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可遇━不可求 2025-02-02 19:40:53

parse_number 的完美用例，来自 readr 它在 tidyverse 中：
来自@andrewgb的数据（非常感谢）

library(dplyr)
library(readr)

data_exp_59965_v11_task_j84b %>% 
  mutate(`X Coordinate` = parse_number(`X Coordinate`))

  X Coordinate
1     -401.222
2      401.222
3     -200.611
4           NA
5           NA

Perfect use case for parse_number from readr it is in tidyverse:
Data from @AndrewGB (many thanks)

library(dplyr)
library(readr)

data_exp_59965_v11_task_j84b %>% 
  mutate(`X Coordinate` = parse_number(`X Coordinate`))

  X Coordinate
1     -401.222
2      401.222
3     -200.611
4           NA
5           NA

如何从数字单元格中删除字母，以使列完全数字化？（R）

傲世九天 2025-01-26 19:40:53 浏览 4 评论 0 收藏 0

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可遇━不可求 2025-02-02 16:08:56

聚会迟到了，但这是我能够对OP的问题的答案（4月14日）。

根据 sveltekit docs 。

// add the following to > svelte.config.js
import { readFileSync } from 'fs';
import { fileURLToPath } from 'url';

const file = fileURLToPath(new URL('package.json', import.meta.url));
const json = readFileSync(file, 'utf8');
const pkg = JSON.parse(json);

也;

// add the following to kit: {}
version: {
  name: pkg.version
}

然后在您所需的组件中；

<script>
  import { version } from '$app/environment';
</script>

<span>The package.json version is: {version}</span>

如果您打算走Vite路线，则应阅读，urb_在此处提出的类似问题的答案我如何将版本号添加到Sveltekit/vite应用程序？。

但总而言之；

请注意，config在 @sveltejs/：a
@sveltejs/
包含在自己的文件中：

A little late to the party, but here's how I was able to achieve an answer to OP's question as of (14 Apr 23).

As per the sveltekit docs.

// add the following to > svelte.config.js
import { readFileSync } from 'fs';
import { fileURLToPath } from 'url';

const file = fileURLToPath(new URL('package.json', import.meta.url));
const json = readFileSync(file, 'utf8');
const pkg = JSON.parse(json);

As well as;

// add the following to kit: {}
version: {
  name: pkg.version
}

Then in your desired component;

<script>
  import { version } from '$app/environment';
</script>

<span>The package.json version is: {version}</span>

If you're planning to go the Vite route, you should read, urb_'s answer to a similar question asked here on S.O. How do I add a version number to a SvelteKit/Vite app?.

but in summary;

Be aware, config changed after @sveltejs/[email protected]: After a
breaking change on @sveltejs/[email protected], Vite config must be
included in its own file:

如何在网站的页脚中显示package.json版本？

顾挽 2025-01-26 16:08:56 浏览 2 评论 0 收藏 0

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可遇━不可求 2025-02-02 15:04:37

您可以从软件包 stringr 中使用 str_extract 来提取任何以上案例字母开头的东西（ [：upper：topper：]] ），然后是。一个或多个字符（。+），直到字符串结束（ $ ）。

library(stringr)

str_extract(df$value, "[[:upper:]].+$")

如果您不想使用Regex，则可以使用 str_split 将字符串分为两个部分。

str_split(df$value, " ", n = 2, simplify = T)[,2]

输出

以上两种方法具有相同的输出：

[1] "Blue sea" "Red ball"

You can use str_extract from the package stringr to extract anything that starts with an upper case letter ([[:upper:]]) followed by one or more characters (.+) until the end of a string ($).

library(stringr)

str_extract(df$value, "[[:upper:]].+quot;)

If you don't want to use regex, you can use str_split to split strings into two parts by an empty space.

str_split(df$value, " ", n = 2, simplify = T)[,2]

Output

The above two methods have the same output:

[1] "Blue sea" "Red ball"

在第一个大写或空间之后提取文字

尹雨沫 2025-01-26 15:04:37 浏览 6 评论 0 收藏 0

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可遇━不可求 2025-02-02 11:12:48

if ( $var1 && $var2 ) {
   # Both are true.
}
elsif ( !$var1 && !$var2 ) {
   # Both are false.
}

或

if ( !( $var1 xor $var2 ) ) {
   # Both are true or both are false.
   if ( $var1 ) {
      # Both are true.
   } else {
      # Both are false.
   }
}

或

if ( $var1 ) { 
   if ( $var2 ) {
      # Both are true.
   }
} else {
   if ( !$var2 ) {
      # Both are false.
   }
}

if ( $var1 && $var2 ) {
   # Both are true.
}
elsif ( !$var1 && !$var2 ) {
   # Both are false.
}

or

if ( !( $var1 xor $var2 ) ) {
   # Both are true or both are false.
   if ( $var1 ) {
      # Both are true.
   } else {
      # Both are false.
   }
}

or

if ( $var1 ) { 
   if ( $var2 ) {
      # Both are true.
   }
} else {
   if ( !$var2 ) {
      # Both are false.
   }
}

在Perl中测试两个布尔值和运算符

哆兒滾 2025-01-26 11:12:48 浏览 3 评论 0 收藏 0

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可遇━不可求 2025-02-02 08:38:18

我最近面对同一问题，发现图书馆有授权的错误。我将PR推送为Repo，但是您可以以相同的方式修补本地副本。

https://github.com/streaminy/streaminy/ksqldb-client/pull/pull/pull/4

使用节点npm ksqldb-client抛出超时错误执行ksql查询

池予 2025-01-26 08:38:18 浏览 6 评论 0 收藏 0

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可遇━不可求 2025-02-02 00:08:28

该错误可能与您传递的原始板一起。如果您以类似的方式开始：

board = [[0] * 1000] * 1000

然后，您对同一列表有1000个引用，而不是1000个不同的列表。您进行的任何修改都是相同的共享列表。

我会用类似的内容来初始化板的初始化

board = [[random.choice([0, 0, 1]) for _ in range(1000)] for _ in range(1000)]

，内部循环在外循环内多次执行，从而为您提供多个唯一的列表；这与列表乘法不同，其中列表的内容简单地重复了。

The error is probably with the original board that you passed in. If you started with something like:

board = [[0] * 1000] * 1000

then you have 1000 references to the same list, not 1000 different lists. Any modification you make is to the same shared list.

I'd initialize the board with something like:

board = [[random.choice([0, 0, 1]) for _ in range(1000)] for _ in range(1000)]

With a nested comprehension, the inner loop is executed multiple times inside the outer loop, giving you multiple unique lists; this is different from list multiplication, where the contents of the list are simply duplicated.

根据随机选择将值分配给列表的元素

明天过后 2025-01-26 00:08:28 浏览 1 评论 0 收藏 0

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可遇━不可求 2025-02-01 17:54:52

我认为 0.000000 是正确的。 C99 6.3.1.8p1说：

否则，如果两个操作数的相应类型是float，则将另一个操作数转换为类型域的不更改的类型，其相应的真实类型为float。

因此，在 fi 中， i 转换为 float ，产生与 f 相同的值。我不确定您的书的编译器如何获得 3.000000 。

如果您真的想查看截断错误，请执行（double）f -i 。

无法确定并打印出从int到float隐式铸造的截断误差

海螺姑娘 2025-01-25 17:54:52 浏览 3 评论 0 收藏 0

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可遇━不可求 2025-02-01 11:33:09

我看不到在NextJS文档中进行任何直接方法。但是，如果您想通过一些调整来完成它，则可以使用 > router.aspath 。您将可以根据您的尝试的路径

const Custom404 = () => {
  const router = useRouter();
  let attemptedPath = router.asPath;
  if (attemptedPath.startsWith("/folder")) {
    return <div>Custom UI</div>;
  }
  return <div>Usual UI</div>;
};

编辑来更改UI：基于您的编辑，一种方法可以在所有其他路由上添加直接检查。如果条件发生变化，例如：

const existingRoutes = ['/contact','/','/moreRoutes'];
if (!existingRoutes.includes(attemptedPath)) {
    return <div>Custom UI</div>;
  }

注意：如果您有更多嵌套路线，则必须同时使用Startswith和完整的字符串等价检查。这完全取决于您的路线。

I do not see any direct way to do it in NextJs docs. But if you are looking to get it done with a little tweaking, you can use router.asPath. You will have the option to change the UI, based on your attempted path

const Custom404 = () => {
  const router = useRouter();
  let attemptedPath = router.asPath;
  if (attemptedPath.startsWith("/folder")) {
    return <div>Custom UI</div>;
  }
  return <div>Usual UI</div>;
};

Edit: Based on your edit, one way to do this can be adding direct checks on all other routes you have. Your if conditions changes like :

const existingRoutes = ['/contact','/','/moreRoutes'];
if (!existingRoutes.includes(attemptedPath)) {
    return <div>Custom UI</div>;
  }

Note: If you have more nested routes then you will have to use both startsWith and complete string equality check. It all depends on your routes.

next.js自定义404页面的sl/动态路线

通知家属抬走 2025-01-25 11:33:09 浏览 2 评论 0 收藏 0

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可遇━不可求 2025-02-01 10:33:11

目前尚不清楚您的期望是什么，但是我想这就是您追求的

select Skill, Count(*) courseCount
from (
    select course_id, Count(distinct SKILL_ID) Skill
    from t
    group by COURSE_ID
)s
group by Skill;

db＆lt;＆gt;＆gt; fiddle

结果：

It's not entirely clear what you're expecting as a result but I think this is what you're after

select Skill, Count(*) courseCount
from (
    select course_id, Count(distinct SKILL_ID) Skill
    from t
    group by COURSE_ID
)s
group by Skill;

DB<>Fiddle

Result:

SQL从一个表中选择两个计数

又怨 2025-01-25 10:33:11 浏览 3 评论 0 收藏 0

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可遇━不可求 2025-02-01 09:50:53

对于其值一致性的列，例如$ 100B，$ 10B，$ 4B ...等等，依此类推。＃$％^＆amp;*（）”）在Google表中。

将文本转换为Google表中的编号＆amp; Excel

亚希 2025-01-25 09:50:53 浏览 5 评论 0 收藏 0

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可遇━不可求 2025-02-01 08:45:55

在第一个代码段中，您将参数定义为a noreflow noreferrer“ 并按照预期的方式工作。

@app.post('/items/v1/cards/{sku}')
async def create_item(sku: str):
    return {'sku': sku}

URL示例：

http://127.0.0.1:8000/items/v1/cards/something

在第二中，您尝试通过a 查询参数以错误的方式。根据 documentation ：

当您声明其他功能参数时，不是一部分
路径参数，它们自动被解释为“查询”
参数。

因此，您的终点应该看起来像这样：

@app.post('/items/v1/cards')
async def create_item(sku: str):
    return {'sku': sku}

查询是在URL中追随？的键值对集合，
由＆amp; 字符分开。

URL示例：

http://127.0.0.1:8000/items/v1/cards?sku=something

In the first code snippet, you defined the parameter as a Path parameter and worked as expected.

@app.post('/items/v1/cards/{sku}')
async def create_item(sku: str):
    return {'sku': sku}

URL Example:

http://127.0.0.1:8000/items/v1/cards/something

In the second one, however, you attempted to pass a Query parameter in the wrong way. As per the documentation:

When you declare other function parameters that are not part of the
path parameters, they are automatically interpreted as "query"
parameters.

Hence, your endpoint should look like this:

@app.post('/items/v1/cards')
async def create_item(sku: str):
    return {'sku': sku}

The query is the set of key-value pairs that go after the ? in a URL,
separated by & characters.

URL Example:

http://127.0.0.1:8000/items/v1/cards?sku=something

使用FastApi返回的邮政方法中的问号404错误

天暗了我发光 2025-01-25 08:45:55 浏览 5 评论 0 收藏 0

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可遇━不可求 2025-02-01 08:32:48

Your code works for me :

HTTP/1.1 200 OK
Date: Thu, 28 Apr 2022 20:20:16 GMT
Server: Apache/2.4.18 (Ubuntu)
Last-Modified: Sat, 13 May 2017 11:22:22 GMT
ETag: "a7-54f6609245537"
Accept-Ranges: bytes
Content-Length: 167
Cache-Control: max-age=0, no-cache, no-store, must-revalidate
Pragma: no-cache
Expires: Wed, 11 Jan 1984 05:00:00 GMT
Connection: close
Content-Type: text/plain

But soft what light through yonder window breaks
It is the east and Juliet is the sun
Arise fair sun and kill the envious moon
Who is already sick and pale with grief

It appears your code is accessing a different url, (presumably, http://google.com), and is getting a 302 redirect, asking your browser to try to get <代码> http://google.com/ 而不是。

Your code works for me :

HTTP/1.1 200 OK
Date: Thu, 28 Apr 2022 20:20:16 GMT
Server: Apache/2.4.18 (Ubuntu)
Last-Modified: Sat, 13 May 2017 11:22:22 GMT
ETag: "a7-54f6609245537"
Accept-Ranges: bytes
Content-Length: 167
Cache-Control: max-age=0, no-cache, no-store, must-revalidate
Pragma: no-cache
Expires: Wed, 11 Jan 1984 05:00:00 GMT
Connection: close
Content-Type: text/plain

But soft what light through yonder window breaks
It is the east and Juliet is the sun
Arise fair sun and kill the envious moon
Who is already sick and pale with grief

It appears your code is accessing a different url, (presumably, http://google.com), and is getting a 302 redirect, asking your browser to try to get http://google.com/ instead.

PY4E问题 - 探索超文本传输协议

谁的年少不轻狂 2025-01-25 08:32:48 浏览 2 评论 0 收藏 0

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可遇━不可求 2025-02-01 08:27:19

我认为您正在使用 JSONB 错误地键入。这是一个数据库列类型，它确定数据本身中的数据是如何编码的，但并非打算在应用程序数据结构和消息传递中使用。

假设您的表是这样定义的：

table! {
    test {
        id -> Integer,
        tags -> Jsonb,
    }
}

您可以将行转换为这样的结构：

#[derive(Queryable, Debug, Serialize, Deserialize)]
pub struct Test {
    pub id: i64,
    pub tags: serde_json::Value,
}

I think you are using the Jsonb type incorrectly. It's a database column type which determines how the data is encoded in the database itself but is not intended to be used direclty in your application data structures and messaging.

Assuming your table is defined like this:

table! {
    test {
        id -> Integer,
        tags -> Jsonb,
    }
}

You can convert rows into a struct like this:

#[derive(Queryable, Debug, Serialize, Deserialize)]
pub struct Test {
    pub id: i64,
    pub tags: serde_json::Value,
}

``serialize''特征不是为`jsonb'实现的

冷了相思 2025-01-25 08:27:19 浏览 2 评论 0 收藏 0

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可遇━不可求 2025-02-01 01:51:57

将您的CSS编辑为这样的东西。

.card > p{
     color: #0c5460;
}

.card > span {
     color: #0c5460;
}

.row > p { 
    color: #0c5460;
 }

 <div class="container">
    <div class="card">
      <p>Account: 2002384</p>
        <span>Account: 2002384</span>
      </div>
      <div class="card-body">
        <div class="row my-auto">
        <p>Balance: $44,930.20</p>
      </div>
      </div>
    </div>

Edit your css to something like this.

.card > p{
     color: #0c5460;
}

.card > span {
     color: #0c5460;
}

.row > p { 
    color: #0c5460;
 }

 <div class="container">
    <div class="card">
      <p>Account: 2002384</p>
        <span>Account: 2002384</span>
      </div>
      <div class="card-body">
        <div class="row my-auto">
        <p>Balance: $44,930.20</p>
      </div>
      </div>
    </div>

如何更改d部门内文本颜色的p标签？

夢归不見 2025-01-25 01:51:57 浏览 1 评论 0 收藏 0

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可遇━不可求 2025-01-31 18:15:23

我找到了解决方案，该解决方案是通过运行：

pip install selenium==3.141.0

source

I found the solution, which is to revert Selenium to 3.141.0 by running:

pip install selenium==3.141.0

Source

find_element给出＆＃x27; dict＆＃x27;对象没有属性＆＃x27; click＆＃x27;使用WinAppDriver测试Windows桌面应用程序时出错

病毒体 2025-01-24 18:15:23 浏览 6 评论 0 收藏 0

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