半城柳色半声笛

文章 评论 浏览 26

半城柳色半声笛 2024-12-28 02:37:27

CSS 不能做到这一点(或类似的事情)

CSS cannot do this (or anything like it)

CSS 指定 < >

半城柳色半声笛 2024-12-28 02:00:49

看看 django-denorm。它允许您在数据库中维护计算值(然后您可以使用它来有效排序),而只需花费单个方法装饰器的成本。

Have a look at django-denorm. It lets you maintain calculated values in the database (which you can then use to sort efficiently) for the cost of a single method decorator.

通过 @property 对 Django 查询集进行排序

半城柳色半声笛 2024-12-27 15:53:39

问题出在第一行的%\n。请注意,% 是格式字符串中的特殊字符,表示后面有格式说明符。 % 后面的 \n 不是有效的格式说明符。

如果要打印百分号,请在格式字符串中将其加倍: %%

如果要打印换行符,则使用 %n,而不是 %\n

What's wrong is the %\n in the first line. Note that the % is a special character in a format string that indicates that a format specifier follows. The \n after the % is not a valid format specifier.

If you wanted to print a percent sign, then double it in the format string: %%

If you wanted to print a newline, then use %n, not %\n.

java.util.UnknownFormatConversionException:

半城柳色半声笛 2024-12-27 13:33:49
var blink = function(){
    $('#blinker').toggle();
};
var bl = setInterval(blink, 800);

$("#stopBlink").click(function(){
   clearInterval(bl); 
});
var blink = function(){
    $('#blinker').toggle();
};
var bl = setInterval(blink, 800);

$("#stopBlink").click(function(){
   clearInterval(bl); 
});

停止眨眼事件

半城柳色半声笛 2024-12-27 10:16:36

使用 memset 代替。这只会使缓冲区无效,但当变量超出范围时,分配的内存将如何从堆栈中释放。

memset (name,'\0',sizeof(name));

Use memset instead. This would just nullify the buffer but the memory allocated would any how gets deallocated from stack when the variable goes out of scope.

memset (name,'\0',sizeof(name));

C 中清空字符串的最佳方法是什么?

半城柳色半声笛 2024-12-27 04:22:10

这是您要找的吗?

String.prototype.parseUsername = function(userName) {
    userName = this.replace(/[@]+[A-Za-z0-9-_]+/g, userName.replace("@", ""));
    return (function(u) {
        var twitter_link = document.createElement("a");
        twitter_link.href = "http://www.twitter.com/"+u
        twitter_link.target = "_blank"

        console.log(twitter_link)
        return twitter_link;

    })(userName);
  };

Is this what you're looking for?

String.prototype.parseUsername = function(userName) {
    userName = this.replace(/[@]+[A-Za-z0-9-_]+/g, userName.replace("@", ""));
    return (function(u) {
        var twitter_link = document.createElement("a");
        twitter_link.href = "http://www.twitter.com/"+u
        twitter_link.target = "_blank"

        console.log(twitter_link)
        return twitter_link;

    })(userName);
  };

函数返回不是我所期望的

半城柳色半声笛 2024-12-27 04:19:46

在计算如此大的数字的 Collat​​z 链时,long int 会溢出。我认为这就是你的递归函数出错的原因。尝试将 c1 参数更改为 64 位类型,例如 long long

我刚刚对此进行了测试,当您达到值 704511 时,链范围高达 56991483520。顺便说一句,这是 Project Euler 问题 14。

编辑:

将数组 totalcounter[] 的声明移到main() 函数使其成为全局的。对于堆栈上的自动存储而言,它太大了(~4MB)。其他替代方案是动态分配数组或使用 std::vector 。

此处的代码示例。

In computing the Collatz chain for such large numbers you are overflowing a long int. I assume that's why your recursive function is faulting. Try changing your c1 parameter to a 64-bit type such as long long.

I just tested this and when you reach the value 704511 the chain ranges as high as 56991483520. By the way, this is Project Euler problem 14.

Edit:

Move your declaration of the array totalcounter[] outside the main() function to make it a global. It's simply too large (~4MB) for automatic storage on the stack. Other alternatives would be to dynamically allocate the array or use std::vector.

Example of your code working here.

C/C++ 100 万数组中的 Stackoverflow 错误

半城柳色半声笛 2024-12-27 00:48:14

有一些事情可能会出错,但我敢打赌,您正在 IIS7 上运行,并且它的默认设置会导致它重写错误。尝试使用 TrySkipIisCustomErrors 属性和 属性href="http://msdn.microsoft.com/en-us/library/ms690497%28v=vs.90%29.aspx" rel="nofollow">httpErrors 配置设置。

There's a few things that could be going wrong, but I'd be prepared to bet that you're running on IIS7 and its defaults are causing it to rewrite the error. Try the TrySkipIisCustomErrors property and the existingResponse attribute on the httpErrors configuration setting.

如何使用 C# / ASP.Net 将错误传回responseText

半城柳色半声笛 2024-12-26 23:29:02

我通过添加 200 毫秒的等待块来减慢 NXT 的速度来修复此问题。这很有效,看起来砖头有点超前了。

I fixed this by adding a 200ms wait block to slow the NXT down. This worked, it seemed that the brick was getting ahead of itself.

为什么该程序在针对计算机而不是 NXT 时可以在 LabView 中运行?

半城柳色半声笛 2024-12-26 19:03:50

您可以将您的“聚合根”表示为演员。当您想要改变聚合根时,您可以从请求处理参与者发送一条消息来执行此操作。您还可以拥有一个中间代理参与者,将消息转发给正确的参与者,并通过实例化代表按需数据的参与者并根据需要停止它们来管理聚合根参与者的缓存(按 id )如果您需要协调表示数据的参与者之间的突变,则需要 STM。

You can represent your "aggregate root" as an actor. When you want to mutate the aggregate root you can send a message to do so from your request handling actor. You can also have an intermediary broker actor that forwards messages to the correct actor and manages a cache of aggregate root actors ( by id ) by instantiating an actor representing the data on demand and stoping them as needed. STM will be needed if you need to coordinate a mutation across actors that represent data.

处理应用程序级并发 - 我有什么选择?

半城柳色半声笛 2024-12-26 18:50:34

android:配置更改
列出活动将自行处理的配置更改。当运行时发生配置更改时,默认情况下 Activity 会关闭并重新启动,但使用此属性声明配置将阻止 Activity 重新启动。相反,该活动保持运行状态并调用其 onConfigurationChanged() 方法。

因此,如果您只需要管理旋转,键盘标志就没用了,因为文档说:

“键盘”键盘类型已更改 - 例如,用户插入了外部键盘

事件发生时将调用 onConfigurationChanged() 回调。因此,您的自定义代码位于回调 self 内部是正确的。

android:configChanges
Lists configuration changes that the activity will handle itself. When a configuration change occurs at runtime, the activity is shut down and restarted by default, but declaring a configuration with this attribute will prevent the activity from being restarted. Instead, the activity remains running and its onConfigurationChanged() method is called.

So if you need to manage only the rotation, the keyboard flag is useless since documentation says:

"keyboard" The keyboard type has changed — for example, the user has plugged in an external keyboard

the onConfigurationChanged() callback is called when the event occurs. So it is correct that your custom code is inside the callback self.

确定方向时应该如何使用 android:configChanges

半城柳色半声笛 2024-12-26 14:44:20

您可以设置g:netrw_chgwin变量以使netrw在特定窗口中打开文件。请参阅:

:h netrw-C

因此,要使当前窗口成为 netrw 的目标,请在该窗口中键入以下内容:

:let g:netrw_chgwin = winnr()

另一种方法是在目标窗口中启动 netrw (:E),点击 C< /code> 选择它进行编辑并使用 关闭 netrw。

You can set the g:netrw_chgwin variable to make netrw open the files in a specific window. See:

:h netrw-C

So to make the current window the target of netrw type this while you're in that window:

:let g:netrw_chgwin = winnr()

Another way is to launch netrw in the target window (:E), hit C to select it for editing and close netrw with <c-o>.

在指定的分割中打开 .netrw 文件

半城柳色半声笛 2024-12-26 13:09:30

该问题很可能是由于这些表是动态添加到页面的这一事实引起的。 tablefilter.js 正在查看作为原始文件一部分的现有 html。我建议将 testphp.php 选项移动到隐藏的 3 个不同的 div 中。这样,选项就已经是 html 的一部分了。然后,当在下拉选项中选择一个时,只需更改要显示的所选 div 的样式即可。这将避免您必须重写 tablefilter.js 的部分内容。

PS 你的 php.ini 中不需要那么多 echo。每桌一个就够了。哈哈。

The problem is most likely arising from the fact that these tables are dynamically added to the page. The tablefilter.js is looking through your existing html that is part of the original file. I recommend just moving the testphp.php options into 3 different divs that are hidden. This way, the options are already part of the html. Then, when one is selected in your drop down choices, just simply change the style of the selected div to show. This will avoid you having to rewrite parts of tablefilter.js.

P.S. you don't need so many echo's in your php. One will do for each table. haha.

为什么我的动态表没有过滤功能?

半城柳色半声笛 2024-12-26 11:50:33

这里有两种类型的占位符,可重新选择和隐藏:

演示: http://jsfiddle.net/lachlan/FuNmc/

可重新选择占位符:

<select>
    <option value="" selected>Please select</option>
    <option value="1">Item 1</option>
    <option value="2">Item 2</option>
    <option value="3">Item 3</option>
</select>

隐藏占位符:

<select class="empty">
    <option value="" selected disabled>Please select</option>
    <option value="1">Item 1</option>
    <option value="2">Item 2</option>
    <option value="3">Item 3</option>
</select>

用于更改第一项颜色的 CSS:

select option { color: black; }
select option:first-child { color: grey; }
select.empty { color: grey; }
/* Hidden placeholder */
select option[disabled]:first-child { display: none; }

以及一些用于在选择后切换字体颜色的 jQuery:

// Applies to all select boxes that have no value for their first option
$("select:has(option[value=]:first-child)").on('change', function() {
    $(this).toggleClass("empty", $.inArray($(this).val(), ['', null]) >= 0);
}).trigger('change');

灵感:
https://stackoverflow.com/a/5805194/1196148 - 可重新选择的占位符
https://stackoverflow.com/a/8442831/1196148 - 隐藏占位符

Here's two types of placeholder, re-selectable and hidden:

Demo: http://jsfiddle.net/lachlan/FuNmc/

Re-selectable placeholder:

<select>
    <option value="" selected>Please select</option>
    <option value="1">Item 1</option>
    <option value="2">Item 2</option>
    <option value="3">Item 3</option>
</select>

Hidden placeholder:

<select class="empty">
    <option value="" selected disabled>Please select</option>
    <option value="1">Item 1</option>
    <option value="2">Item 2</option>
    <option value="3">Item 3</option>
</select>

CSS to change the colour of the first item:

select option { color: black; }
select option:first-child { color: grey; }
select.empty { color: grey; }
/* Hidden placeholder */
select option[disabled]:first-child { display: none; }

And a little jQuery to toggle the font-color after selection:

// Applies to all select boxes that have no value for their first option
$("select:has(option[value=]:first-child)").on('change', function() {
    $(this).toggleClass("empty", $.inArray($(this).val(), ['', null]) >= 0);
}).trigger('change');

Inspiration:
https://stackoverflow.com/a/5805194/1196148 - re-selectable placeholder
https://stackoverflow.com/a/8442831/1196148 - hidden placeholder

“select”标签的占位符?

半城柳色半声笛 2024-12-26 09:50:37

如果没有正确的设置,on(...) 不会订阅页面上尚未出现的事件。要执行您想要的操作,您应该尝试以下操作:

$(document).on("change", "#subcategory_id", function(){
    alert( 'Success!' );
});

为了提高效率,您应该将 $(document) 替换为您知道在执行此代码时将出现在页面上的元素的最接近的父元素被称为。

on(...) won't subscribe to events that aren't on the page yet without the proper setup. To do what you want, you should try the following:

$(document).on("change", "#subcategory_id", function(){
    alert( 'Success!' );
});

To make this more efficient, you should replace $(document) with the closest parent of the element that you know will be on the page when this code is called.

jQuery 无法使用 .on() 将事件绑定到 AJAX 加载的元素

更多

推荐作者

α

文章 0 评论 0

メ斷腸人バ

文章 0 评论 0

人间不值得

文章 0 评论 0

往事风中埋

文章 0 评论 0

别理我

文章 0 评论 0

更多

友情链接

    我们使用 Cookies 和其他技术来定制您的体验包括您的登录状态等。通过阅读我们的 隐私政策 了解更多相关信息。 单击 接受 或继续使用网站,即表示您同意使用 Cookies 和您的相关数据。
    原文