糖粟与秋泊

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糖粟与秋泊 2025-01-30 21:32:23

让我们尝试:

s = np.sign(df.set_index('ski').stack())
s.groupby([pd.Grouper(level=0), s.diff().ne(0).cumsum()]).sum().groupby(level=0).agg(list)

ski
book    [3.0, -2.0, 1.0]
jar     [1.0, -2.0, 3.0]
kook         [-5.0, 1.0]
dtype: object

Let us try:

s = np.sign(df.set_index('ski').stack())
s.groupby([pd.Grouper(level=0), s.diff().ne(0).cumsum()]).sum().groupby(level=0).agg(list)

ski
book    [3.0, -2.0, 1.0]
jar     [1.0, -2.0, 3.0]
kook         [-5.0, 1.0]
dtype: object

我如何计算标志列?

糖粟与秋泊 2025-01-30 19:40:05

解决此问题的唯一方法是删除带有与离子卡符号相同特征的DIV标签的离子卡符号标签。这是一种更好的解决方案,因为现在您可以自定义您的离子卡包含。

我尝试相同的方式,对我有用。请记住,离子文档中的离子卡 - 包含没有CSS信息:

The only way to fix this problem is to remove the ion-card-content tag and replace with a div tag with the same characteristics as the ion-card-content. This is a way better solution because now you can customize your ion-card-content.

I try the same way and it works for me. Remember that ion-card-content has no CSS information in the ionic documentation: https://ionicframework.com/docs/api/card-content#css-custom-properties

我如何修改< p>的字体尺寸在离子6中的离子卡内部标记6

糖粟与秋泊 2025-01-30 16:44:15

由于您是从左到右扫描,因此您可以在找到第一个匹配IE之后返回,替换

           if (numbers[i] + numbers[j] != k){
               pairs = new int[]{0, 0};
           }

返回对

Since you are scanning left to right, you can just return after finding the first match i.e., replacing

           if (numbers[i] + numbers[j] != k){
               pairs = new int[]{0, 0};
           }

with return pairs.

鉴于INT数组中的两个元素的总和,如何找到其最小的索引?

糖粟与秋泊 2025-01-30 14:48:40

我一直在道具(“选定”)的问题上,以下内容一直对我有用:

//first remove the current value
$("#selectBox").children().removeAttr("selected");
$("#selectBox").children().eq(index).attr('selected', 'selected');

I've always had issues with prop('selected'), the following has always worked for me:

//first remove the current value
$("#selectBox").children().removeAttr("selected");
$("#selectBox").children().eq(index).attr('selected', 'selected');

jQuery集选择索引

糖粟与秋泊 2025-01-30 12:03:02

要修复Access-Control-Allow-Origin,您必须从 .htaccess 进行操作。这是要添加到该文件的代码以及参考文章,该代码更深入地解释了错误。

https://crunchify.com/how-to-fix-access-control-allow-oryigin-origin-sissue-for-your-https-enabled-wordpress-wordpress-site-site-site-and-maxcdn/

<IfModule mod_headers.c>
  <FilesMatch "\.(ttf|ttc|otf|eot|woff|woff2|font.css|css|js)$">
    Header set Access-Control-Allow-Origin "*"
  </FilesMatch>
</IfModule>

To fix Access-Control-Allow-Origin, you have to do it from .htaccess. Here is the code to add to that file as well as the reference article, which explains the error in more depth.

https://crunchify.com/how-to-fix-access-control-allow-origin-issue-for-your-https-enabled-wordpress-site-and-maxcdn/

<IfModule mod_headers.c>
  <FilesMatch "\.(ttf|ttc|otf|eot|woff|woff2|font.css|css|js)
quot;>
    Header set Access-Control-Allow-Origin "*"
  </FilesMatch>
</IfModule>

WordPress中的访问控制 - 允许原素

糖粟与秋泊 2025-01-29 21:12:31

我不熟悉cvxpy lib,但我相信您正在尝试将列表写入Excel文档。我认为这是不支持的。

此代码产生类似的错误

import openpyxl
val = [50.20042375]
wb = openpyxl.Workbook()
sheet = wb.active
sheet.cell(row=1, column=1).value = val

来解决该问题,最终会添加[0]

import openpyxl
val = [50.20042375]
wb = openpyxl.Workbook()
sheet = wb.active
sheet.cell(row=1, column=1).value = val[0]

Im not familiar with the cvxpy lib but i belive you are trying to write a list to the excel document. I don't think that is supported.

This code produce a similar error

import openpyxl
val = [50.20042375]
wb = openpyxl.Workbook()
sheet = wb.active
sheet.cell(row=1, column=1).value = val

To fix the issue do add a [0] in the end like this

import openpyxl
val = [50.20042375]
wb = openpyxl.Workbook()
sheet = wb.active
sheet.cell(row=1, column=1).value = val[0]

如何将阵列转换为python的Excel?

糖粟与秋泊 2025-01-29 15:29:05

在您希望隐藏的条件下,您可以在该条件下添加它。

  menu.visibility = View.INVISIBLE

或者

   menu.visibility = View.GONE

Under what condition you want it to be hidden, you can add it under that condition.

  menu.visibility = View.INVISIBLE

or

   menu.visibility = View.GONE

如何在某些情况下将Menuitem隐藏在工具栏中?

糖粟与秋泊 2025-01-28 19:38:11

您可以将您的两个chars 参考&amp; 替代到字符串,并使用Regex检查 transition Transversion 。类似

import java.util.function.BiFunction;

....


public static Map<String, List<Snp>> getTransversionsTransitions() {
    BiFunction<Character,Character,String> func =
            (a,b) -> (""+a+b).matches("AG|GA|CT|TC") ? "Transitions":"Transversions";
    return SNP_COLLECTION.stream()
            .collect(Collectors.groupingBy(snp -> func.apply(snp.getReference(),snp.getAlternative())));
}

You could concat your two chars reference & alternative to a string and use regex to check for transition or transversion. Something like

import java.util.function.BiFunction;

....


public static Map<String, List<Snp>> getTransversionsTransitions() {
    BiFunction<Character,Character,String> func =
            (a,b) -> (""+a+b).matches("AG|GA|CT|TC") ? "Transitions":"Transversions";
    return SNP_COLLECTION.stream()
            .collect(Collectors.groupingBy(snp -> func.apply(snp.getReference(),snp.getAlternative())));
}

两个不同的过滤器后,Java流制作地图

糖粟与秋泊 2025-01-28 18:00:25

UGGH。是的,访问此类JSON数据结构很糟糕,
有点尴尬。

glom 进行救援!

有两种获胜的方法:

  1. 您可以只指定 ...,默认= none)避免异常,..

  2. 例外/PI.html#defaults-with-coalesce“ rel =“ nofollow noreferrer”> cocecce

      print(glom(data,{'object_1.object_2.list':['属性']},默认值= none))
     

Uggh. Yeah, accessing such JSON data structures is just terrible,
it's a bit awkward.

Glom to the rescue!

There's two ways to win:

  1. You can just specify ... , default=None) to avoid exceptions, ..or..

  2. Use Coalesce.

     print(glom(data, {'object_1.object_2.list': ['property']}, default=None))
    

Python:列表的安全词典访问?

糖粟与秋泊 2025-01-28 06:11:40

我已经使用逻辑来实现这一目标,

您可以在 app.component.ts 中使用逻辑

import { Router, NavigationEnd } from '@angular/router';
    
export class AppComponent implements OnInit {
      constructor(
        private router: Router,
      ) {
        this.router.events.subscribe((ev) => {
          if (ev instanceof NavigationEnd) {
    
            const user = localStorage.getItem("Id");
            const Role = localStorage.getItem('UserRole')
            if (user && Role && Role === 'User' && ev.url.includes('/admin)) {
                this.router.navigate(['user/home']);
          }
        }
      }

类似地,对于您的所有角色,您都可以定义条件,并且可以
在其主要路由上重定向,如果用户则是用户的默认页面,
如果超级管理员,则可能是管理员/仪表板
这个。


第二种方法:

另一种实现这一目标的方法是使用 ngx-permissions < /a>使用可以根据角色控制路线的使用。

附加 stackblitz 演示以获取更多澄清。

官方doc

npm软件包

I have achieved this by using logic,

You can use logic like in your app.component.ts

import { Router, NavigationEnd } from '@angular/router';
    
export class AppComponent implements OnInit {
      constructor(
        private router: Router,
      ) {
        this.router.events.subscribe((ev) => {
          if (ev instanceof NavigationEnd) {
    
            const user = localStorage.getItem("Id");
            const Role = localStorage.getItem('UserRole')
            if (user && Role && Role === 'User' && ev.url.includes('/admin)) {
                this.router.navigate(['user/home']);
          }
        }
      }

Similarly for your all roles you can define if condition and can
redirect on their main route lets if user then user's default page,
if super admin then it might be admin/dashboard anything like
this.

Second way:

Another way to achieve this is to use ngx-permissions using which you can control your route based on role.

attaching stackblitz demo for more clarification.

Official doc

NPM Package

如何限制用户访问Angular中未经授权的路径

糖粟与秋泊 2025-01-27 22:36:35

TypeScript 3.9+ 更新(2020 年 5 月 12 日)

现在,TypeScript 还支持命名元组。这极大地提高了代码的可理解性可维护性查看官方 TS 游乐场。


所以,现在而不是unnamed:

const a: [number, string] = [ 1, "message" ];

我们可以添加名称:

const b: [id: number, message: string] = [ 1, "message" ];

注意:您需要一次添加所有名称,不能省略某些名称,例如:

type tIncorrect = [id: number, string]; // INCORRECT, 2nd element has no name, compile-time error.
type tCorrect = [id: number, msg: string]; // CORRECT, all have a names.

提示:如果您不确定的数量最后一个元素,你可以这样写:

type t = [msg: string, ...indexes: number];// means first element is a message and there are unknown number of indexes.

TypeScript 4.x+ Variadic Tuple Types

对于 TS 4.x,最后一个示例必须更改为这个:

type t = [msg: string, ...indexes: number[]];// means first element is a message and there are unknown number of indexes.

类型 number 更改为 number[]

更多信息在这里: https:// /www.typescriptlang.org/docs/handbook/release-notes/typescript-4-0.html#variadic-tuple-types

TypeScript 3.9+ update (May 12, 2020)

Now, TypeScript also supports named tuples. This greatly increases the understandability and maintainability of the code. Check the official TS playground.


So, now instead of unnamed:

const a: [number, string] = [ 1, "message" ];

We can add names:

const b: [id: number, message: string] = [ 1, "message" ];

Note: you need to add all names at once, you can not omit some names, e.g:

type tIncorrect = [id: number, string]; // INCORRECT, 2nd element has no name, compile-time error.
type tCorrect = [id: number, msg: string]; // CORRECT, all have a names.

Tip: if you are not sure in the count of the last elements, you can write it like this:

type t = [msg: string, ...indexes: number];// means first element is a message and there are unknown number of indexes.

TypeScript 4.x+ Variadic Tuple Types

The last example has to be changed to this one for TS 4.x:

type t = [msg: string, ...indexes: number[]];// means first element is a message and there are unknown number of indexes.

The type number is changed to number[].

More info here: https://www.typescriptlang.org/docs/handbook/release-notes/typescript-4-0.html#variadic-tuple-types

定义具有多种类型的数组

糖粟与秋泊 2025-01-27 18:46:15

请检查此循环以检索CPTS。

$args = array(
 'post_type' => arra('apps-und-tools'),
'tax_query' => array(
    array(
        'taxonomy' => $term_taxonomy,
        'field'    => 'slug',
        'terms'    => $term_slug,
    ),
 ),
);
$query = new WP_Query( $args );

Please check this loop to retrieve CPTs.

$args = array(
 'post_type' => arra('apps-und-tools'),
'tax_query' => array(
    array(
        'taxonomy' => $term_taxonomy,
        'field'    => 'slug',
        'terms'    => $term_slug,
    ),
 ),
);
$query = new WP_Query( $args );

自定义帖子类型通过自己的分类法进行过滤

糖粟与秋泊 2025-01-27 18:05:36

您传递的值不是来自originalData,因此onUpdated不知道它是什么value

您使用map在originalData上运行,因此您需要传递item。 onUpdate 函数

const dataWithComponent = originalData.map((item, i) => ({
    ...item,
    entregado: <SelectorComponent
      value={deliver?.items[i].delivered} // you can't use items use deliver.length > 0 ? [i].delivered : ""
      key={i}
      onUpdate={() => handleUpdate("here you pass item", i)}
    />
    }));

The value that you pass don't come from originalData, so the onUpdated don't know what it's value

You run on originalData using map, so you need to pass item.somthing the the onUpdate function

const dataWithComponent = originalData.map((item, i) => ({
    ...item,
    entregado: <SelectorComponent
      value={deliver?.items[i].delivered} // you can't use items use deliver.length > 0 ? [i].delivered : ""
      key={i}
      onUpdate={() => handleUpdate("here you pass item", i)}
    />
    }));

ReactJS,使用处理程序更新状态但数据为空

糖粟与秋泊 2025-01-27 17:11:12

此问题可能会发生,因为网站没有启用目录浏览功能。要解决此问题,您可以尝试使用以下方法:

  1. start IIS Manager。为此,选择“启动”,选择“运行”,“键入inetmgr.exe”,然后选择“确定”。
  2. 在IIS Manager中,扩展服务器名称,扩展网站,然后选择要更改的网站。
  3. 在功能视图中,双击目录浏览。
  4. 在动作窗格中,选择启用。

This problem may occurs because the website doesn't have the Directory Browsing feature enabled. To resolve this problem,you can try use the following methods:

  1. Start IIS Manager. To do it, select Start, select Run, type inetmgr.exe, and then select OK.
  2. In IIS Manager, expand server name, expand Web sites, and then select the website that you want to change.
  3. In the Features view, double-click Directory Browsing.
  4. In the Actions pane, select Enable.

这些文件没有在IIS服务器中的MVC框架中加载

糖粟与秋泊 2025-01-27 12:26:19

错误消息“所有范围键的聚合大小已超过 1024 的大小限制”令人费解,因为只能有一个排序键,那么“聚合”指的是什么?以下帖子也对此消息感到惊讶: https://www.stuffofminsun .com/2019/05/07/dynamodb-keys/

我猜你实际上确实尝试编写一个项目,其中“p”(你说的是你的排序键)本身超过 1024 个字符。我不明白 p+r 组合的大小有什么影响。您可以查看(和/或包含在问题中)失败的一个特定请求,并检查 p 本身的长度是多少。另请仔细检查您是否确实将“p”而不是其他内容设置为排序键。

最后,如果您确实需要长度超过 1024 个字符的排序键,您可以考虑 Scylla Alternator - 一个与 DynamoDB 兼容的开源数据库,它没有此特定限制。

The error message "Aggregated size of all range keys has exceeded the size limit of 1024" is baffling because there can only be one sort key, so what does "aggregate" refer to? The following post was also surprised by this message: https://www.stuffofminsun.com/2019/05/07/dynamodb-keys/.

I am guessing you actually do try to write an item where its "p" (which you said is your sort key) itself is over 1024 characters. I don't see how it's the size of p+r combined that matters. You can take a look (and/or include in the question) at the one specific request that fails, and check what is the length of p itself. Please also double-check that you really set "p", and not something else, as the sort key.

Finally, if you really need sort keys over 1024 characters in length, you can consider Scylla Alternator - an open-source DynamoDB-compatible database which doesn't have this specific limitation.

DynamoDB 范围键超出大小限制

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