走过海棠暮

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走过海棠暮 2024-11-02 11:40:29

如果用户调整字段大小,可能是因为他们希望(或需要)它变大1

在这种情况下,您应该考虑您的用户知道他们在做什么,这样做是因为他们想要/需要,并且他们会接受布局有点损坏,只要它允许他们使用该文本区域。

不过,如果您想这样做(您不应该),请引用如何禁用文本区域调整大小? :

textarea {
    resize: none;
} 

1.我看得不太清楚,当我缩放或使某些东西更大时,这是因为我也需要 - 并且,在这种情况下,我更喜欢布局有点破损的网站,而不是我无法使用的网站!

If users resize the field, it's probably because they want (or need) it to be bigger 1.

In such a case, you should consider your users know what they are doing, are doing it because they want / need to, and that they will accept the layout to be a little broken, provided it allows them to use that textarea.

Still, if you want to do that (you shouldn't), quoting How do I disable textarea resizing? :

textarea {
    resize: none;
} 

1. I don't see very well, and when I zoom, or make something bigger, it's because I need too -- and, in such a case, I prefer a layout a bit broken to a website I cannot use !

如何禁用用户动态调整多行输入大小?

走过海棠暮 2024-11-02 08:13:19

在我看来,如果您加载具有两个文件名的图像,我认为您应该将它们保留在磁盘上。如果没有,您可以删除其中一个。无论您设置什么像素大小,原始像素数据始终是您从磁盘加载的图像文件。

In my opinion,If you load the image with the two file name, I think you should keep them on disk.If not, you can delete one of them. Nomatter what pixels size you set, the original pixels datas are always which image file you load from disk.

对于 UIImage,使用 @2x 不复制文件

走过海棠暮 2024-11-02 07:47:56

我知道您无法为 Silverlight 4 编写调试可视化工具,但我不太清楚为什么。 Josh Smith 在提到 Mole 2010 时也说了同样的话(请参阅前几条评论)。

我确实知道您无法在 XAML 设计视图的设计图面上显示 Silverlight 控件,这可能是相关的。

I know that you cannot write a debug visualizer for Silverlight 4, but I'm not exactly sure why. Josh Smith says as much in reference to Mole 2010 (see the first couple of comments).

I do know that you cannot display Silverlight controls on the design surface of the XAML design view, which is probably related.

无法为 Silverlight 4 编写调试可视化工具?

走过海棠暮 2024-11-01 22:48:08

不确定标题,但我会研究三次样条插值。您可以查看此网站。它有一种非常巧妙的方法来执行三次插值。我不确定如何修改标头,但我很确定 Stack Overflow 上已经有您可以搜索的答案。

Not sure about the header, but I would look into cubic spline interpolation. You could look at this website. It's got a very neat way of performing cubic interpolation. I'm not sure how to modify the header, but I'm pretty sure there have been answers to that on Stack Overflow that you could search for.

用于上采样的 PCM 算法

走过海棠暮 2024-11-01 15:25:41

如果您有不同的频道可以read(),那么您一定应该使用不同的次要号码。想象一下,您有一张带有四个串行端口的卡,您肯定需要四个 /dev/ttySx
但您的设备适合这个型号吗?

If you have different chanel you can read() from, then you should definitely use different minor number. Imagine you have a card whith four serial port, you would definitely want four /dev/ttySx.
But does your device fit whith this model ?

Linux 设备驱动程序处理多个中断源/向量

走过海棠暮 2024-11-01 14:00:23

Javaamtho 可能指的是 facebook 页面的赞框

http://developers.facebook .com/docs/reference/plugins/like-box/

这是一个漂亮的工具,可以对其进行一些自定义

http:// /prettylikebox.com/

Javaamtho may be referring to the like box for facebook pages

http://developers.facebook.com/docs/reference/plugins/like-box/

and here's a nifty tool to customize it a bit

http://prettylikebox.com/

如何在 Facebook 上显示“likebox”在我的网站上?

走过海棠暮 2024-11-01 08:36:02

抱歉,这不是您问题的直接答案,但您可能需要考虑使用 XMLHttpRequest 的 HTML5 文件 API。

var req = new XMLHttpRequest();
req.upload.addEventListener("progress", updateProgress, false);
// ...
req.open();
// ...

developer.mozilla.org 上有一些示例。

缺点是它依赖于浏览器。优点是它独立于服务器。但最终,这将是跟踪文件上传的最佳方式。

Sorry, this isn't a direct answer to your question, but you may want to consider the HTML5 file API with XMLHttpRequest.

var req = new XMLHttpRequest();
req.upload.addEventListener("progress", updateProgress, false);
// ...
req.open();
// ...

There are some examples on developer.mozilla.org.

The downside is that it is browser dependent. The upside is that it is server independent. But ultimately, this will be the best way to track file uploads.

lightppd 中使用 APC 进行 PHP 上传

走过海棠暮 2024-10-31 20:35:40

cftool(X,Y) 就是要走的路。
这是一些链接:

LINK1
LINK2

cftool(X,Y) is the way to go.
here's some linkage:

LINK1
LINK2

Matlab中通过数据点拟合指数曲线

走过海棠暮 2024-10-31 02:19:08

您需要通过包含定义该类的标头来提供 Point 类的定义。例如:

#include "TemplatedClass.h"
#include "Point.h"   // if this header contains the Point's declaration
using namespace std;
class PointList
{
public:
    PointList(TemplatedClass<Point> *p);
//snip
};

编辑

实际上,由于您的方法需要一个指针,因此您可以只转发声明:

template< typename T > class TemplatedClass;
class Point;
using namespace std;
class PointList
{
public:
    PointList(TemplatedClass<Point> *p);
//snip
};

但是然后在源(cpp)文件中您需要包含这些标头

You need to provide the definition of the Point class by including a header where that class is defined. For example :

#include "TemplatedClass.h"
#include "Point.h"   // if this header contains the Point's declaration
using namespace std;
class PointList
{
public:
    PointList(TemplatedClass<Point> *p);
//snip
};

EDIT

Actually, since your method takes a pointer, you can just forward declare :

template< typename T > class TemplatedClass;
class Point;
using namespace std;
class PointList
{
public:
    PointList(TemplatedClass<Point> *p);
//snip
};

but then in the source (cpp) file you need to include those headers

如何使用指向模板类型的指针

走过海棠暮 2024-10-31 00:15:28

只需在 onCreate 方法中注册上下文菜单,

@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
TextView tv = (TextView)this.findViewById(R.id.textViewId);
registerForContextMenu(this.getTextView());
}

通过添加项目在此处创建上下文菜单

@Override
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenuInfo menuInfo)
{
menu.setHeaderTitle("Sample Context Menu");
menu.add(200, 200, 200, "item1");
}

,在此处响应所选项目

 @Override
public boolean onContextItemSelected(MenuItem item)
{
if (item.itemId() = some-menu-item-id)
{
//handle this menu item
return true;
}
… other exception processing
}

只需运行并获取上下文菜单:)

just register for context menu in onCreate method

@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
TextView tv = (TextView)this.findViewById(R.id.textViewId);
registerForContextMenu(this.getTextView());
}

create ContextMenu here by adding item

@Override
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenuInfo menuInfo)
{
menu.setHeaderTitle("Sample Context Menu");
menu.add(200, 200, 200, "item1");
}

respond here for selected item

 @Override
public boolean onContextItemSelected(MenuItem item)
{
if (item.itemId() = some-menu-item-id)
{
//handle this menu item
return true;
}
… other exception processing
}

just run and get your context menu :)

上下文菜单创建

走过海棠暮 2024-10-30 16:52:13

在大多数从头开始的过程中,在写入平面文件之前,即使没有执行任何转换,也会在写入文件之前或写入文件的步骤之前对数据执行一些转换,存在中间 DML,其中包含每列的数据定义,其中大部分是通用定义,您所需要做的就是要求 ab-initio 开发人员向您发送该通用 dml 的副本,然后您可以将此 DML 发送到java 中的映射值。希望这有帮助。

In most ab-inito processes, just before a flat file is written, some transformation is performed on the data, even if there in no transformation performed, before writing to the file, or a step before the step that writes to the file, an intermediate DML is present which contains the data definitions for each columns, most of these are generic definitions, all you need to do is ask the ab-initio developer to send you a copy of that generic dml, and then you can you this DML to map values in java. Hope this helps.

如何将其他语言的数据映射到java

走过海棠暮 2024-10-29 19:48:43

您确定需要 groups_users 表吗?每个用户不是只能属于一个组吗?

如果您只需将组 id 作为外键放入用户表中,您将能够更轻松地完成此操作

    CREATE TABLE IF NOT EXISTS `users` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `email` varchar(64) NOT NULL,
  `password` varchar(64) NOT NULL,
  `enabled` tinyint(1) NOT NULL,
  `created` datetime NOT NULL,
  `modified` datetime NOT NULL,
  `group_id` int(11) NOT NULLL,
  PRIMARY KEY (`id`),
  UNIQUE KEY `email` (`email`)
)

然后您可以将用户是否应该能够

在您的 app_controller 中看到某些信息发送到视图。 php 添加以下内容

function beforeFilter(){
    $this->set('users_role', $this->Auth->user('group_id'));
}

现在您的视图将有一个可访问的变量,该变量将是 $users_role... 然后您可以在视图中执行以下操作。

<?php if($users_role == 1 ): ?>
    //show records available to admins
<?php elseif ($users_role == 2): ?>
    //show records available to logged in users
<?php else : ?>
    //show records for all users
<?php endif; ?>

Are you sure that you need the groups_users table? Wouldn't each user only be able to belong to one group?

You will be able to accomplish this much easier if you just bring the group id into the users table as a foreign key

    CREATE TABLE IF NOT EXISTS `users` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `email` varchar(64) NOT NULL,
  `password` varchar(64) NOT NULL,
  `enabled` tinyint(1) NOT NULL,
  `created` datetime NOT NULL,
  `modified` datetime NOT NULL,
  `group_id` int(11) NOT NULLL,
  PRIMARY KEY (`id`),
  UNIQUE KEY `email` (`email`)
)

Then you can send to the view whether or not the user should be able to see certain information...

in your app_controller.php add the following

function beforeFilter(){
    $this->set('users_role', $this->Auth->user('group_id'));
}

Now you will have a variable accessable by your view which will be $users_role... then you can perform the following in your view.

<?php if($users_role == 1 ): ?>
    //show records available to admins
<?php elseif ($users_role == 2): ?>
    //show records available to logged in users
<?php else : ?>
    //show records for all users
<?php endif; ?>

cakePHP如何获取权限

走过海棠暮 2024-10-29 06:29:18

不,PHP 没有这样的东西。 PHP 中最接近的近似方法是使用单引号字符串作为哈希键 - 只是为了确保其中不会有“插值”。

几个例子:

  • $arr[key] - 在大多数情况下,这与 $arr['key'] 一样工作,但有几个缺点:
    a) 如果确实存在定义的常量(例如,define('key', 'rubbish') - 您将访问$arr['rubish']。所以,这根本不安全。
    b) 它将生成“PHP 通知”消息(除非通知被抑制)

  • $arr[@key] — 就像以前一样,但没有通知。事实上,错误抑制在可维护性方面非常糟糕。

  • $arr["key"] — 绝对有效的方式,除非双引号字符串中有一些特殊符号。例如:"ab\ntc" != 'ab\ntc'"ab$c" != 'ab$c' 等等。但我相信,想到这种情况有点偏执。

  • $arr['key'] — 在我看来,这是最接近 PHP 中的 Ruby 的 arr[:key]

No, PHP does not have anything like this. The most close approximation in PHP would be to use single-quoted strings for your hash keys — just to make sure there would be no "interpolations" in them.

Few examples:

  • $arr[key] — this would work like $arr['key'] in most cases, but has couple of drawbacks:
    a) if there is indeed a defined constant (e.g., define('key', 'rubbish') — you'll access $arr['rubish']. So, it's simply unsafe.
    b) it would produce "PHP Notice" messages (unless notices are suppressed)

  • $arr[@key] — just like before, but without notices. In fact, errors suppressing is very bad in terms of maintainability.

  • $arr["key"] — absolutely valid way, unless you have some special symbols inside the double-quoted string. For example: "ab\ntc" != 'ab\ntc', "ab$c" != 'ab$c' and so on. But its a bit paranoid to think of such cases, I believe.

  • $arr['key'] — this is, to my opinion, the closest to Ruby's arr[:key] as you could get in PHP.

PHP 相当于 Ruby 符号

走过海棠暮 2024-10-29 06:07:30

3 年后我偶然发现了这个问题;)

有趣的事实是 imagemagick 本身存在于 javascript 中。
但 google (page1) 和 github 不知何故找不到它。
Github 失败是因为主项目(有用的 emscripten ports)

UNIX 工具箱.js

仅由模块组成...

这是带有自述文件的主要项目:
github : manuels/unix-toolbox.js

git clone ... --recursive

和特定模块:
github:manuels/unix-toolbox.js-imagemagick

3 years later I stumbled upon this question ;)

The fun fact is that imagemagick itself exists in javascript.
But google (page1) and github somehow do not find it.
Github fails because the main project (useful emscripten ports)

UNIX toolbox.js

just consists of the modules ...

Here is the main project with readme:
github : manuels/unix-toolbox.js

git clone ... --recursive

and the particular module :
github : manuels/unix-toolbox.js-imagemagick

类似于 Imagemagick 的 JavaScript 库(即调整图像和图片的大小,同时最大化图片保真度)?

走过海棠暮 2024-10-29 05:51:16

虽然我不能 100% 确定你的意图,但我认为你的目标是取代
fileLine 中的每个匹配子字符串与 valuesMap 的相应值。
如果是这样,以下代码可能会满足您的目的:

  ...same as your code...

  while ( regex_search( begin, end, what, expression, flags ) ) {
    outLine.insert( outLine.end(), begin, what[0].first );
    outLine += valuesMap[what[0]];
    begin = what[0].second;
  }

  outLine.insert( outLine.end(), begin, end );

希望这会有所帮助

Though I'm not 100% sure about your intent, I presume your goal is replacing
each matched substring in fileLine with the corresponding value of valuesMap.
If so, the following code might meet your purpose:

  ...same as your code...

  while ( regex_search( begin, end, what, expression, flags ) ) {
    outLine.insert( outLine.end(), begin, what[0].first );
    outLine += valuesMap[what[0]];
    begin = what[0].second;
  }

  outLine.insert( outLine.end(), begin, end );

Hope this helps

带 Boost 的 regex_search 和 regex_replace

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