软的没边

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软的没边 2025-02-02 19:33:08

修复程序最终是:

  • 移动{{widgets.record_vm.recordingurl}}}媒体URL字段到Message> Message> Message字段,如图所示。
  • (感谢Akash @ twilio支持!)

”在此处输入图像描述

The fix ended up being:

  • Move {{widgets.RECORD_VM.RecordingUrl}} from the MEDIA URL field to the MESSAGE BODY field as shown.
  • (Thanks to Akash @ Twilio Support!)

enter image description here

Twilio无法将记录的语音邮件发送给短信

软的没边 2025-02-02 19:26:40

这意味着您的价格列中的某些记录可能具有字符串值“ 48.5200.048.5200.0200.0200.0200.0200.037.037.0200.037.0200.0200.0200.037.0200.0200.0200.0200.0200.0200.0200.0.0200.0200.0200.0200.0200.0200.0200.0200.0200.0200.0200.0200.0200.0200.0200.0200.0200.0200.0200.0200.0200.0200.0200.0200.0200.bit .0200.0200.037.0200.037.0200.0200.0200.0200.0200.037.0200.0200.0200.0200.0200.0200.0200.0200.0200.0200.037.0200

稍后,您进行了该列和>的比较。 0。 python虽然动态,但仍然强烈键入,这意味着您通常只能比较相同类型的值。字符串不是一个数字,也不能与数字进行比较,因此,如果定价列包含字符串,则类型。

为了解决您的问题,您将必须以某种方式将长字符串转换为可以转换为数字的可以转换为。您通常只能使用单个小数分离器转换一些东西。例如,float(“ 48.5200”)将起作用,但是float(“ 48.5200.048”) not。

我相信您的groupby.sum()可能正在创建这个长字符串。在进行GroupBy操作之前,将Price列转换为float

This means some record in your Price column likely has a string with the literal value "48.5200.048.5200.0200.0200.037.0200.037.0200.0200.037.0200.0200.037.0200.0200.037.0200.037.0200.0200.0200.037.0200.0200.037.0200.037.0200.0200.0200.0200.037.0200.0200.0200.0200.037.0200.0200.037.0200"

This string format cannot be naively converted to a number, and thus the conversion fails.

Later you do a comparison between that column and > 0. Python, while dynamic, is still strongly typed, meaning that you can only usually compare values of the same type. A string isn't a number and cannot be compared to a number, hence the TypeError if the Pricing column contains strings.

To resolve your issue, you will have to somehow convert your long string to something that can be converted to a number. You can typically only convert something with a single decimal separator. For example, float("48.5200") will work, but float("48.5200.048") won't.

I believe your groupby.sum() is probably creating this long string. Convert the Price column to a float before doing the groupby operation.

ValueError:Int()带有10:' 48.5200.048.5200.0200的Int()文字无效

软的没边 2025-02-02 16:40:20

基于ID的选择器不起作用的原因

  1. 尚不存在带有ID的元素/DOM。
  2. 该元素存在,但没有在DOM中注册(如果HTML节点从AJAX响应动态附加)。
  3. 存在多个具有相同ID的元素,这会导致冲突。

solutions

  1. 在声明后尝试访问该元素,或者使用$(docund)$(document).ready();

    之类的东西

  2. 诸如来自ajax响应的元素的内容,请使用jQuery的.bind()方法。 jQuery的较旧版本的.live()

  3. 使用工具[例如,用于浏览器的Web -Developer插件]来查找重复的ID并删除它们。

Reasons why id based selectors don't work

  1. The element/DOM with id specified doesn't exist yet.
  2. The element exists, but it is not registered in DOM [in case of HTML nodes appended dynamically from Ajax responses].
  3. More than one element with the same id is present which is causing a conflict.

Solutions

  1. Try to access the element after its declaration or alternatively use stuff like $(document).ready();

  2. For elements coming from Ajax responses, use the .bind() method of jQuery. Older versions of jQuery had .live() for the same.

  3. Use tools [for example, webdeveloper plugin for browsers] to find duplicate ids and remove them.

为什么jQuery或诸如getElementById之类的DOM方法找不到元素?

软的没边 2025-02-02 14:00:59

这是代码 -
确保用床单替换Sheet1。


Private Sub Worksheet_Change(ByVal Target As Range)

If Target.Address = "$E$6" Or Target.Address = "$E$30" Then

    If Sheet1.Range("E30").Value = "No" And Sheet1.Range("E6").Value = "VIC" Then
    
        Sheet1.Range("A1:A45").Rows.EntireRow.Hidden = False
        Sheet1.Range("A46:A81").Rows.EntireRow.Hidden = True
    
    ElseIf Sheet1.Range("E30").Value = "Yes" And Sheet1.Range("E6").Value = "VIC" Then
        
        Sheet1.Range("A1:A33").Rows.EntireRow.Hidden = False
        Sheet1.Range("A34:A81").Rows.EntireRow.Hidden = True
    
    ElseIf Sheet1.Range("E30").Value = "No" And Sheet1.Range("E6").Value = "OTHER" Then
        
        Sheet1.Range("A1:A33").Rows.EntireRow.Hidden = False
        Sheet1.Range("A64:A81").Rows.EntireRow.Hidden = False
        Sheet1.Range("A34:A63").Rows.EntireRow.Hidden = True
    
    ElseIf Sheet1.Range("E30").Value = "Yes" And Sheet1.Range("E6").Value = "OTHER" Then
        
        Sheet1.Range("A1:A33").Rows.EntireRow.Hidden = False
        Sheet1.Range("A34:A81").Rows.EntireRow.Hidden = True
    
    End If

Here is the code -
Make sure to replace Sheet1 with your sheet.


Private Sub Worksheet_Change(ByVal Target As Range)

If Target.Address = "$E$6" Or Target.Address = "$E$30" Then

    If Sheet1.Range("E30").Value = "No" And Sheet1.Range("E6").Value = "VIC" Then
    
        Sheet1.Range("A1:A45").Rows.EntireRow.Hidden = False
        Sheet1.Range("A46:A81").Rows.EntireRow.Hidden = True
    
    ElseIf Sheet1.Range("E30").Value = "Yes" And Sheet1.Range("E6").Value = "VIC" Then
        
        Sheet1.Range("A1:A33").Rows.EntireRow.Hidden = False
        Sheet1.Range("A34:A81").Rows.EntireRow.Hidden = True
    
    ElseIf Sheet1.Range("E30").Value = "No" And Sheet1.Range("E6").Value = "OTHER" Then
        
        Sheet1.Range("A1:A33").Rows.EntireRow.Hidden = False
        Sheet1.Range("A64:A81").Rows.EntireRow.Hidden = False
        Sheet1.Range("A34:A63").Rows.EntireRow.Hidden = True
    
    ElseIf Sheet1.Range("E30").Value = "Yes" And Sheet1.Range("E6").Value = "OTHER" Then
        
        Sheet1.Range("A1:A33").Rows.EntireRow.Hidden = False
        Sheet1.Range("A34:A81").Rows.EntireRow.Hidden = True
    
    End If

根据多个标准隐藏行

软的没边 2025-02-02 10:36:00

让我们分析以下表达式:

expr = 2*utu
# out: 2*u_1**2 + 2*u_2**2 + 2*u_3**2

已经评估了乘法。这是Sympy的默认行为:它评估事物。我们可以使用表达操纵功能来实现我们的目标。

例如:

expr = collect_const(expr)
# out: 2*(u_1**2 + u_2**2 + u_3**2)
expr.subs(utu, 1)
# out: 2

另一个示例:

expr = (2 * u).norm()
# out: sqrt(4*u_1**2 + 4*u_2**2 + 4*u_3**2)
expr = expr.simplify() # Note that expr.factor() produces the same result with this expression
# out: 2*sqrt(u_1**2 + u_2**2 + u_3**2)
expr.subs(utu, 1)
# out: 2

如果您在这些示例中播放(和修改),您会意识到可以通过不同的功能(因素,简化,收集,collect_const,...)实现相同的结果,但甚至有一点更改该表达可能会阻止一个函数“完成工作”,而其他功能也许可以。表达操纵是一种应该练习的艺术(很多)。

为了完整性,我将向您展示unestexpr,这允许在表达操作过程中保持特定表达式,尽管它可能并不总是最好的选择:

n = UnevaluatedExpr(utu)
# out: u_1**2 + u_2**2 + u_3**2
expr = 4 * n
# out: 4*(u_1**2 + u_2**2 + u_3**2)

请注意,Sympy没有继续进行全面评估。现在:

expr.subs(utu, 1)
# out: 4*1

为什么有一个4*1而不是4? 1是指我们之前创建的unevaluateexpr对象:要评估它,我们可以使用doit()方法:

expr.subs(utu, 1).doit()
# 4

请记住,请记住。使用unevaluateExpr,表达式变得不交流(我认为这是Sympy的错误),这将阻止其他功能产生预期的结果。

Let's analyze this expression:

expr = 2*utu
# out: 2*u_1**2 + 2*u_2**2 + 2*u_3**2

The multiplication has been evaluated. This is SymPy's default behavior: it evaluates things. We can work with the expression manipulation functions to achieve our goal.

For example:

expr = collect_const(expr)
# out: 2*(u_1**2 + u_2**2 + u_3**2)
expr.subs(utu, 1)
# out: 2

Another example:

expr = (2 * u).norm()
# out: sqrt(4*u_1**2 + 4*u_2**2 + 4*u_3**2)
expr = expr.simplify() # Note that expr.factor() produces the same result with this expression
# out: 2*sqrt(u_1**2 + u_2**2 + u_3**2)
expr.subs(utu, 1)
# out: 2

If you play (and modify) with these examples, you will realize that the same result can be achieved with different functions (factor, simplify, collect, collect_const, ...), but even one little change in the expression might prevent one function from "doing its work", while others might be able to. Expression manipulation is kind of an art that one should practice (a lot).

For completeness, I'm going to show you UnevaluatedExpr, which allows a particular expression to remain unevaluated during expression manipulation, though it might not always be the best choice:

n = UnevaluatedExpr(utu)
# out: u_1**2 + u_2**2 + u_3**2
expr = 4 * n
# out: 4*(u_1**2 + u_2**2 + u_3**2)

Note that SymPy didn't proceed with the full evaluation. Now:

expr.subs(utu, 1)
# out: 4*1

Why is there a 4*1 instead of 4? The 1 refers to the UnevaluateExpr object that we created earlier: to evaluate it we can use the doit() method:

expr.subs(utu, 1).doit()
# 4

Keep in mind that while using UnevaluateExpr, the expression becomes non-commutative (I think it's a bug with SymPy), which will prevent other functions to produce the expected results.

Sympy:简化表达式替代

软的没边 2025-02-01 20:30:20

target_link_libraries不会自动链接任何内容。您应该具有先前通过add_library(或add_executable)创建的目标,其中所有文件均被列出。

这些目标添加到您的CMAKE项目中的方式可能有所不同。例如,您可以在某些文件夹libs/mylib下使用 cmakelists.txt.txt 配置的库源文件。然后,在您的 cmakelists.txt 中,您可以将库添加到add_subdirectory(libs/mylib)。另一个选项是添加find_package的库。

target_link_libraries doesn't link anything automatically. You should have a target previously created via add_library (or add_executable), where all files are listed.

The way these targets added into your CMake project may differ. E.g. you may have a library source files with CMakeLists.txt configuration (where the said add_library command is) under some folder libs/mylib. Then in your CMakeLists.txt you may have the library added with add_subdirectory(libs/mylib). Another option is to add the library with find_package.

Target_link_libraries在哪里寻找所需的文件?

软的没边 2025-02-01 16:36:32

您可以制作3个嵌套环,有些类似:

for (int i = 0; i<2; i++) {
       
       for(int j = 0; j<2; j++) {
           
           for(int k = 0; k<2; k++) {
               
               //put your code here
           }
       }
   }

you can make 3 nested loops, some thing like:

for (int i = 0; i<2; i++) {
       
       for(int j = 0; j<2; j++) {
           
           for(int k = 0; k<2; k++) {
               
               //put your code here
           }
       }
   }

如何以不同的组合来安排阵列?

软的没边 2025-01-31 23:28:49

在SVA 1中,有效地是通配符,因为从定义上讲,它是正确的。因此,它与任何东西匹配。

&lt; expression&gt; [&lt;编号或范围&gt;]是SVA重复运算符。

$表示“无限”。

因此,1 [0:$]表示“零或更多次”。

有更好的方法吗?是的。以下是其他一些方法,这些方法都遭受了与您的例子相同的问题的困扰:

state==ACTIVE1 |-> ##[0:$] state==ACTIVE2
state==ACTIVE1 |-> eventually state==ACTIVE2

这些问题是什么?

(i)如果有很多active1 s,而没有active2 s,则将启动越来越多的检查(即产卵),这会减慢您的模拟。这是使用$最终在右侧的的问题( 条件) 。

(ii)您的断言永远不会失败:宇宙的热死亡没有Active2没有关系,您的断言不会失败。这是一个妥协的断言,即所谓的 strong 属性:

state==ACTIVE1 |-> s_eventually state==ACTIVE2

s _代表“强”。现在,如果您的断言在模拟结束时没有通过,那被认为是失败的。

In SVA 1 is effectively a wildcard, because it is, by definition, true. So it matches anything.

<expression>[<number or range>] is the SVA repetition operator.

$ means "infinity".

So, 1[0:$] means "anything zero or more times".

Is there a better way to do it? Yes. Here are some other ways to do it that suffer all suffer from the same problems that your example does:

state==ACTIVE1 |-> ##[0:$] state==ACTIVE2
state==ACTIVE1 |-> eventually state==ACTIVE2

What are these problems?

(i) If there are lots of ACTIVE1s and no ACTIVE2s then more and more checks will be started (ie threads spawned), which slows down your simulation. This is a problem with the use of $ or eventually on the right hand side (the consequent or condition).

(ii) Your assertion can never fail: it doesn't matter whether there has been no ACTIVE2 by the heat death of the universe, your assertion will not fail. Here is a compromise assertion, a so-called strong property:

state==ACTIVE1 |-> s_eventually state==ACTIVE2

The s_ stands for "strong". Now, if your assertion has not passed by the end of the simulation, that is considered a fail.

| - &gt的含义; 1 [0:$]主张

软的没边 2025-01-31 17:58:15

要输入网站您需要诱导 webdriverwait 对于并且您可以使用以下 lotator Strategies

  • 使用 css_selector EM>:

      driver.get(“ https://account.chrobinson.com/”)
    webdriverwait(驱动程序,20).until(ec.element_to_be_clickable(((by.css_selector
    driver.find_element(by.css_selector,“输入[name ='password']”)。send_keys(“ ribella”)
    driver.find_element(by.css_selector,“ input [value ='in in']”)。click()
     
  • 注意:您必须添加以下导入:

     来自selenium.webdriver.support.ui导入webdriverwait
    从selenium.webdriver.common.通过进口
    从selenium.webdriver.support进口预期_conditions作为ec
     
  • 浏览器快照:

“

To enter sign in information for the website you need to induce WebDriverWait for the element_to_be_clickable() and you can use the following locator strategies:

  • Using CSS_SELECTOR:

    driver.get("https://account.chrobinson.com/")
    WebDriverWait(driver, 20).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "input[name='username']"))).send_keys("Ribella")
    driver.find_element(By.CSS_SELECTOR, "input[name='password']").send_keys("Ribella")
    driver.find_element(By.CSS_SELECTOR, "input[value='Sign In']").click()
    
  • Note: You have to add the following imports :

    from selenium.webdriver.support.ui import WebDriverWait
    from selenium.webdriver.common.by import By
    from selenium.webdriver.support import expected_conditions as EC
    
  • Browser Snapshot:

chrobinson

Python Web刮擦带有请求登录

软的没边 2025-01-31 11:21:02

实现该布局的最佳方法是使用CSS网格。我使用网格布局,然后为每个部分嵌套。

.title {
            text-align: center;
            padding: 2rem 0;
        }

        .grid-container {
            display: grid;
            grid-template-columns: repeat(2, 1fr);
            grid-gap: 2rem;
            padding: 0 2rem;
        }

        img {
            max-width: 100%;
            height: 100%;
            object-fit: cover;
            display: block;
        }

        .jb,
        .ach {
            display: grid;
            grid-template-columns: repeat(2, 1fr);
            grid-gap: 1rem;
        }
        
        .ach * {
            grid-column: 1 / -1;
            text-align: center;
        }

        .ach .sectionOne img {
            margin: 0 auto;
        }

@media screen and (max-width: 768px) {
  .grid-container, .jb, .ach {
    grid-template-columns: 1fr;
  }
  
  .sectionOne {
    grid-column: 1 / -1;
  }
  
}
<h1 class="title">Joshua Eachus</h1>
<div class="grid-container">
   <div class="jb">
        <div class="sectionOne">
            <img src="https://picsum.photos/500/300" alt="Joshua EAchus">
        </div>
        <div class="sectionTwo">
            <h2>Job Experience</h2>

            <h3>Menchies</h3>
            <p class="menchies"> Between January 2020-November 2020 I was a team member at menchies, I would mainly greet customers, help them around the store if needed and cash them out with the cash register when ready. I also am constantly busy making sure every topping and yogurt
        machine is filled up for the customers. I would usually be closing so I work 5 to 8 hour shifts every time. When closing I would put all the toppings away, clean the whole store completely and prep food for the next day.</p>

            <h3>Walgreens</h3>
            <p class="Walgreens"> I am currently working at Walgreens, which has been a great introduction into retail and has truly taught me many things. There is a diverse and large amount of tasks I do at Walgreens, one of the main tasks is running the photo department, where
      I print many kinds of photos, create canvases and many more projects. Other tasks includes stocking, outdating, cleaning duties and counting registers.</p>

        </div>
    </div>

    <div class="ach">
        <h3>Achievements</h3>
        <div class="sectionOne">
            <img src="https://picsum.photos/500/300" alt="PTK">
        </div>
        <div class="sectionTwo">
            <p>I am a member of Phi Theta Kappa. Founded on November 19, 1918 Phi Theta Kappa is the world’s largest organization specifically devoted to recognizing the achievements of honor students at 2-year institutions. Currently, PTK has approximately 3 million
                members globally.</p>
        </div>
    </div>
</div>

The best way to achieve that layout would be to use CSS grid. I am using a grid layout and then nested divs for each section.

.title {
            text-align: center;
            padding: 2rem 0;
        }

        .grid-container {
            display: grid;
            grid-template-columns: repeat(2, 1fr);
            grid-gap: 2rem;
            padding: 0 2rem;
        }

        img {
            max-width: 100%;
            height: 100%;
            object-fit: cover;
            display: block;
        }

        .jb,
        .ach {
            display: grid;
            grid-template-columns: repeat(2, 1fr);
            grid-gap: 1rem;
        }
        
        .ach * {
            grid-column: 1 / -1;
            text-align: center;
        }

        .ach .sectionOne img {
            margin: 0 auto;
        }

@media screen and (max-width: 768px) {
  .grid-container, .jb, .ach {
    grid-template-columns: 1fr;
  }
  
  .sectionOne {
    grid-column: 1 / -1;
  }
  
}
<h1 class="title">Joshua Eachus</h1>
<div class="grid-container">
   <div class="jb">
        <div class="sectionOne">
            <img src="https://picsum.photos/500/300" alt="Joshua EAchus">
        </div>
        <div class="sectionTwo">
            <h2>Job Experience</h2>

            <h3>Menchies</h3>
            <p class="menchies"> Between January 2020-November 2020 I was a team member at menchies, I would mainly greet customers, help them around the store if needed and cash them out with the cash register when ready. I also am constantly busy making sure every topping and yogurt
        machine is filled up for the customers. I would usually be closing so I work 5 to 8 hour shifts every time. When closing I would put all the toppings away, clean the whole store completely and prep food for the next day.</p>

            <h3>Walgreens</h3>
            <p class="Walgreens"> I am currently working at Walgreens, which has been a great introduction into retail and has truly taught me many things. There is a diverse and large amount of tasks I do at Walgreens, one of the main tasks is running the photo department, where
      I print many kinds of photos, create canvases and many more projects. Other tasks includes stocking, outdating, cleaning duties and counting registers.</p>

        </div>
    </div>

    <div class="ach">
        <h3>Achievements</h3>
        <div class="sectionOne">
            <img src="https://picsum.photos/500/300" alt="PTK">
        </div>
        <div class="sectionTwo">
            <p>I am a member of Phi Theta Kappa. Founded on November 19, 1918 Phi Theta Kappa is the world’s largest organization specifically devoted to recognizing the achievements of honor students at 2-year institutions. Currently, PTK has approximately 3 million
                members globally.</p>
        </div>
    </div>
</div>

如何让我的CSS匹配此设置?我在边界和元素对齐方面有问题

软的没边 2025-01-31 10:13:07

显然,我无法为选定的答案提供编辑,因此这是适用于Python 3的更新。Translate方法在进行非平凡转换时仍然是最有效的选择。

原始繁重的举重归功于上面的@brian。感谢@ddejohn对原始测试的改进的出色建议。

#!/usr/bin/env python3

"""Determination of most efficient way to remove punctuation in Python 3.

Results in Python 3.8.10 on my system using the default arguments:

set       : 51.897
regex     : 17.901
translate :  2.059
replace   : 13.209
"""

import argparse
import re
import string
import timeit

parser = argparse.ArgumentParser()
parser.add_argument("--filename", "-f", default=argparse.__file__)
parser.add_argument("--iterations", "-i", type=int, default=10000)
opts = parser.parse_args()
with open(opts.filename) as fp:
    s = fp.read()
exclude = set(string.punctuation)
table = str.maketrans("", "", string.punctuation)
regex = re.compile(f"[{re.escape(string.punctuation)}]")

def test_set(s):
    return "".join(ch for ch in s if ch not in exclude)

def test_regex(s):  # From Vinko's solution, with fix.
    return regex.sub("", s)

def test_translate(s):
    return s.translate(table)

def test_replace(s):  # From S.Lott's solution
    for c in string.punctuation:
        s = s.replace(c, "")
    return s

opts = dict(globals=globals(), number=opts.iterations)
solutions = "set", "regex", "translate", "replace"
for solution in solutions:
    elapsed = timeit.timeit(f"test_{solution}(s)", **opts)
    print(f"{solution:<10}: {elapsed:6.3f}")

Apparently I can't supply edits to the selected answer, so here's an update which works for Python 3. The translate approach is still the most efficient option when doing non-trivial transformations.

Credit for the original heavy lifting to @Brian above. And thanks to @ddejohn for his excellent suggestion for improvement to the original test.

#!/usr/bin/env python3

"""Determination of most efficient way to remove punctuation in Python 3.

Results in Python 3.8.10 on my system using the default arguments:

set       : 51.897
regex     : 17.901
translate :  2.059
replace   : 13.209
"""

import argparse
import re
import string
import timeit

parser = argparse.ArgumentParser()
parser.add_argument("--filename", "-f", default=argparse.__file__)
parser.add_argument("--iterations", "-i", type=int, default=10000)
opts = parser.parse_args()
with open(opts.filename) as fp:
    s = fp.read()
exclude = set(string.punctuation)
table = str.maketrans("", "", string.punctuation)
regex = re.compile(f"[{re.escape(string.punctuation)}]")

def test_set(s):
    return "".join(ch for ch in s if ch not in exclude)

def test_regex(s):  # From Vinko's solution, with fix.
    return regex.sub("", s)

def test_translate(s):
    return s.translate(table)

def test_replace(s):  # From S.Lott's solution
    for c in string.punctuation:
        s = s.replace(c, "")
    return s

opts = dict(globals=globals(), number=opts.iterations)
solutions = "set", "regex", "translate", "replace"
for solution in solutions:
    elapsed = timeit.timeit(f"test_{solution}(s)", **opts)
    print(f"{solution:<10}: {elapsed:6.3f}")

从字符串中剥离标点符号的最佳方法

软的没边 2025-01-31 08:58:29

全局范围范围为同一模块。

您有多个选择来解决此问题,其中:

  • 将变量传递给类,并使用self.attribute
  • 将变量传递给该方法。
  • 创建一个包含全局的模块,例如globals.py,并从双方导入它。
  • 使用Import SecondClass注入全局; SecondClass.Somelist = [1,2,3]

和许多其他解决方案。

就个人而言,我将在一周中的任何一天去参加第一或第二天。

global is scoped to the same module.

You have multiple options to solve this, among them:

  • Pass the variable to the class and use self.attribute.
  • Pass the variable to the method.
  • Create a module holding the global, such as globals.py and import it from both sides.
  • Inject the global using import secondclass; secondclass.somelist = [1,2,3]

And plenty of other solutions.

Personally, I'd go for the first or second any day of the week.

尝试从Python中的类实例访问全局变量

软的没边 2025-01-31 07:49:47

我担心Windows 10中关于“虚拟桌面”的所有内容都没有证明,但是在俄罗斯页面中,我看到的记录了界面。我不会说俄语,但似乎他们使用了反向工程。无论如何,代码非常清楚(感谢它们!)。

在这里关注:

http://wwwwwww.cyberforum.ru/blogs/105416/blog3671.html 查看旧的API的CreateSktop,OpenDesktop等...链接到新的Virtual-Desktops,但没有办法...

接口与Windows 10(2015-05-08)的最终生产版本一起使用,但是您在Microsoft记录它们之前,不应在真正的宽分布式应用程序中使用它们。风险太多。

问候。

I fear that all about "Virtual desktops" in Windows 10 is undocumented, but in a Russian page I've seen documented the interfaces. I don't speak Russian but seems that they have used reversed engineering. Anyway, the code is very clear (Thanks to them!).

Keep an eye here:
http://www.cyberforum.ru/blogs/105416/blog3671.html

I've been trying to see if the old API's CreateDesktop, OpenDesktop, etc... is linked to the new Virtual-Desktops, but no way...

The interfaces work with the final production release of Windows 10 (2015-05-08), but you shouldn't use them in a real wide distributed application until Microsoft documents them. Too much risk.

Regards.

Windows 10中虚拟桌面的程序化控制10

软的没边 2025-01-31 02:54:45

您不仅可以将从&lt; casten_image&gt;:&lt; ver&gt;添加到新的Dockerfile指令的顶部,并每次将其构建到新图像中吗?

然后,您的管道仅需要docker build&lt; location&gt; -t my-Sec-image:1 PTP之前。

Could you not just add FROM <existing_image>:<ver> to the top of your new Dockerfile directives and build it every time into a new image?

Then your pipeline needs only docker build <location> -t my-sec-image:1 before PTP.

将二进制注入Docker图像

软的没边 2025-01-31 02:41:00

我发挥了这样的作用并起作用。

function insertVariantsProduct($id_produkt){  
$userData = count($_POST["input_name"]);

if ($userData > 0) {

    for ($i=0; $i < $userData; $i++) { 
        if (trim($_POST['input_name'] != '') && trim($_POST['input_price'] != '')) {
            
            $var_id = $_POST["input_id"][$i];
            $name   = $_POST["input_name"][$i];
            $price  = $_POST["input_price"][$i];
            if(empty($var_id) && !isset($var_id)){      
                $sql = "INSERT INTO variant_product ( id_product, name, price ) VALUES(?,?,?)";
                $data = array("isi", $id_produkt, $name, $price);
            }else {
                $sql = "UPDATE variant_product SET name='$name',price='$price' WHERE id='$var_id'  ";
                $data = null;
            }
            $result = db_query($sql, $data);
            
        }
    }
    return $result; // This should be out of loop because it's will break the loop 

}

}

I make function like that and working.

function insertVariantsProduct($id_produkt){  
$userData = count($_POST["input_name"]);

if ($userData > 0) {

    for ($i=0; $i < $userData; $i++) { 
        if (trim($_POST['input_name'] != '') && trim($_POST['input_price'] != '')) {
            
            $var_id = $_POST["input_id"][$i];
            $name   = $_POST["input_name"][$i];
            $price  = $_POST["input_price"][$i];
            if(empty($var_id) && !isset($var_id)){      
                $sql = "INSERT INTO variant_product ( id_product, name, price ) VALUES(?,?,?)";
                $data = array("isi", $id_produkt, $name, $price);
            }else {
                $sql = "UPDATE variant_product SET name='$name',price='$price' WHERE id='$var_id'  ";
                $data = null;
            }
            $result = db_query($sql, $data);
            
        }
    }
    return $result; // This should be out of loop because it's will break the loop 

}

}

在一个foreach糟糕插件中有两个变量

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