first spinner via Intent (See the putExtra section) and retrieve the value from the next activity so that you can set accordingly the next spinners.

Edit:

Here is an example that changes the selected item in the 2nd and 3rd spinner. Update the listener (onItemSelected method) with your logic

Activity:

private Spinner s;
private Spinner s2;
private Spinner s3;

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    setContentView(R.layout.main);
    String[] myList = new String[] { "Hello", "World", "Foo", "Bar" };
    String[] myList2 = new String[] { "Hello2", "World2", "Foo2", "Bar2" };
    String[] myList3 = new String[] { "Hello3", "World3", "Foo3", "Bar3" };

    s = (Spinner) findViewById(R.id.spinner1);
    s2 = (Spinner) findViewById(R.id.spinner2);
    s3 = (Spinner) findViewById(R.id.spinner3);

    s.setAdapter(new ArrayAdapter<String>(this,android.R.layout.simple_spinner_item, myList));
    s2.setAdapter(new ArrayAdapter<String>(this,android.R.layout.simple_spinner_item, myList2));
    s3.setAdapter(new ArrayAdapter<String>(this,android.R.layout.simple_spinner_item, myList3));


    s.setOnItemSelectedListener(new OnItemSelectedListener(){

        @Override
        public void onItemSelected(AdapterView<?> parent, View v,
                int pos, long id) {
            s2.setSelection(pos);
            s3.setSelection(pos);
        }

        @Override
        public void onNothingSelected(AdapterView<?> arg0) {


        }});
}

main.xml:

<?xml version="1.0" encoding="utf-8"?>
<LinearLayout android:layout_width="fill_parent" xmlns:android="http://schemas.android.com/apk/res/android"
         android:layout_height="wrap_content"
        android:orientation="vertical">
<Spinner android:id="@+id/spinner1" android:layout_height="wrap_content" android:layout_width="fill_parent" />
<Spinner android:id="@+id/spinner2" android:layout_height="wrap_content" android:layout_width="fill_parent" />
<Spinner android:id="@+id/spinner3" android:layout_height="wrap_content" android:layout_width="fill_parent" />
</LinearLayout>

在微调器中选择项目后更新内容

走过海棠暮 2024-08-28 16:22:35
NSString *path = [[NSBundle mainBundle] pathForResource:@"plistfilename" ofType:@"plist"];
NSDictionary *dict = [[NSDictionary alloc] initWithContentsOfFile:[NSString stringWithFormat:@"%@", path]];

NSString *body = [dict objectForKey:@"Keyname"];

使用它任何人都可以从 plist 文件中读取数据。

NSString *path = [[NSBundle mainBundle] pathForResource:@"plistfilename" ofType:@"plist"];
NSDictionary *dict = [[NSDictionary alloc] initWithContentsOfFile:[NSString stringWithFormat:@"%@", path]];

NSString *body = [dict objectForKey:@"Keyname"];

with the use of this anyone can read data from plist file.

iPhone从文件中读取

走过海棠暮 2024-08-28 15:22:24

手册页

如果errno返回值为0且函数返回
FALSE,这表明
在 connect() 之前发生错误
称呼。这很可能是由于
初始化套接字时出现问题。

From the man page:

If the value returned in errno is 0 and the function returned
FALSE, it is an indication that the
error occurred before the connect()
call. This is most likely due to a
problem initializing the socket.

在 PHP 中 - 有没有办法知道 fsockopen 何时超时?

走过海棠暮 2024-08-28 14:13:19

我开始寻找一个矢量化的解决方案,以避免
lapply()跨长向量的单字符串解决方案之一。失败
为了找到现有的解决方案,我不知何故掉进了一个兔子洞
煞费苦心地用 C 语言写了一个。相比之下,它最终变得非常复杂
此处显示的许多单行 R 解决方案(不,感谢我决定也
想要处理 Unicode 字符串以匹配 R 版本),但我想我会
分享结果,以防有一天它能以某种方式帮助某人。这是什么
最终变成了这样:

#define R_NO_REMAP
#include <R.h>
#include <Rinternals.h>

// Find the width (in bytes) of a UTF-8 character, given its first byte
size_t utf8charw(char b) {
  if (b == 0x00) return 0;
  if ((b & 0x80) == 0x00) return 1;
  if ((b & 0xe0) == 0xc0) return 2;
  if ((b & 0xf0) == 0xe0) return 3;
  if ((b & 0xf8) == 0xf0) return 4;
  return 1; // Really an invalid character, but move on
}

// Find the number of UTF-8 characters in a string
size_t utf8nchar(const char* str) {
  size_t nchar = 0;
  while (*str != '\0') {
    str += utf8charw(*str); nchar++;
  }
  return nchar;
}

SEXP C_str_chunk(SEXP x, SEXP size_) {
  // Allocate a list to store the result
  R_xlen_t n = Rf_xlength(x);
  SEXP result = PROTECT(Rf_allocVector(VECSXP, n));

  int size = Rf_asInteger(size_);

  for (R_xlen_t i = 0; i < n; i++) {
    const char* str = Rf_translateCharUTF8(STRING_ELT(x, i));

    // Figure out number of chunks
    size_t nchar = utf8nchar(str);
    size_t nchnk = nchar / size + (nchar % size != 0);
    SEXP chunks = PROTECT(Rf_allocVector(STRSXP, nchnk));

    for (size_t j = 0, nbytes = 0; j < nchnk; j++, str += nbytes) {
      // Find size of next chunk in bytes
      nbytes = 0;
      for (int cp = 0; cp < size; cp++) {
        nbytes += utf8charw(str[nbytes]);
      }
      
      // Assign to chunks vector as an R string
      SET_STRING_ELT(chunks, j, Rf_mkCharLenCE(str, nbytes, CE_UTF8));
    }

    SET_VECTOR_ELT(result, i, chunks);
  }

  // Clean up
  UNPROTECT(n);
  UNPROTECT(1);

  return result;
}

然后我将这个怪物放入一个名为 str_chunk.c 的文件中,并使用 R CMD SHLIB str_chunk.c 进行编译。
为了尝试一下,我们需要在 R 端进行一些设置:

str_chunk <- function(x, n) {
  .Call("C_str_chunk", x, as.integer(n))
}

# The (currently) accepted answer
str_chunk_one <- function(x, n) {
  substring(x, seq(1, nchar(x), n), seq(n, nchar(x), n))
}

dyn.load("str_chunk.dll")

所以我们在 C 版本中实现的是获取向量输入并返回一个列表:

str_chunk(rep("0123456789AB", 2), 2)
#> [[1]]
#> [1] "01" "23" "45" "67" "89" "AB"
#> 
#> [[2]]
#> [1] "01" "23" "45" "67" "89" "AB"

现在我们开始进行基准测试。

我们以 200 倍的改进开始,对于长向量
短弦:

x <- rep("0123456789AB", 1000)
microbenchmark::microbenchmark(
  accepted = lapply(x, str_chunk_one, 2),
  str_chunk(x, 2)
) |> print(unit = "relative")
#> Unit: relative
#>             expr      min       lq     mean  median       uq      max neval
#>         accepted 229.5826 216.8246 182.5449 203.785 182.3662 25.88823   100
#>  str_chunk(x, 2)   1.0000   1.0000   1.0000   1.000   1.0000  1.00000   100

……然后缩小到明显不那么令人印象深刻的 3 倍改进
大字符串。

x <- rep(strrep("0123456789AB", 1000), 10)
microbenchmark::microbenchmark(
  accepted = lapply(x, str_chunk_one, 2),
  str_chunk(x, 2)
) |> print(unit = "relative")
#> Unit: relative
#>             expr     min       lq     mean   median       uq      max neval
#>         accepted 2.77981 2.802641 3.304573 2.787173 2.846268 13.62319   100
#>  str_chunk(x, 2) 1.00000 1.000000 1.000000 1.000000 1.000000  1.00000   100

dyn.unload("str_chunk.dll")

那么,值得吗?好吧,绝对不考虑花了多长时间
实际上可以正常工作 - 但如果这是在一个包中,它就会
在我的用例中节省了大量时间(短字符串,长向量)。

I set out looking for a vectorised solution to this, in order to avoid
lapply()ing one of the single string solutions across long vectors. Failing
to find an existing solution, I somehow fell down a rabbit hole of
painstakingly writing one in C. It ended up hilariously complicated compared
to the many one-line R solutions shown here (no thanks to me deciding to also
want to handle Unicode strings to match the R versions), but I thought I’d
share the result, in case it somehow someday helps somebody. Here’s what
eventually became of that:

#define R_NO_REMAP
#include <R.h>
#include <Rinternals.h>

// Find the width (in bytes) of a UTF-8 character, given its first byte
size_t utf8charw(char b) {
  if (b == 0x00) return 0;
  if ((b & 0x80) == 0x00) return 1;
  if ((b & 0xe0) == 0xc0) return 2;
  if ((b & 0xf0) == 0xe0) return 3;
  if ((b & 0xf8) == 0xf0) return 4;
  return 1; // Really an invalid character, but move on
}

// Find the number of UTF-8 characters in a string
size_t utf8nchar(const char* str) {
  size_t nchar = 0;
  while (*str != '\0') {
    str += utf8charw(*str); nchar++;
  }
  return nchar;
}

SEXP C_str_chunk(SEXP x, SEXP size_) {
  // Allocate a list to store the result
  R_xlen_t n = Rf_xlength(x);
  SEXP result = PROTECT(Rf_allocVector(VECSXP, n));

  int size = Rf_asInteger(size_);

  for (R_xlen_t i = 0; i < n; i++) {
    const char* str = Rf_translateCharUTF8(STRING_ELT(x, i));

    // Figure out number of chunks
    size_t nchar = utf8nchar(str);
    size_t nchnk = nchar / size + (nchar % size != 0);
    SEXP chunks = PROTECT(Rf_allocVector(STRSXP, nchnk));

    for (size_t j = 0, nbytes = 0; j < nchnk; j++, str += nbytes) {
      // Find size of next chunk in bytes
      nbytes = 0;
      for (int cp = 0; cp < size; cp++) {
        nbytes += utf8charw(str[nbytes]);
      }
      
      // Assign to chunks vector as an R string
      SET_STRING_ELT(chunks, j, Rf_mkCharLenCE(str, nbytes, CE_UTF8));
    }

    SET_VECTOR_ELT(result, i, chunks);
  }

  // Clean up
  UNPROTECT(n);
  UNPROTECT(1);

  return result;
}

I then put this monstrosity into a file called str_chunk.c, and compiled with R CMD SHLIB str_chunk.c.
To try it out, we need some set-up on the R side:

str_chunk <- function(x, n) {
  .Call("C_str_chunk", x, as.integer(n))
}

# The (currently) accepted answer
str_chunk_one <- function(x, n) {
  substring(x, seq(1, nchar(x), n), seq(n, nchar(x), n))
}

dyn.load("str_chunk.dll")

So what we’ve achieved with the C version is to take a vector inputs and return a list:

str_chunk(rep("0123456789AB", 2), 2)
#> [[1]]
#> [1] "01" "23" "45" "67" "89" "AB"
#> 
#> [[2]]
#> [1] "01" "23" "45" "67" "89" "AB"

Now off we go with benchmarking.

We start off strong with a 200x improvement for a long(ish) vector of
short strings:

x <- rep("0123456789AB", 1000)
microbenchmark::microbenchmark(
  accepted = lapply(x, str_chunk_one, 2),
  str_chunk(x, 2)
) |> print(unit = "relative")
#> Unit: relative
#>             expr      min       lq     mean  median       uq      max neval
#>         accepted 229.5826 216.8246 182.5449 203.785 182.3662 25.88823   100
#>  str_chunk(x, 2)   1.0000   1.0000   1.0000   1.000   1.0000  1.00000   100

… which then shrinks to a distinctly less impressive 3x improvement for
large strings.

x <- rep(strrep("0123456789AB", 1000), 10)
microbenchmark::microbenchmark(
  accepted = lapply(x, str_chunk_one, 2),
  str_chunk(x, 2)
) |> print(unit = "relative")
#> Unit: relative
#>             expr     min       lq     mean   median       uq      max neval
#>         accepted 2.77981 2.802641 3.304573 2.787173 2.846268 13.62319   100
#>  str_chunk(x, 2) 1.00000 1.000000 1.000000 1.000000 1.000000  1.00000   100

dyn.unload("str_chunk.dll")

So, was it worth it? Well, absolutely not considering how long it took to
actually get working properly – But if this was in a package, it would have
saved quite a lot of time in my use-case (short strings, long vectors).

将字符串切成固定宽度字符元素的向量

走过海棠暮 2024-08-28 13:35:28

默认情况下,Yahoo 帐户未启用 OpenID,但您可以通过访问此网站轻松启用 OpenID。

Yahoo accounts are not OpenID enabled by default but you can easily make them so by visiting this site.

我如何检查我的 openid 日志记录系统是否正在接受和处理 yahoo openid?

走过海棠暮 2024-08-28 10:07:57

尝试 git update-index --assume-unchanged --。对于源代码控制下的文件,它的作用类似于 gitignore。不过,该功能的最初目的是提高 git 检查包含大量文件的文件夹中的修改的性能。这是 doco:

--假设不变
--no-假设不变

当指定这些标志时,记录的对象名称
路径未更新。相反,这些
选项设置和取消设置“假设
路径的“未更改”位。当
“假设不变”位已打开,git
停止检查工作树文件
对于可能的修改,所以你
需要手动取消设置该位来告诉
git 当你改变工作树时
文件。有时这会很有帮助
正在处理一个大项目
lstat(2) 非常慢的文件系统
系统调用(例如cifs)。

此选项也可以用作粗略的文件级机制来忽略
跟踪文件中未提交的更改
(类似于 .gitignore 的作用
未跟踪的文件)。你应该记住
显式 git add 操作
仍然会导致文件
从工作树中刷新。 git
会(优雅地)失败,以防万一
需要修改索引中的这个文件
例如,在合并提交时;因此,
如果假设的未跟踪文件是
更改上游,您将需要
手动处理这种情况。

try git update-index --assume-unchanged --<path>. It acts like gitignore for files under source control. The original purpose of the feature though, was to improve performance of git checking modifications in a folder with lots of files. Here is the doco:

--assume-unchanged
--no-assume-unchanged

When these flags are specified, the object names recorded for the
paths are not updated. Instead, these
options set and unset the "assume
unchanged" bit for the paths. When the
"assume unchanged" bit is on, git
stops checking the working tree files
for possible modifications, so you
need to manually unset the bit to tell
git when you change the working tree
file. This is sometimes helpful when
working with a big project on a
filesystem that has very slow lstat(2)
system call (e.g. cifs).

This option can be also used as a coarse file-level mechanism to ignore
uncommitted changes in tracked files
(akin to what .gitignore does for
untracked files). You should remember
that an explicit git add operation
will still cause the file to be
refreshed from the working tree. Git
will fail (gracefully) in case it
needs to modify this file in the index
e.g. when merging in a commit; thus,
in case the assumed-untracked file is
changed upstream, you will need to
handle the situation manually.

让 Git 对我的更改视而不见的更好方法

走过海棠暮 2024-08-28 08:15:05

mimetic 声称支持它。我认为 GNU cgicc 也可能支持它。

mimetic claims to support it. I think GNU cgicc may also support it.

C 或 C++ 中是否有轻量级的多部分/表单数据解析器?

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