Answer 1

const intersection = (...arg) => {
return arg[0].filter((item, index) => {
const res = arg[1].indexOf(item);
if(res > -1) {
arg[1].splice(res, 1);
}
return res > -1;
})
};

Answer 2

时间复杂度： O(n2)
let arr = [ 2, 3, 4, 44, 9, 4, 3, 2, 5, 1, 65, 2, 3, 6 ]
	for(let i = 0; i < arr.length; i++ ) {
		for(let j = i + 1; j < arr.length; j++) {
			if(arr[i] > arr[j]) {
				let beforeVar = arr[i]
				arr[i] = arr[j]
				arr[j] = beforeVar
			}
		}	
	}