爱冒险

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爱冒险 2025-02-20 09:27:02

极性坐标中的散点图与常规散点图相同,并且具有一个模式,因此可以通过设置线和字符串来显示它们。绳子位于顶部的中心。要调整当时的比例,请在布局更新中设置轴范围。

import plotly.graph_objects as go
from plotly.subplots import make_subplots

fig = go.Figure()

question= ["Q1", "Q2","Q3", "Q4"]

fig = make_subplots(rows=2, cols=2, specs=[[{'type': 'polar'}] * 2] * 2)

fig.add_trace(
    go.Scatterpolar(
        mode='lines+text',
        theta= question, #question
        r=[5.60, 5.62, 5.60, 5.59], 
        name = "Graph 1",
        text=[5.60, 5.62, 5.60, 5.59],
        textposition='top center'
    ),
    row=1,
    col=1,
)
    
fig.add_trace(
    go.Scatterpolar(
        mode='lines+text',
        theta= question, #question
        r=[5.60, 5.62, 5.60, 5.59], 
        name = "Graph2",
        text=[5.60, 5.62, 5.60, 5.59],
        textposition='top center'
    ),
    row=1,
    col=2,
)
fig.add_trace(
    go.Scatterpolar(
        mode='lines+text',
        theta= question, #question
        r=[5.60, 5.62, 5.60, 5.59], 
        name = "Graph3",
        text=[5.60, 5.62, 5.60, 5.59],
        textposition='top center'
    ),
    row=2,
    col=1,
)
    
fig.add_trace(
    go.Scatterpolar(
        mode='lines+text',
        theta= question, #question
        r=[5.60, 5.62, 5.60, 5.59],
        name = "Graph4",
        text=[5.60, 5.62, 5.60, 5.59],
        textposition='top center'
    ),
    row=2,
    col=2,
)

fig.update_layout(autosize=False,
                  height=600,
                  polar=dict(radialaxis=dict(range=[0,6])),
                  polar2=dict(radialaxis=dict(range=[0,6])),
                  polar3=dict(radialaxis=dict(range=[0,6])),
                  polar4=dict(radialaxis=dict(range=[0,6])),
)
fig.show()

Scatter plots in polar coordinates are the same as regular scatter plots and have a mode so that they can be displayed by setting the line and string. The string is positioned at the center of the top. To adjust the scale at that time, set the axis range in the layout update.

import plotly.graph_objects as go
from plotly.subplots import make_subplots

fig = go.Figure()

question= ["Q1", "Q2","Q3", "Q4"]

fig = make_subplots(rows=2, cols=2, specs=[[{'type': 'polar'}] * 2] * 2)

fig.add_trace(
    go.Scatterpolar(
        mode='lines+text',
        theta= question, #question
        r=[5.60, 5.62, 5.60, 5.59], 
        name = "Graph 1",
        text=[5.60, 5.62, 5.60, 5.59],
        textposition='top center'
    ),
    row=1,
    col=1,
)
    
fig.add_trace(
    go.Scatterpolar(
        mode='lines+text',
        theta= question, #question
        r=[5.60, 5.62, 5.60, 5.59], 
        name = "Graph2",
        text=[5.60, 5.62, 5.60, 5.59],
        textposition='top center'
    ),
    row=1,
    col=2,
)
fig.add_trace(
    go.Scatterpolar(
        mode='lines+text',
        theta= question, #question
        r=[5.60, 5.62, 5.60, 5.59], 
        name = "Graph3",
        text=[5.60, 5.62, 5.60, 5.59],
        textposition='top center'
    ),
    row=2,
    col=1,
)
    
fig.add_trace(
    go.Scatterpolar(
        mode='lines+text',
        theta= question, #question
        r=[5.60, 5.62, 5.60, 5.59],
        name = "Graph4",
        text=[5.60, 5.62, 5.60, 5.59],
        textposition='top center'
    ),
    row=2,
    col=2,
)

fig.update_layout(autosize=False,
                  height=600,
                  polar=dict(radialaxis=dict(range=[0,6])),
                  polar2=dict(radialaxis=dict(range=[0,6])),
                  polar3=dict(radialaxis=dict(range=[0,6])),
                  polar4=dict(radialaxis=dict(range=[0,6])),
)
fig.show()

enter image description here

在图中显示雷达图上的数据点

爱冒险 2025-02-20 05:47:09

frommultipartdata(builder.build()) fromResource(new filesystemsource(resource))

,您可以完全删除

MultipartBodyBuilder builder = new MultipartBodyBuilder();
builder.part("file", resource);

我知道我在这里迟到了,但是这个答案可以帮助某人

Replace fromMultipartData(builder.build()) with fromResource(new FileSystemResource(resource))

and you can completely remove

MultipartBodyBuilder builder = new MultipartBodyBuilder();
builder.part("file", resource);

I know i am late here, but this answer may assist someone

排除内容元数据添加到使用WebClient Springboot的文件上传的内容

爱冒险 2025-02-20 03:27:23

looks like there is no such possibility

you might construct it dynamically

you could grab a list of methods here:

octo 那个数组,或构造每个数组循环的方法:

// https://github.com/Automattic/mongoose/blob/c5893fa9f6d652d2bed08a52ad58f0f875e34bb4/lib/helpers/query/validOps.js
const validOps = [
    // Read
    'count',
    'countDocuments',
    'distinct',
    'estimatedDocumentCount',
    'find',
    'findOne',
    // Update
    'findOneAndReplace',
    'findOneAndUpdate',
    'replaceOne',
    'update',
    'updateMany',
    'updateOne',
    // Delete
    'deleteMany',
    'deleteOne',
    'findOneAndDelete',
    'findOneAndRemove',
    'remove'
]

mySchema.pre(validOps, function(next) {
    //...
})

// or        
for (const method of validOps) {
    mySchema.pre(method, function(next) {
        const query = this;
        console.log(`called the pre-${method} middleware and hello`);
    })
}

looks like there is no such possibility

you might construct it dynamically

you could grab a list of methods here: https://github.com/Automattic/mongoose/blob/c5893fa9f6d652d2bed08a52ad58f0f875e34bb4/lib/helpers/query/validOps.js

(I couldn't find them on the library)

and then pass that array, or construct each method with a loop:

// https://github.com/Automattic/mongoose/blob/c5893fa9f6d652d2bed08a52ad58f0f875e34bb4/lib/helpers/query/validOps.js
const validOps = [
    // Read
    'count',
    'countDocuments',
    'distinct',
    'estimatedDocumentCount',
    'find',
    'findOne',
    // Update
    'findOneAndReplace',
    'findOneAndUpdate',
    'replaceOne',
    'update',
    'updateMany',
    'updateOne',
    // Delete
    'deleteMany',
    'deleteOne',
    'findOneAndDelete',
    'findOneAndRemove',
    'remove'
]

mySchema.pre(validOps, function(next) {
    //...
})

// or        
for (const method of validOps) {
    mySchema.pre(method, function(next) {
        const query = this;
        console.log(`called the pre-${method} middleware and hello`);
    })
}

执行所有查询中间的中间件功能

爱冒险 2025-02-20 03:19:30

获取使用此方法锁定文件的流程:

static public List<Process> WhoIsLocking(string path)
{
    uint handle;
    string key = Guid.NewGuid().ToString();
    List<Process> processes = new List<Process>();
    int res = RmStartSession(out handle, 0, key);
    if (res != 0) throw new Exception("Could not begin restart session.  Unable to determine file locker.");
    try {
        const int ERROR_MORE_DATA = 234;
        uint pnProcInfoNeeded = 0,
             pnProcInfo = 0,
             lpdwRebootReasons = RmRebootReasonNone;
        string[] resources = new string[] { path }; // Just checking on one resource.
        res = RmRegisterResources(handle, (uint)resources.Length, resources, 0, null, 0, null);
        if (res != 0) throw new Exception("Could not register resource.");
        res = RmGetList(handle, out pnProcInfoNeeded, ref pnProcInfo, null, ref lpdwRebootReasons);
        if (res == ERROR_MORE_DATA) {
            // Create an array to store the process results
            RM_PROCESS_INFO[] processInfo = new RM_PROCESS_INFO[pnProcInfoNeeded];
            pnProcInfo = pnProcInfoNeeded;
            res = RmGetList(handle, out pnProcInfoNeeded, ref pnProcInfo, processInfo, ref lpdwRebootReasons);
            if (res == 0) {
                processes = new List<Process>((int)pnProcInfo);

                // Enumerate all of the results and add them to the 
                // list to be returned
                for (int i = 0; i < pnProcInfo; i++)
                    try {
                        processes.Add(Process.GetProcessById(processInfo[i].Process.dwProcessId));
                    }
                    // catch the error -- in case the process is no longer running
                    catch (ArgumentException) { }
            }
            else throw new Exception("Could not list processes locking resource.");
        }
        else if (res != 0) throw new Exception("Could not list processes locking resource. Failed to get size of result.");
    }
    finally
    {
        RmEndSession(handle);
    }
    return processes;
}

然后杀死:

List<Process> ps = WhoIsLocking("file path");
foreach(Process p in ps)
    p.Kill();

完成;

Get processes who locking file with this method:

static public List<Process> WhoIsLocking(string path)
{
    uint handle;
    string key = Guid.NewGuid().ToString();
    List<Process> processes = new List<Process>();
    int res = RmStartSession(out handle, 0, key);
    if (res != 0) throw new Exception("Could not begin restart session.  Unable to determine file locker.");
    try {
        const int ERROR_MORE_DATA = 234;
        uint pnProcInfoNeeded = 0,
             pnProcInfo = 0,
             lpdwRebootReasons = RmRebootReasonNone;
        string[] resources = new string[] { path }; // Just checking on one resource.
        res = RmRegisterResources(handle, (uint)resources.Length, resources, 0, null, 0, null);
        if (res != 0) throw new Exception("Could not register resource.");
        res = RmGetList(handle, out pnProcInfoNeeded, ref pnProcInfo, null, ref lpdwRebootReasons);
        if (res == ERROR_MORE_DATA) {
            // Create an array to store the process results
            RM_PROCESS_INFO[] processInfo = new RM_PROCESS_INFO[pnProcInfoNeeded];
            pnProcInfo = pnProcInfoNeeded;
            res = RmGetList(handle, out pnProcInfoNeeded, ref pnProcInfo, processInfo, ref lpdwRebootReasons);
            if (res == 0) {
                processes = new List<Process>((int)pnProcInfo);

                // Enumerate all of the results and add them to the 
                // list to be returned
                for (int i = 0; i < pnProcInfo; i++)
                    try {
                        processes.Add(Process.GetProcessById(processInfo[i].Process.dwProcessId));
                    }
                    // catch the error -- in case the process is no longer running
                    catch (ArgumentException) { }
            }
            else throw new Exception("Could not list processes locking resource.");
        }
        else if (res != 0) throw new Exception("Could not list processes locking resource. Failed to get size of result.");
    }
    finally
    {
        RmEndSession(handle);
    }
    return processes;
}

then kill that:

List<Process> ps = WhoIsLocking("file path");
foreach(Process p in ps)
    p.Kill();

Done;

C#writeline:该过程无法访问该文件,因为另一个过程正在使用该文件

爱冒险 2025-02-19 14:07:45

您可以组合 for_each fileset 为此:

data "archive_file" "from_s3" {

  for_each = fileset("${path.module}", "lambda_functions/*.py")
  type        = "zip"
  source_file = "${path.module}/${each.value}"
  output_path = "${path.module}/archived_files/${trimsuffix(trimprefix(each.value, "lambda_functions/"),".py")}.zip"

}

You can combine for_each and fileset for this:

data "archive_file" "from_s3" {

  for_each = fileset("${path.module}", "lambda_functions/*.py")
  type        = "zip"
  source_file = "${path.module}/${each.value}"
  output_path = "${path.module}/archived_files/${trimsuffix(trimprefix(each.value, "lambda_functions/"),".py")}.zip"

}

避免在目录Terraform中重复代码以归档文件

爱冒险 2025-02-19 13:37:15

您可以遍历第二个字典检查是否在第一个dict中,以决定是否必须求和或分配值:

dict1 = {
    "Elizabeth Alexandra Mary": 250000,
    "Barack Hussein Obama II": 1750000,
    "Zhang Aiqin": 1000,
    "Dean Craig Pelton": 1000000,
    }

dict2 = {
    "Christopher Larkin": 50000,
    "Eyal Shani": 5000,
    "Dean Craig Pelton": 2500000,
    "Sheldon Cooper": 15600000
    }

for i in dict2:
  if not i in dict1:
    dict1[i] = dict2[i]
  else:
    dict1[i] = dict1[i] + dict2[i]

print('Updated dictionary:')
print(dict1)

output:

Updated dictionary:
{'Elizabeth Alexandra Mary': 250000, 'Barack Hussein Obama II': 1750000, 'Zhang Aiqin': 1000, 'Dean Craig Pelton': 3500000, 'Christopher Larkin': 50000, 'Eyal Shani': 5000, 'Sheldon Cooper': 15600000}

You can traverse the second dictionary checking if each key element is in the first dict, to decide whether values have to be summed or assigned:

dict1 = {
    "Elizabeth Alexandra Mary": 250000,
    "Barack Hussein Obama II": 1750000,
    "Zhang Aiqin": 1000,
    "Dean Craig Pelton": 1000000,
    }

dict2 = {
    "Christopher Larkin": 50000,
    "Eyal Shani": 5000,
    "Dean Craig Pelton": 2500000,
    "Sheldon Cooper": 15600000
    }

for i in dict2:
  if not i in dict1:
    dict1[i] = dict2[i]
  else:
    dict1[i] = dict1[i] + dict2[i]

print('Updated dictionary:')
print(dict1)

Output:

Updated dictionary:
{'Elizabeth Alexandra Mary': 250000, 'Barack Hussein Obama II': 1750000, 'Zhang Aiqin': 1000, 'Dean Craig Pelton': 3500000, 'Christopher Larkin': 50000, 'Eyal Shani': 5000, 'Sheldon Cooper': 15600000}

合并2个字典,如果有共同的键,请尝试更新总和?

爱冒险 2025-02-18 22:21:46

您不需要自定义验证,

而是可以执行此操作

rulefor(a =&gt; a.portCode).notempty()。必须(w =&gt; w.tostring()。代码>

you don't need custom validation

you can do this instead

RuleFor(a => a.PortCode).NotEmpty().Must(w => w.ToString().Length < 10);

荧光验证验证数字最大长度

爱冒险 2025-02-18 20:56:15
function classDecorator<T extends { new(...args: any[]): {} }>(constructor: T) {
    return class extends constructor {
        newProperty = "new property";
        hello = "override";
    }
}
interface classInterface {
    newProperty: string;
    hello: string;
}

//trick
interface Greeter extends classInterface { };

@classDecorator
class Greeter {
    property = "property";
    hello: string;
    constructor(m: string) {
        this.hello = m;
    }
}
const b = new Greeter();
console.log(b.newProperty);

似乎我们可以使用接口技巧来解决问题。
技巧的参考:
https://stackoverflow.com/a/a/52373394/4831179

function classDecorator<T extends { new(...args: any[]): {} }>(constructor: T) {
    return class extends constructor {
        newProperty = "new property";
        hello = "override";
    }
}
interface classInterface {
    newProperty: string;
    hello: string;
}

//trick
interface Greeter extends classInterface { };

@classDecorator
class Greeter {
    property = "property";
    hello: string;
    constructor(m: string) {
        this.hello = m;
    }
}
const b = new Greeter();
console.log(b.newProperty);

Seems we can use interface trick to solve the problem.
Reference of the trick:
https://stackoverflow.com/a/52373394/4831179

通过打字稿中的装饰器向类添加属性

爱冒险 2025-02-18 20:31:39

events.participant 是一个数组

{events
        .filter((e) => e.participants.some((p) => p.email === currentProfile.email))
        .map((event) => (
          <>
            <Grid key={event._id} item xs={12} sm={6} md={4}>
            <Event event={event} setCurrentId2={setCurrentId2} />
          <>
        ))}

对于当前用户的电子邮件

events.participants is an array and you are doing events.participants.email wich is undefined, to do what you want:

{events
        .filter((e) => e.participants.some((p) => p.email === currentProfile.email))
        .map((event) => (
          <>
            <Grid key={event._id} item xs={12} sm={6} md={4}>
            <Event event={event} setCurrentId2={setCurrentId2} />
          <>
        ))}

With this, each event is iterating the partcipants field looking for the current user's email

反应:如何通过MongoDB中的一系列对象循环

爱冒险 2025-02-18 11:52:12

您正在尝试使用OpenAPI定义创建API。当您在此处提供URL时,将验证OpenAPI定义。请确保您在该URL中具有有效的OpenAPI定义。

如果您正在尝试创建一个没有OpenAPI定义的简单API,请使用“从头开始”选项启动并在此处提供后端URL。

You are trying to create an API using an OpenAPI definition. The OpenAPI definition is validated when you provide the URL here. Please make sure that you have a valid OpenAPI definition in that URL.

If you are a trying to create a simple API without an OpenAPI definition, please use the option Start from Scratch and provide your backend URL there.

在WSO2 API Manager中发布现有API

爱冒险 2025-02-18 08:25:52

就我而言,以某种方式使用水疗端口的过程变成了僵尸,我没有得到明显的错误。我只是一个“水疗代理还没有准备好。返回临时着陆页”的消息在代理方面。

但是

运行

之后

在 回到能够再次到达水疗中心。

我仅通过在项目文件夹上打开VS代码而始终看到这种行为。没有任何操作,它似乎只是开始在背景上运行水疗中心(?)

In my case, somehow a process that was using the SPA port became a zombie and I was not getting a clear error. I was just a "SPA proxy is not ready. Returning temporary landing page" message on the proxy side.

But after running

Get-Process -Id (Get-NetTCPConnection -LocalPort **port**).OwningProcess

and

taskkill /PID **process id** /F

the proxy went back to being able to reach the SPA again.

I am seeing this behaviour consistently just by opening VS Code on the project folder. Without running anything, it just seems to start running the SPA on the background (?)

可以为Net6&#x2B; t lauch spa代理React应用程序

爱冒险 2025-02-18 08:15:28

您可以在Kafka流中使用自定义TimeWindow实现。

cf https://github.com/confluentinc/kafka-streams-examples/blob/7.1.1-post/src/src/test/java/java/io/confluent/confluent/expluent/exmpleas/exampleass/streams/streams/windowwindow/dailow/dailytimewindows.java.java,java,java,java,java,java,java,java.java.java.java ic.java

有一张票可以将其纳入Kafka Streams,但需求并不高,因此从未完成。如果您想捡起它,那就太好了!

You can use a custom TimeWindow implementation in Kafka Streams.

Cf https://github.com/confluentinc/kafka-streams-examples/blob/7.1.1-post/src/test/java/io/confluent/examples/streams/window/DailyTimeWindows.java

There is a ticket to add it natively to Kafka Streams, but demand was not super high and so it was never done. If you want to pick it up, it would be great!

如何将偏移窗口应用到翻滚窗口,以延迟Windows&lt; timeWindow&gt;在Kafka流中

爱冒险 2025-02-18 03:59:14

我发现了。如果我登录所有帐户,则可以使用。

I figured it out. If I sign out of all accounts, it works.

为什么Microsoft Edge显示“状态:失败”当Chrome每次工作时,在Google Apps脚本中使用客户端服务器函数集成时?

爱冒险 2025-02-17 08:58:45

我创建了一个Bootstrap 5迁移工具脚本,该脚本扫描文件夹中的所有页面/模板,并用Bootstrap 5类代替所有Bootstrap 4类。它还用实用程序类替代了弃用的组件(例如.jumbotron和.media),将所有数据属性(例如数据toggle和data-target)重命名为新名称,并更新所有Bootstrap v4 cdn链接(JSDELIVR.NET,JSDELIVR.NET,,,,,,,JSDELIVR.NET,,,,,,,JSDELIVR.NET,,,,,,,地名称,,,地位,。 unpkg.com和stackpath.bootstrapcdn.com)到最新版本的Bootstrap V5。

https://github.com/coliff/coliff/bootstrap-5-migrate-tool

I've created a Bootstrap 5 Migrate Tool script which scans all pages/templates in a folder and replaces all the Bootstrap 4 classes with Bootstrap 5 classes. It also replaces deprecated components (such as .jumbotron and .media) with utility classes, renames all the data attributes (such as data-toggle and data-target) to the new names and updates all Bootstrap v4 CDN links (jsdelivr.net, unpkg.com and stackpath.bootstrapcdn.com) to latest version of Bootstrap v5.

https://github.com/coliff/bootstrap-5-migrate-tool

如何升级我的旧项目的引导版本?

爱冒险 2025-02-17 05:27:04
import React from 'react';
import backgroundImage from './your-image-path.jpg';

function YourComponent() {
  const style = {
    backgroundImage: `url(${backgroundImage})`,
    backgroundRepeat: 'no-repeat',
    backgroundSize: 'cover',
  };

  return (
    <div style={style}>
      {/* your page content goes here */}
    </div>
  );
}

export default YourComponent;
import React from 'react';
import backgroundImage from './your-image-path.jpg';

function YourComponent() {
  const style = {
    backgroundImage: `url(${backgroundImage})`,
    backgroundRepeat: 'no-repeat',
    backgroundSize: 'cover',
  };

  return (
    <div style={style}>
      {/* your page content goes here */}
    </div>
  );
}

export default YourComponent;

我想为此页面渲染一个背景图像,不是整个应用程序

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