man kaio:没有手动输入 kaio
我捆了一个过程,它们是如下的线。而且我想知道kaio的定义,但是kaio没有手动输入,请问能否得到定义?
/1: kaio(AIOWRITE, 259, 0x3805B2A00, 8704, 0x099C9E000755D3C0) = 0 /1: kaio(AIOWRITE, 259, 0x380CF9200, 14336, 0x099CC0000755D5B8) = 0 /1: kaio(AIOWRITE, 259, 0x381573600, 8704, 0x099CF8000755D7B0) = 0 /1: kaio(AIOWRITE, 259, 0x381ACA600, 8192, 0x099D1A000755D9A8) = 0 /1: kaio(AIOWAIT, 0xFFFFFFFF7FFFD620) = 4418032576 /1: timeout: 600.000000 sec /1: kaio(AIOWAIT, 0xFFFFFFFF7FFFD620) = 4418033080 /1: timeout: 600.000000 sec /1: kaio(AIOWAIT, 0xFFFFFFFF7FFFD620) = 4418033584 /1: timeout: 600.000000 sec
I trussed a process, and they are lines as below. And I want to know the definition of kaio, but there is no manual entry for kaio, so whether can I get the definition?
/1: kaio(AIOWRITE, 259, 0x3805B2A00, 8704, 0x099C9E000755D3C0) = 0 /1: kaio(AIOWRITE, 259, 0x380CF9200, 14336, 0x099CC0000755D5B8) = 0 /1: kaio(AIOWRITE, 259, 0x381573600, 8704, 0x099CF8000755D7B0) = 0 /1: kaio(AIOWRITE, 259, 0x381ACA600, 8192, 0x099D1A000755D9A8) = 0 /1: kaio(AIOWAIT, 0xFFFFFFFF7FFFD620) = 4418032576 /1: timeout: 600.000000 sec /1: kaio(AIOWAIT, 0xFFFFFFFF7FFFD620) = 4418033080 /1: timeout: 600.000000 sec /1: kaio(AIOWAIT, 0xFFFFFFFF7FFFD620) = 4418033584 /1: timeout: 600.000000 sec
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来自一篇关于它的文章:
From an article about it:
我得到答案:
它是在文件 /usr/include/sys/syscall.h 中定义的
I get the answer:
it's defined in file /usr/include/sys/syscall.h