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还在原地等你 2025-02-15 20:31:57
text = "today is a sunny day dont you think? I like this day very much"
keyword_list = ['like', 'day']

splitted_text = text.split()
for index, word in enumerate(splitted_text):
    if word in keyword_list:
        print(f'{word}: {splitted_text[index+1]}')

输出:

day: dont
like: this
day: very
text = "today is a sunny day dont you think? I like this day very much"
keyword_list = ['like', 'day']

splitted_text = text.split()
for index, word in enumerate(splitted_text):
    if word in keyword_list:
        print(f'{word}: {splitted_text[index+1]}')

Output:

day: dont
like: this
day: very

在第一个发现时搜索字符串停止中的关键字

还在原地等你 2025-02-15 17:17:51

我现在唯一想做的就是能够在
连接器。假设连接器上添加“ SSL”,并在可能的情况下进行更改
将连接器颜色为红色。

Raph,尝试将这些行添加到您的代码中

vsoConnectorShape.Text = "SSL" ' add text to connector
vsoConnectorShape.CellsSRC(visSectionObject, visRowLine, visLineColor).FormulaU = 2 ' make connector red
vsoConnectorShape.CellsSRC(visSectionObject, visRowLine, visLineEndArrow).FormulaU = "1" ' add arrow to end

The only thing I want to do now is to be able to add a text on the
connector. Let's say add "SSL" on the connector and if possible change
to color of the connector to red.

Raph, try add these lines to your code

vsoConnectorShape.Text = "SSL" ' add text to connector
vsoConnectorShape.CellsSRC(visSectionObject, visRowLine, visLineColor).FormulaU = 2 ' make connector red
vsoConnectorShape.CellsSRC(visSectionObject, visRowLine, visLineEndArrow).FormulaU = "1" ' add arrow to end

VESIO中的动态连接器的VBA

还在原地等你 2025-02-15 11:54:31

使用

Listoftuples=[(#elements)]
l=[]
for e in Listoftuples[0]:
    l=l+[e]
print(l)

结果

[#elements]

Use

Listoftuples=[(#elements)]
l=[]
for e in Listoftuples[0]:
    l=l+[e]
print(l)

Result

[#elements]

python提取元素的元素清单

还在原地等你 2025-02-15 11:36:51

尝试以下操作:innerRef = {ref => {scrollref.current = ref; }}。我假设有一个const scrollRef = useref()在代码的该部分之上。然后,要实际滚动,您可以在从功能组件中返回之前使用以下片段。

const scrollToInput = useCallback((reactNode) => {
  scrollRef.current.props.scrollToFocusedInput(reactNode)
})

确保也将onfocus Prop更改为此。

onFocus={e => scrollToInput(ReactNative.findNodeHandle(e.target))}

Try this: innerRef={ref => { scrollRef.current = ref; }}. I'm assuming that there's a const scrollRef = useRef() somewhere above that part of the code. Then to actually scroll you can use the following snippet before returning from your functional component.

const scrollToInput = useCallback((reactNode) => {
  scrollRef.current.props.scrollToFocusedInput(reactNode)
})

Make sure to change the onFocus prop to this too.

onFocus={e => scrollToInput(ReactNative.findNodeHandle(e.target))}

React Native:Undefined不是对象(评估' _this.scroll = ref ref')

还在原地等你 2025-02-15 08:56:37

您无法使用另一列的默认值创建表

对默认列值的限制默认列值受到以下限制:

默认表达式不能包含对PL/SQL函数的引用或其他列,PseudoColumns级别,先验和Rownum或尚未完全指定的日期常数。

表达式除标量子查询表达式外,可以是任何形式。

oracle

文档插入。但这是另一个问题。堆栈溢出的规则是在一篇文章中不问多个问题。

You can not create table with a default value of another column

Restrictions on Default Column Values Default column values are subject to the following restrictions:

A DEFAULT expression cannot contain references to PL/SQL functions or to other columns, the pseudocolumns LEVEL, PRIOR, and ROWNUM, or date constants that are not fully specified.

The expression can be of any form except a scalar subquery expression.

ORACLE documentation

You can create a trigger for the INSERT. But that is another question. And Stack Overflow has a rule of not asking multiple questions in one post.

在Oracle SQL中,如何使用一个规则创建一个值以默认为一个值,以默认为插入时同一行中另一个值的百分比?

还在原地等你 2025-02-14 21:34:43

您可以只使用Pandas矢量化的字符串方法:

df.<your_column_name> = df.<your_column_name>.str.rjust(5)

You can just use a pandas vectorised string methods:

df.<your_column_name> = df.<your_column_name>.str.rjust(5)

lambda功能带有循环和条件

还在原地等你 2025-02-14 19:37:30

简短版本

旧版datetime类型存储日期为64位浮点偏移,从1900-01-01

floatValue=struct.unpack('<d',bytes)[0]
OLE_TIME_ZERO = datetime.datetime(1900, 01, 01, 0, 0, 0)
date=OLE_TIME_ZERO + datetime.timedelta(days=floatValue)

较新的类型不使用该格式。

Excel处理库,例如OpenPyXl提供函数,可转换OA/串行日期,例如 openpyxl.utils.datetime.from_excel.from_excel

长解释

premacy dateTime dateTime 在SQL Server使用中存储格式在Excel,Visual Basic和所有桌面应用程序中也用于1990年代末和2000年代初支持OLE/COM自动化的所有桌面应用程序。这是一个64位浮点数(称为excel中的串行日期)整体部分是自1899-12-30以来的偏移,而分数部分是一天中的时间。除非是1899-12-31或1900-01-01。

回到Excel发行时,Lotus 1-2-3是最受欢迎的电子表格和Defatso标准,并且错误地认为1900年是LEAP年。为了确保兼容性,Excel采用了相同的错误。采用的VBA试图修复错误确保公式与Excel和Lotus产生相同的结果,因此请使用1899-12-30作为基础。

SQL Server团队不在乎该错误,而是使用逻辑1900-01-01。

本质上,此值是timedelta。在Python中,您可以通过将其作为days参数传递到timeDELTA,然后将其添加到基础1900-01-01:

OLE_TIME_ZERO = datetime.datetime(1900, 01, 01, 0, 0, 0)
date=OLE_TIME_ZERO + datetime.timedelta(days=floatValue)

要获取一个:获得一个从一个字节数组中的64位浮动您可以使用 with 适当的格式a>。 64位浮点实际上是双重:

floatValue=struct.unpack('<d',bytes)[0]

警告

datetime是一种旧类型。 2005年推出的类型,datetimedateTime2dateTimeOffset具有不同的存储格式。 dateTime2dateTimeOffset具有可变精度和变量大小。

Short Version

The legacy datetime type stores dates as a 64-bit floating point offset from 1900-01-01

floatValue=struct.unpack('<d',bytes)[0]
OLE_TIME_ZERO = datetime.datetime(1900, 01, 01, 0, 0, 0)
date=OLE_TIME_ZERO + datetime.timedelta(days=floatValue)

Newer types don't use that format though.

Excel handling libraries like openpyxl offer functions that convert OA/Serial dates like openpyxl.utils.datetime.from_excel

Long Explanation

The legacy datetime type in SQL Server uses the OLE Automation Date storage format that was also used in Excel, Visual Basic and all desktop applications that supported OLE/COM Automation in the late 1990s and early 2000s, before macro viruses. This is a 64-bit floating point number (called a Serial date in Excel) whose integral part is an offset since 1899-12-30 and fractional part is the time of day. Except when it's 1899-12-31 or 1900-01-01.

Back when Excel was released, Lotus 1-2-3 was the most popular spreadsheet and a defacto standard, and incorrectly considered 1900 a leap year. To ensure compatibility, Excel adopted the same bug. VBA adopted tried to both fix the bug and ensure formulas produced the same results as Excel and Lotus, so use 1899-12-30 as a base.

The SQL Server team didn't care about the bug and used the logical 1900-01-01 instead.

Essentially, this value is a timedelta. In Python, you can convert this float to a timedelta by passing it as the days parameter to timedelta, and add it to the base 1900-01-01:

OLE_TIME_ZERO = datetime.datetime(1900, 01, 01, 0, 0, 0)
date=OLE_TIME_ZERO + datetime.timedelta(days=floatValue)

To get a 64-bit float from an array of bytes you can use struct.unpack with the appropriate format string. A 64-bit float is actually a double:

floatValue=struct.unpack('<d',bytes)[0]

WARNING

datetime is a legacy type. The types introduced in 2005, date, time, datetime2 and datetimeoffset have a different storage format. datetime2 and datetimeoffset have variable precision and variable size.

如何使用Python将二进制数据从SQLServer转换为人类可读日期和时间

还在原地等你 2025-02-14 11:38:12

要检查您的缓慢加载是由于托管性能还是Prestashop本身,请尝试切换回默认的Prestashop主题。

如果我没记错的话,您的主题是“ Pro Business-多功能Prestashop主题”
如果问题确实是您的主题,那么您的主题尚未适应Prestashop 1.7.8.5与主题建设者联系。

To check if your slow loading is due to hosting performance or your Prestashop itself, try to switch back to the default Prestashop theme.

If i'm not mistaken your theme is 'Pro Business - Multipurpose Prestashop Theme '
Your theme has not adapted to Prestashop 1.7.8.5 contact the theme builder, if the issue is indeed your theme.

类别页面的缓慢加载和所讨论的同一页面上的产品的编号

还在原地等你 2025-02-14 08:30:28

尝试删除以下空间之间的空间:悬停和:不。这样的事情:

.menubaroptions tr.menubaroption:hover:not(.disabled) td {
   opacity:1;
   text-shadow:0 0 5px #fff,0 0 10px #fff,0 0 20px #fff,0 0 40px #0ff,0 0 80px #0ff;
}

Try removing the space between the :hover and :not. So something like this:

.menubaroptions tr.menubaroption:hover:not(.disabled) td {
   opacity:1;
   text-shadow:0 0 5px #fff,0 0 10px #fff,0 0 20px #fff,0 0 40px #0ff,0 0 80px #0ff;
}

如何结合CSS:悬停:不

还在原地等你 2025-02-13 20:13:41

如果我们看不到tranzicija类的标头和源文件的相关部分,很难为您提供帮助。例如,很高兴知道MousePressEvent是否被称为公共,受保护,信号等。

It would be really hard to help you if we don't see the relevant parts of the header and source files of your tranzicija class. For example it would be great to know whether the mousePressEvent was declared as public, protected, signal etc.

QT-鼠标库不起作用的问题

还在原地等你 2025-02-13 19:06:52

由于您在Next.js的链接标签中添加功能组件,因此可以进行一些更改。这是文档

如果链接的孩子是功能组件,除了使用passhref,您还必须将组件包装在react.forwardref.forwardref中。

这意味着,首先,您应该在使用Headericon时将passhref prop prop prop prop ,

<Link href="/" passHref>
   <HeaderIcon
      inactiveIcon={<AiOutlineHome />}
      activeIcon={<AiFillHome />}  
    />
</Link>

然后将headericon更改为以下代码。请注意,我正在使用userOuter从Next.js使用来处理活动状态和不活动状态。

import { useRouter } from "next/router";
const HeaderIcon = ({ onClick, href, inactiveIcon, activeIcon }, ref) => {
  const router = useRouter();
  return (
    <a href={href} onClick={onClick} ref={ref}>
      <div>{router.pathname ? activeIcon : inactiveIcon}</div>
    </a>
  );
};
export default React.forwardRef(HeaderIcon);

Since you are adding a Functional Component inside Next.js's Link tag, there are some changes to be made. Here is an overview of what the say in the documentation:

If the child of Link is a functional component, in addition to using passHref, you must wrap the component in React.forwardRef.

Which means, first you should add passHref prop to Link when using HeaderIcon, this way:

<Link href="/" passHref>
   <HeaderIcon
      inactiveIcon={<AiOutlineHome />}
      activeIcon={<AiFillHome />}  
    />
</Link>

Then change HeaderIcon to the following code. Notice I'm using useRouter from Next.js to handle active and inactive state.

import { useRouter } from "next/router";
const HeaderIcon = ({ onClick, href, inactiveIcon, activeIcon }, ref) => {
  const router = useRouter();
  return (
    <a href={href} onClick={onClick} ref={ref}>
      <div>{router.pathname ? activeIcon : inactiveIcon}</div>
    </a>
  );
};
export default React.forwardRef(HeaderIcon);

&#x201D;警告:无法给出功能组件参考。&#x201c;在NextJ中使用自定义组件时出错

还在原地等你 2025-02-13 17:28:11

您是否将某种记录器添加为依赖性?

<dependency>
    <groupId>org.apache.logging.log4j</groupId>
    <artifactId>log4j-api</artifactId>
    <version>2.6.1</version>
</dependency>
<dependency>
    <groupId>org.apache.logging.log4j</groupId>
    <artifactId>log4j-core</artifactId>
    <version>2.6.1</version>
</dependency>

还是您可以向我们展示您的记录依赖性?

另外,还有一些可供伐木的教程:

Do you have some kind of a logger added as a dependency?

<dependency>
    <groupId>org.apache.logging.log4j</groupId>
    <artifactId>log4j-api</artifactId>
    <version>2.6.1</version>
</dependency>
<dependency>
    <groupId>org.apache.logging.log4j</groupId>
    <artifactId>log4j-core</artifactId>
    <version>2.6.1</version>
</dependency>

Or can you show us your logger dependencies?

Also there are good tutorials for logging:

使用Logger时会出现错误 - &quot'考虑定义类型'org.slf4j.logger&#x27;在您的配置中。

还在原地等你 2025-02-13 17:10:34

您应该始终查看

”代码> parsephoneNumber 返回…phonenumber类的实例,或者如果无法解释电话号码,则不确定……。而且您不能指望json.stringify(phonenumber)将导致仅包含电话号码的东西。

ispossiblephoneNumber 期望符号作为参数的字符串,该字符串是一个有效的手机编号;文档指出:

此功能只是“严格”解析电话号码然后调用.ispossible()的两步过程的快捷方式。

因此,您要做的是:

const contact_asset = "2022032034"
const phoneNumber = libphonenumber.parsePhoneNumber(contact_asset, 'US')

if (phoneNumber) {
  console.log(phoneNumber.isPossible());
}

const contact_asset = "2022032034"
console.log(libphonenumber.isPossiblePhoneNumber(contact_asset, 'US'));

You should always take a look at the documention

parsePhoneNumber returns …an instance of PhoneNumber class, or undefined if no phone number could be parsed…. And you can't expect that JSON.stringify(phoneNumber) will result in something that just contains a phone number.

And isPossiblePhoneNumber expects a string as parameter that is a valid phone number; the documentation states there:

This function is just a shortcut for a two-step process of "strictly" parsing a phone number and then calling .isPossible().

So what you want to do is either:

const contact_asset = "2022032034"
const phoneNumber = libphonenumber.parsePhoneNumber(contact_asset, 'US')

if (phoneNumber) {
  console.log(phoneNumber.isPossible());
}

Or

const contact_asset = "2022032034"
console.log(libphonenumber.isPossiblePhoneNumber(contact_asset, 'US'));

LibphoneNumber-JS评估良好的电话号码为false

还在原地等你 2025-02-13 07:10:06

R2表示在回归方程创建的行中的数据点的比例。较高的R2值是可取的,因为它表明结果更好。

您需要将最小值标准化为0,最大值为1,因为R2是线路的一部分。负数是不可能的。

由于最小值为零,因此您不能在分母中使用它,因此您必须这样设置它

,因此请使用1- [0/r1]

有一个用于修复此错误


from sklearn.metrics import r2_score

R2 indicates the proportion of data points which lie within the line created by the regression equation. A higher value of R2 is desirable as it indicates better results.

You need to standardize the minimum to 0 and the maximum to one, since r2 is a proportion of the line. A negative % is not possible.

since the minimum is zero you cant have it in the denominator, so you have to set it like this

so use 1 - [0/r1]

there is a python module for fixing this error


from sklearn.metrics import r2_score

如何解释MANE_TEST_SCORE和STD_TEST_SCORE?

还在原地等你 2025-02-13 00:39:42

我看到的主要安全问题是,任何人都可以更改其存储的用户ID,以将其作为其他用户进行身份验证。

而且,如果您的用户ID是增量的,您甚至不必知道任何用户ID,您可以猜到它们。如果我的用户ID是108,那么可能有107,109等。

我的建议是尝试实现诸如JWT身份验证之类的东西,但是如果一开始太多,则存储用户ID和秘密字符串的哈希(例如SHA256)将使无法猜测。这样,您就不能仅将用户形式复制到本地存储。在服务器中,您会收到Hash和userId,因此您可以使用UserId和Secret String复制哈希,如果它们匹配,则可以使用。

The main security issue I see is that anyone can change their stored userId to be authenticated as any other user.

And if your userIds are incremental, you don't even have to know any userId, you can guess them. If my userId is 108, then probably there's a 107, a 109, and so on.

My advice is to try to implement something like a JWT authentication, but if it's too much to begin with, storing a hash (like sha256) of the userId plus a secret string will make it impossible to guess. This way you can't just copy userIds to your localstorage. In the server you receive the hash and the userId, so you replicate the hash with the userId plus your secret string, and if they match, you're good to go.

反应身份验证处理

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