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与他有关 2025-02-08 02:40:26

代码的快速副本和粘贴到混音中,表明您在投标功能后的关闭式设备放错了。如果您删除了放错位置的闭合支架,则您的代码应正确编译。

A quick copy and paste of your code to remix shows that you have a misplaced closing brace after the bid function. If you remove that misplaced closing brace, your code should compile correctly.

如何求解ParserError:预期的PRAGMA,进口指令或合同/接口/库/struct/enum/constant/constant/function/错误定义。在固体中

与他有关 2025-02-08 01:20:47

您可以尝试

Assert.IsType<ViewResult>(result);

如果重定向到另一个动作,结果将是
RedirecttoActionResult

You could try with

Assert.IsType<ViewResult>(result);

if redirected to another action,the result will be
RedirectToActionResult
enter image description here

如何断言Xunit中的行动返回类型

与他有关 2025-02-07 20:56:49

是的!

json_encoders 是一个很好的尝试,但是在hood pydantic下调用json.dumps 。因此,对于可序列化类型(例如 snowflakeid ),它不在乎其他 json_encoders

您可以做的是覆盖转储方法:

def my_dumps(v, *, default):
    for key, value in v.items():
        if isinstance(value, SnowflakeId):
            v[key] = str(value)
        else:
            v[key] = value
    return json.dumps(v)

class BaseModel(pydantic.BaseModel):
    id: SnowflakeId

    class Config:
        json_dumps = my_dumps

validate 返回 snowflakeid

class SnowflakeId(int):
    ...

    @classmethod
    def validate(cls, v: str):
        return cls(v)
m = BaseModel(id="123")
print(m.json()) # {"id": "123"}

Yes it is!

json_encoders is a good try, however under the hood pydantic calls json.dumps. So for serializable types (like your SnowflakeId) it won't care about additional json_encoders.

What you can do is to override dumps method:

def my_dumps(v, *, default):
    for key, value in v.items():
        if isinstance(value, SnowflakeId):
            v[key] = str(value)
        else:
            v[key] = value
    return json.dumps(v)

class BaseModel(pydantic.BaseModel):
    id: SnowflakeId

    class Config:
        json_dumps = my_dumps

And let validate return SnowflakeId:

class SnowflakeId(int):
    ...

    @classmethod
    def validate(cls, v: str):
        return cls(v)
m = BaseModel(id="123")
print(m.json()) # {"id": "123"}

如何序列化在Pydantic中扩展内置类型的自定义类型?

与他有关 2025-02-07 16:10:42

C ++中的切片问题来自其对象的值语义,这主要是由于与C结构的兼容性。您需要使用显式参考或指针语法来实现在大多数其他使用对象的语言中发现的“正常”对象行为,即始终通过参考传递对象。

简短的答案是,通过将派生对象分配给基本对象 by Value ,即剩下的对象只是派生对象的一部分。为了保留价值语义,切片是一种合理的行为,并且具有相对罕见的用途,在大多数其他语言中都不存在。有些人认为这是C ++的特征,而许多人认为它是C ++的怪癖/错误之一。

The slicing problem in C++ arises from the value semantics of its objects, which remained mostly due to compatibility with C structs. You need to use explicit reference or pointer syntax to achieve "normal" object behavior found in most other languages that do objects, i.e., objects are always passed around by reference.

The short answers is that you slice the object by assigning a derived object to a base object by value, i.e. the remaining object is only a part of the derived object. In order to preserve value semantics, slicing is a reasonable behavior and has its relatively rare uses, which doesn't exist in most other languages. Some people consider it a feature of C++, while many considered it one of the quirks/misfeatures of C++.

什么是对象切片?

与他有关 2025-02-06 10:58:55

React路由器v6 在这里。根据此doc ::

import React from "react";
import { BrowserRouter, Routes ,Route } from 'react-router-dom';
import "./App.css";
import NavBar from "./components/NavBar/NavBar";
import Footer from "./components/Footer/Footer";

import VolcanoInfo from "./components/VolcanoInfo/VolcanoInfo";

import Blank1 from "./components/Blank1/Blank1";

import Blank2 from "./components/Blank2/Blank2";

import Blank3 from "./components/Blank3/Blank3";

import image from './image.jpg';

//TODO Web Template Studio: Add routes for your new pages here.
const App = () => {
    return (
      
      <BrowserRouter>
        <header className="App-header">
           <img src={image} className="image" alt="image" />
        </header>
        <NavBar />
        <Routes>
          <Route path = "/VolcanoInfo" element= { <VolcanoInfo /> } />
          <Route path = "/Blank1" element= { <Blank1 />} />
          <Route path = "/Blank2" element= { <Blank2 />} />
          <Route path = "/Blank3" element= { <Blank3 />} />
        </Routes>
        <Footer />
      </BrowserRouter>
    );
}




export default App;

Tutorial for React Router v6 in here. And many change from v5 to v6 according to this doc :

import React from "react";
import { BrowserRouter, Routes ,Route } from 'react-router-dom';
import "./App.css";
import NavBar from "./components/NavBar/NavBar";
import Footer from "./components/Footer/Footer";

import VolcanoInfo from "./components/VolcanoInfo/VolcanoInfo";

import Blank1 from "./components/Blank1/Blank1";

import Blank2 from "./components/Blank2/Blank2";

import Blank3 from "./components/Blank3/Blank3";

import image from './image.jpg';

//TODO Web Template Studio: Add routes for your new pages here.
const App = () => {
    return (
      
      <BrowserRouter>
        <header className="App-header">
           <img src={image} className="image" alt="image" />
        </header>
        <NavBar />
        <Routes>
          <Route path = "/VolcanoInfo" element= { <VolcanoInfo /> } />
          <Route path = "/Blank1" element= { <Blank1 />} />
          <Route path = "/Blank2" element= { <Blank2 />} />
          <Route path = "/Blank3" element= { <Blank3 />} />
        </Routes>
        <Footer />
      </BrowserRouter>
    );
}




export default App;

可以通往reactj中另一页的路由

与他有关 2025-02-06 09:24:10

关于这个问题,您可能需要使用 CSS模块,它仍然是CSS,但仅影响一个组件。

注意:这宁愿使用React App和WebPack,我没有使用其他环境进行测试=))

文件结构:

|
|_ MyComponent.module.css
|_ MyComponent.js

mycomponent.module.css:

.myColor {
  color: #5D5C5C;
}

mycomponent.js:

import styles from './MyComponent.module.css';

...

<Card.Meta className={{styles.myColor}}>
  {calculateTime(post.createdAt)}
</Card.Meta>

About this issue, you might want to use CSS module, it's still CSS, but only affect in one component only.

Note: this would prefer to work with React app and webpack, I haven't tested with other environment =)))

File structure:

|
|_ MyComponent.module.css
|_ MyComponent.js

MyComponent.module.css:

.myColor {
  color: #5D5C5C;
}

MyComponent.js:

import styles from './MyComponent.module.css';

...

<Card.Meta className={{styles.myColor}}>
  {calculateTime(post.createdAt)}
</Card.Meta>

语义ui:className di d di n die not style

与他有关 2025-02-06 08:44:29

您可以将Visual Studio代码用于ASP.NET开发。
您需要安装扩展C#以进行代码智能。

要运行DOT Net应用程序,您可以使用CMD。

dotnet run

请参阅 Microsoft page

You can use visual studio code for asp.net development.
you need install extension c# for code intelligence.

To run dot net application you can use cmd.

dotnet run

Please refer Microsoft page for more command

VS代码或Visual Studio用于ASP.NET开发

与他有关 2025-02-06 04:00:44

我曾认为提供商中有这样的功能,但没有,那将是有用的。

目前,我的解决方案是创建构造方法将所有内容都设置回东西,因此我可以在导航之前将其调用。

I had thought that there was such a function like this in Provider but no, would've been useful.

For now my solution was to create constructor methods that set everything back, so I can call them before I navigate.

更新提供商软件包的密钥值?

与他有关 2025-02-05 23:24:49

问题在于以下行:

    for(j=1;j<5;j++){

将其更改为:

    for(j=i+1;j<5;j++){

否则它将交换以前分类的元素。固定版本开始查看第一个元素 正在处理的版本。

The problem is with this line:

    for(j=1;j<5;j++){

Change it to:

    for(j=i+1;j<5;j++){

Otherwise it will swap previously sorted elements. The fixed version starts looking at the first element after the one being processed.

这个简单的排序阵列代码中有什么错误?

与他有关 2025-02-05 14:01:15

使用查找(sub_str)函数。

new_list = [item[item.find("eww"):] for item in List]
print(new_list)

输出:

['eww/d/df/rr/e.jpg', 'eww/ees/err/err.jpg', 'eww/err/dd.jpg']

Use find(sub_str) function.

new_list = [item[item.find("eww"):] for item in List]
print(new_list)

Output:

['eww/d/df/rr/e.jpg', 'eww/ees/err/err.jpg', 'eww/err/dd.jpg']

与Python的名单分开

与他有关 2025-02-05 13:13:16

您可以使用外部表从云存储将蜂巢表从云存储中导入到数据链球上,并使用databricks sql查询它。

步骤1:在您的Hive命令行上显示创建表语句

问题a show create table&gt; 命令,以查看创建表的语句。

请参阅下面的示例:

hive> SHOW CREATE TABLE wikicc;
OK
CREATE  TABLE `wikicc`(
  `country` string,
  `count` int)
ROW FORMAT SERDE
  'org.apache.hadoop.hive.serde2.lazy.LazySimpleSerDe'
STORED AS INPUTFORMAT
  'org.apache.hadoop.mapred.TextInputFormat'
OUTPUTFORMAT
  'org.apache.hadoop.hive.ql.io.HiveIgnoreKeyTextOutputFormat'
LOCATION
  '/user/hive/warehouse/wikicc'
TBLPROPERTIES (
  'totalSize'='2335',
  'numRows'='240',
  'rawDataSize'='2095',
  'COLUMN_STATS_ACCURATE'='true',
  'numFiles'='1',
  'transient_lastDdlTime'='1418173653')

步骤2:发行创建外部表语句,

如果返回的语句使用 create table 命令,复制语句并替换用使用创建外部表

  • 外部确保Spark SQL在丢弃表格时不会删除数据。

  • 您可以省略tblproperties字段。

drop table wikicc

CREATE EXTERNAL TABLE `wikicc`(
  `country` string,
  `count` int)
ROW FORMAT SERDE
  'org.apache.hadoop.hive.serde2.lazy.LazySimpleSerDe'
STORED AS INPUTFORMAT
  'org.apache.hadoop.mapred.TextInputFormat'
OUTPUTFORMAT
  'org.apache.hadoop.hive.ql.io.HiveIgnoreKeyTextOutputFormat'
LOCATION
  '/user/hive/warehouse/wikicc'

步骤3:您的数据上的sql命令

select * select *来自wikicc

source> source: https://docs.databricks.com/data/data/data-sources/hive-tables.htables.html

You can import a Hive table from cloud storage into Databricks using an external table and query it using Databricks SQL.

Step 1: Show the CREATE TABLE statement

Issue a SHOW CREATE TABLE <tablename> command on your Hive command line to see the statement that created the table.

Refer below example:

hive> SHOW CREATE TABLE wikicc;
OK
CREATE  TABLE `wikicc`(
  `country` string,
  `count` int)
ROW FORMAT SERDE
  'org.apache.hadoop.hive.serde2.lazy.LazySimpleSerDe'
STORED AS INPUTFORMAT
  'org.apache.hadoop.mapred.TextInputFormat'
OUTPUTFORMAT
  'org.apache.hadoop.hive.ql.io.HiveIgnoreKeyTextOutputFormat'
LOCATION
  '/user/hive/warehouse/wikicc'
TBLPROPERTIES (
  'totalSize'='2335',
  'numRows'='240',
  'rawDataSize'='2095',
  'COLUMN_STATS_ACCURATE'='true',
  'numFiles'='1',
  'transient_lastDdlTime'='1418173653')

Step 2: Issue a CREATE EXTERNAL TABLE statement

If the statement that is returned uses a CREATE TABLE command, copy the statement and replace CREATE TABLE with CREATE EXTERNAL TABLE.

  • EXTERNAL ensures that Spark SQL does not delete your data if you drop the table.

  • You can omit the TBLPROPERTIES field.

DROP TABLE wikicc

CREATE EXTERNAL TABLE `wikicc`(
  `country` string,
  `count` int)
ROW FORMAT SERDE
  'org.apache.hadoop.hive.serde2.lazy.LazySimpleSerDe'
STORED AS INPUTFORMAT
  'org.apache.hadoop.mapred.TextInputFormat'
OUTPUTFORMAT
  'org.apache.hadoop.hive.ql.io.HiveIgnoreKeyTextOutputFormat'
LOCATION
  '/user/hive/warehouse/wikicc'

Step 3: Issue SQL commands on your data

SELECT * FROM wikicc

Source: https://docs.databricks.com/data/data-sources/hive-tables.html

Databricks SQL似乎不支持SQL Server

与他有关 2025-02-02 17:58:19

当一列在SELECT中重命名时,这也有效:

select('New Name' = ulgy_old_name) %>%

arrange(.data[[ 'New Name']])

This also works when a column is renamed in a select:

select('New Name' = ulgy_old_name) %>%

arrange(.data[[ 'New Name']])

为什么不使用vector元素在for循环中正确排列排序

与他有关 2025-02-02 15:28:33

while循环当前阻止线程

您确定吗?因为 clientwebsocket.connectasockenc 明确指出

此操作不会阻止。返回的任务对象将完成
在Clientwebsocket实例上的连接请求之后
完成。

因此, connectAsync 不应阻止,因此都不应循环。但是,即使是不封锁的,它仍然可能会消耗大量的CPU使用情况。否则可能会在打电话 clientwebsocket.connectasync 之前就可以投掷一些东西,并且由于您只吃所有您永远不会知道的例外。

使我们有可能在StartAsync执行期间致电StopAsync,并取消永久重试的过程

您应该在螺纹或异步上下文中停止某些服务时要小心。由于其他任务可能会发现所需的资源已被处置。

while(!等待connectAsync()。configureawait(false)&amp;&amp;&amp;!

问题是,如果没有建立连接,则循环将退出并继续运行该方法。因此,建议使用 fortifCancellationRequested ,即使将异常用于流控制有些痛苦。

我的建议是使 startAsync 取下逐步流产的to否。此方法应返回代表连接的对象,即 task&lt; myConnection&gt; 。此连接对象应处置。 。

// Create connection
var cts = new CancellationTokenSource();
var myStartAsyncConnectionTask = StartAsync(cts.Token);

// Close connection
cts.Cancel();
try{
    var myConnection = await myStartAsyncConnectionTask;
    myConnection.Dispose();
}
catch(OperationCancelledException)
{
...
}

无论连接所在状态如何,都可以停止连接 如果它没有连接,那么等待任务就应该投掷。请注意, startAsync 需要编写,以便在任何阶段抛出任何异常的情况下清理任何创建的资源。

The while loop currently blocks the thread

Are you sure? because ClientWebSocket.ConnectAsync explicitly states

This operation will not block. The returned Task object will complete
after the connect request on the ClientWebSocket instance has
completed.

So ConnectAsync should not block, and therefore neither the while loop. But even if it is non-blocking it might still consume significant CPU usage. Or something might throw before you even call ClientWebSocket.ConnectAsync, and since you just eat all the exceptions you will never know.

make it possible for us to call StopAsync during StartAsync's execution and cancel that process of retrying forever

You should be careful when stopping some service in a threaded or async context. Since some other task might find that the needed resource have been disposed.

while (!await ConnectAsync().ConfigureAwait(false) && !_tokenSource.IsCancellationRequested)

The problem with this is that the loop will exit and continue running the method if no connection has been established. Because of this it is recommended to use ThrowIfCancellationRequested, even if it is somewhat painful to use exceptions for flow control.

My recommendations would be to make StartAsync take a cancellationToken that aborts the connection process. This method should return an object representing the connection, i.e. Task<MyConnection>. This connection object should be disposable. Stopping the connection could be done like

// Create connection
var cts = new CancellationTokenSource();
var myStartAsyncConnectionTask = StartAsync(cts.Token);

// Close connection
cts.Cancel();
try{
    var myConnection = await myStartAsyncConnectionTask;
    myConnection.Dispose();
}
catch(OperationCancelledException)
{
...
}

That should work regardless of what state the connection is in. If a connection has been established the cancellation will do nothing, and the object will be disposed. If it has failed to connect, awaiting the task should throw. Note that StartAsync need to be written so that it cleans up any created resource in case the method throws any exception at any stage.

取消并不按预期进行

与他有关 2025-02-02 14:11:20

添加了 console.log ,以帮助了解递归的工作原理。引入了变量 idx ,以帮助跟踪递归级别。

function steamrollArray(arr, idx=0) {
  console.log('bgn--> recursion # ', idx);
  console.log('arr: ', JSON.stringify(arr));
  let answer = [].concat(...arr);
  console.log(
    'computed answer: ', JSON.stringify(answer)
  );
  if(answer.some(Array.isArray)){
    // "answer" has an array, so recurse to next level
    console.log(
      'at least ONE elt in "answer" is an array\n',
      '--> making recursive call from recursion #: ',
      idx
    );
    return steamrollArray(answer, idx+1);
  };
  console.log(
    'no elt in "answer" is an array\n',
    'no more recursion from recursion #: ', idx,
    ' answer: ', answer.join(),
    ' has ZERO arrays ...'
  );
  return answer;
}

let result = steamrollArray([1, [2], [3, [[4]]]]);
// console.log(result)
.as-console-wrapper { max-height: 100% !important; top: 0 }

Have added console.log to help with understanding how the recursion works. Introduced a variable idx to help track the level of recursion.

function steamrollArray(arr, idx=0) {
  console.log('bgn--> recursion # ', idx);
  console.log('arr: ', JSON.stringify(arr));
  let answer = [].concat(...arr);
  console.log(
    'computed answer: ', JSON.stringify(answer)
  );
  if(answer.some(Array.isArray)){
    // "answer" has an array, so recurse to next level
    console.log(
      'at least ONE elt in "answer" is an array\n',
      '--> making recursive call from recursion #: ',
      idx
    );
    return steamrollArray(answer, idx+1);
  };
  console.log(
    'no elt in "answer" is an array\n',
    'no more recursion from recursion #: ', idx,
    ' answer: ', answer.join(),
    ' has ZERO arrays ...'
  );
  return answer;
}

let result = steamrollArray([1, [2], [3, [[4]]]]);
// console.log(result)
.as-console-wrapper { max-height: 100% !important; top: 0 }

Steamroller JavaScript代码如何发生

与他有关 2025-02-01 14:30:32

最简单的方法是在 student 类中创建方法 tohashmap()

public LinkedHashMap<String,Object> toHashMap(){
    LinkedHashMap<String, Object> h = new LinkedHashMap<>();
    h.put("Id",id);
    h.put("Name", name);
    h.put("Age",age);
    return h;
}

我使用 linkedHashmap 来保留插入顺序。完成此操作后,请尝试以下操作:

List<Student> ls = new ArrayList<>();
ls.add(new Student(12123,"Tom",12));
ls.add(new Student(12354,"George",21));
ls.add(new Student(12245,"Sara",16));
ls.add(new Student(17642,"Caitlyn",11));


List<LinkedHashMap<String,Object>> names = ls.stream().map(Student::toHashMap).collect( Collectors.toList() );

System.out.println(names);

输出: [{ID = 12123,name = tom,age = 12},{id = 12354,name = george,age = 21},{id = 12245,name = sara = sara = sara ,age = 16},{id = 17642,name = caitlyn,age = 11}]

Easiest way would be to create a method toHashMap() in your Student class:

public LinkedHashMap<String,Object> toHashMap(){
    LinkedHashMap<String, Object> h = new LinkedHashMap<>();
    h.put("Id",id);
    h.put("Name", name);
    h.put("Age",age);
    return h;
}

I use a LinkedHashMap to preserve the insertion order. Once that is done, try this:

List<Student> ls = new ArrayList<>();
ls.add(new Student(12123,"Tom",12));
ls.add(new Student(12354,"George",21));
ls.add(new Student(12245,"Sara",16));
ls.add(new Student(17642,"Caitlyn",11));


List<LinkedHashMap<String,Object>> names = ls.stream().map(Student::toHashMap).collect( Collectors.toList() );

System.out.println(names);

Output: [{Id=12123, Name=Tom, Age=12}, {Id=12354, Name=George, Age=21}, {Id=12245, Name=Sara, Age=16}, {Id=17642, Name=Caitlyn, Age=11}]

如何将Java对象列表转换为地图列表

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