警告和 SunStudio C++ 编译器

发布于 2024-07-12 09:56:18 字数 358 浏览 7 评论 0原文

我说服我的团队再次打开编译器警告。一些如何禁用所有警告（-w）的信息（不要问...）。其中大多数都是显而易见的，但其中之一确实很烦人。我从我的日期和时间课程中得到它，这些课程在很多地方都使用。故事其实很简单。 Time 是 Date 的子类，它们都定义了自己的运算符。这有什么问题吗？这是我收到的警告：

Warning: ACTime::operator- hides the function ACDate::operator-(const ACDate&) const.

也许有人可以给我链接描述每个 SunStudio C++ 编译器警告含义的文档？我找不到这个...谢谢！

原文

I talked my team into turning on compiler warnings again. Some how all warnings (-w) were disabled (don't ask...). Most of them are obvious but one of them is really annoying. I get it from my date and time classes which are used in lots of places. Story is really simple. Time is subclass of Date and both of them have their operators defined. What can be wrong with that? Here's the warning I get:

Warning: ACTime::operator- hides the function ACDate::operator-(const ACDate&) const.

Perhaps somebody can link me the docs describing what each of SunStudio C++ compiler warnings mean? I can't find this... Thanks!

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漆黑的白昼 2024-07-19 09:56:18

我以前在 SunStudio 编译器中见过这个。基本上，您有这样的构造：

class ACDate
{
   public:
     ACDate &operator-(const ACDate &);
};

class ACTime : public ACDate
{
    public:
    ACTime &operator-(const ACTime &);
};

由于 C++ 作用域规则，ACTime::operator- 在 ACTime 对象的上下文中隐藏了 ACDate::operator-。这是很正常的，但 SunStudio 编译器会警告此问题，因为它可能是缺少“虚拟”限定符的迹象。

这种情况的一种解决方法是在 ACTime 的类声明中显式“使用 ACDate::operator-”，但这可能不是您想要的。

对于您的情况，另一种可能更好的解决方法是使操作员成为免费的朋友功能，但这可能会导致其他有趣的问题。

I've seen this before with the SunStudio compiler. Basically, you have a construct like this:

class ACDate
{
   public:
     ACDate &operator-(const ACDate &);
};

class ACTime : public ACDate
{
    public:
    ACTime &operator-(const ACTime &);
};

Due to the C++ scoping rules, ACTime::operator- hides ACDate::operator- in the context of an ACTime object. This is pretty normal but the SunStudio compiler warns about this problem as it might be a sign of a missing 'virtual' qualifier.

One workaround for this situation would be an explicit 'using ACDate::operator-' in ACTime's class declaration, but that might not be what you want.

Another, potentially better workaround for your situation is to make the operator- a free friend function, but that might lead to other interesting problems.

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