无所的.畏惧

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无所的.畏惧 2025-02-20 10:27:51

以下仅适用于年度,但是您可以使用适当的案例逻辑进行扩展:

with 
  t0 as (select '2020-01-07' as Start_Date, 12 as No_of_Months, 120 as Amount, 'Annual' as Frequency),
  t1 as (select row_number() over(order by 0) as i from table(generator(rowcount => 12)))
select dateadd("months", i-1, Start_Date) as Start_Date, t0.Amount/12 as Amount
from t0 cross join t1
where i-1 < 12

基于此答案

The following only accommodates Annual, but you can expand it with appropriate CASE logic:

with 
  t0 as (select '2020-01-07' as Start_Date, 12 as No_of_Months, 120 as Amount, 'Annual' as Frequency),
  t1 as (select row_number() over(order by 0) as i from table(generator(rowcount => 12)))
select dateadd("months", i-1, Start_Date) as Start_Date, t0.Amount/12 as Amount
from t0 cross join t1
where i-1 < 12

Based on an idea at this answer

如何在12个月度记录中拆分年度记录

无所的.畏惧 2025-02-20 04:44:14

这似乎是一个错误。

在Google的几年前。 google代表在a

当前的方法表。getNamedRanges()返回表上的每个命名范围(有效和无效)(...)以示例性这种行为我创建了一个带有三个范围的新表格,我删除了两个列的列这些范围使它们无效。然后,我根据所述解决方案编写了此代码:

  //(某些代码和某些日志)
 

无效的名为范围与有效的范围很容易区分。请尝试复制这种方法,如果它无助于分享您如何创建无效的范围和使用的代码,以便我可以继续调查此方法。

您可以转到代码示例的线程,但从本质上讲,他表明 getNamedRanges()确实返回了“无效”范围, #ref error。这不是完全错误的,只是他通过删除列而不是工作表进行了测试。鉴于他的解释,看来该方法应列出所有无效的范围,以便可以处理它们,因此它不会在删除板中列出范围的事实似乎确实是一种监督或错误。不幸的是,该线程死亡,因为之后几乎没有活动。

我还尝试了其他一些可能的解决方法,没有成功:

我的建议是转到 earke tracker 一个href =“ https://issuetracker.google.com/issues/new?component = 191608&amp;无论哪种方式,修复可能需要一段时间,因此与此同时,您可能必须在代码中考虑此问题,并在删除表格之前删除命名范围。

This appears to be a bug.

There's a report of this same issue in Google's issue tracker from a few years back. A Google rep replied to this thread in a comment stating the following:

Currently the method Sheet.getNamedRanges() returns every named range on the Sheet (both valid and invalid) (...) To exemplarise this behaviour I created a new Sheet with three ranges, and I deleted the columns of two of those ranges to make them invalid. Then I wrote this code based on the described solution:

//(Some code and some logs)

The invalid named ranges are easily differentiated from the valid ones. Please, try to replicate this approach and come back if it doesn't help sharing how you created the invalid ranges and the code used, so I could continue investigating this.

You can go to the thread for the code sample, but essentially he showed that getNamedRanges() does return "invalid" ranges with a #REF error. This is not entirely wrong, except that he tested it by deleting the column rather than the worksheet. Given his explanation it seems that it is expected that the method should list all invalid ranges so they can be handled, so the fact that it doesn't list the ranges in deleted sheets does appear to be an oversight or bug. Unfortunately, the thread died since there was little activity afterwards.

I also tried a few other possible workarounds with no success:

  • The getSheets() method doesn't seem to keep track of deleted sheets to see if we can directly reference them to search for the ranges.
  • getRangeByName() also returns null even if you want to directly search by name.
  • As suggested by TheMaster's comment I tried the Advanced service by running Sheets.Spreadsheets.get(), and it also only listed the namedRanges that were not in deleted sheets. Given that this is pretty much the same as the "pure" API calls it seems that it's not only an Apps Script issue. You can also test it in Google's APIs Explorer.

My suggestion would be to go to the issue tracker to try to reopen the bug or maybe just file a new report which may get it quicker attention. Either way it may take a while to fix so in the meantime you'll probably have to account for this issue in your code and delete the named ranges before deleting a Sheet.

电子表格。getnamedranges()未返回已删除工作表中定义的名称列表

无所的.畏惧 2025-02-20 03:50:32
  1. 将IDE与集成调试器(如Pycharm)一起使用。
  2. 在产生错误调试的代码线处设置一个断点
  3. - 它将在断点停止,然后您将看到所有变量
  1. Use an IDE with an integrated debugger, like PyCharm.
  2. Set a break point at the line of code which produces the error
  3. Debug the program - it will stop at the break point and then you will see all the variables

如何确定在库中引起typeError的变量的值?

无所的.畏惧 2025-02-19 19:35:22

就我而言,现在使用 UNNEX 现在起作用。结果看起来像这样:

INSERT INTO setting_sales_channel (sales_channel_id)
SELECT UNHEX(sales_channel_id) from setting;

In my case it worked when using UNHEX now. The result looked like this:

INSERT INTO setting_sales_channel (sales_channel_id)
SELECT UNHEX(sales_channel_id) from setting;

从MySQL中从Varchar转换为二进制(16)?

无所的.畏惧 2025-02-19 16:41:01

删除SinglechildScrollview,然后用扩展的小部件包装内列。

Remove SingleChildScrollView and wrap the inner column with an expanded widget.

在列中心显示小部件

无所的.畏惧 2025-02-19 08:43:33

昨天我遇到了这个问题,很可能是同一回事。

我禁用了 websecurityConfigurerAdapter 的类中的CSRF,以使其工作。如果您要进入生产,则可能应该使其启用。

我的 websecurityconfig 类:

@Configuration
@EnableWebSecurity
public class WebSecurityConfig extends WebSecurityConfigurerAdapter {
    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http
                .csrf().disable()
                .authorizeRequests()
                .antMatchers("/").permitAll();
    }
}

我不完全了解CSRF保护是如何保护的,因此如果您尝试从浏览器登录,可能会有问题。输出 .csrf()。disable()

I had this problem yesterday, it's most likely the same thing.

I disabled csrf in the class that extends WebSecurityConfigurerAdapter to get it to work. If you're moving into production, you should probably leave it enabled.

My WebSecurityConfig class:

@Configuration
@EnableWebSecurity
public class WebSecurityConfig extends WebSecurityConfigurerAdapter {
    @Override
    protected void configure(HttpSecurity http) throws Exception {
        http
                .csrf().disable()
                .authorizeRequests()
                .antMatchers("/").permitAll();
    }
}

I don't fully understand how the csrf protection so there might be issues if you try to log in from a browser. Uncomment out the .csrf().disable() when you want to run in from a browser

Springboot在网络上工作,但在邮递员中不起作用吗?

无所的.畏惧 2025-02-19 05:25:59

假设 wall_area 是一个浮点号,它很简单:

gallons_paint = wall_area/350

Assuming wall_area is a floating point number, it's simple:

gallons_paint = wall_area / 350

Zybook-油漆挑战python

无所的.畏惧 2025-02-19 01:03:02

就我而言,我通过为Google BigQuery客户端提供证书来解决问题。
检查下面的代码。

# https://googleapis.dev/python/google-api-core/latest/auth.html
from google.oauth2 import service_account

json_account_info = #{service_account_info}
credentials = service_account.Credentials.from_service_account_info(
    json_account_info)
...

from google.cloud import bigquery
client = bigquery.Client(credentials=credentials)

sql="select * from austin_311.311_service_requests"
query_job=client.query(sql)

In my case, I solved the problem by offering credentials for the google BigQuery Client.
Check codes below.

# https://googleapis.dev/python/google-api-core/latest/auth.html
from google.oauth2 import service_account

json_account_info = #{service_account_info}
credentials = service_account.Credentials.from_service_account_info(
    json_account_info)
...

from google.cloud import bigquery
client = bigquery.Client(credentials=credentials)

sql="select * from austin_311.311_service_requests"
query_job=client.query(sql)

连接到Python的BigQuery:ProjectID和DataSetID必须是非空的

无所的.畏惧 2025-02-18 03:46:35

使用 > with dict coldection pracsions

In [1664]: video_items_df['breakdown'] = video_items_df.breakdown.apply(lambda x: {k: v or '' for (k,v) in x[0].items()})

In [1665]: video_items_df.breakdown[0]
Out[1665]: 
{'platform': 'facebook',
 'total': 18463,
 'likes': 9436,
 'shares': 5581,
 'comments': 608,
 'tweets': '',
 'favorites': '',
 'hahas': 1049,
 'wows': 170,
 'loves': 1554,
 'sads': 44,
 'angrys': 21}

Use df.apply with dict comprehension:

In [1664]: video_items_df['breakdown'] = video_items_df.breakdown.apply(lambda x: {k: v or '' for (k,v) in x[0].items()})

In [1665]: video_items_df.breakdown[0]
Out[1665]: 
{'platform': 'facebook',
 'total': 18463,
 'likes': 9436,
 'shares': 5581,
 'comments': 608,
 'tweets': '',
 'favorites': '',
 'hahas': 1049,
 'wows': 170,
 'loves': 1554,
 'sads': 44,
 'angrys': 21}

熊猫 - 列嵌套无值,转换为空字符串

无所的.畏惧 2025-02-17 06:22:58

Ampiz635 答案是正确的。您需要添加一个构造函数和 toString 的覆盖。

record

You can get both of those by defining your class as a

在记录中,编译器隐含地创建了构造函数,getters, equals &amp; HashCode toString

顺便说一句,您应该比 data 设计一个更具描述性的类名。

record Data ( String id , String code ) {}

仅供参考,可以在方法中本地定义记录,也可以定义在类中嵌套,也可以在其自己的 .java 文件中为自己的类定义。

示例用法。

String[] parts = line.split( " " ) ;
Data d = new Data( parts[0] , parts[1] ) ;
results.add( d ) ;

The Answer by admiz635 is correct. You need to add a constructor and an override of toString.

record

You can get both of those by defining your class as a record in Java 16+. A record is appropriate when the main purpose of your class is to communicate data transparently and immutably.

In a record, the compiler implicitly creates the constructor, getters, equals & hashCode, and toString.

By the way, you should devise a more descriptive class name than Data.

record Data ( String id , String code ) {}

FYI, a record can be defined locally within a method, or defined nested within a class, or as its own class in its own .java file.

Example usage.

String[] parts = line.split( " " ) ;
Data d = new Data( parts[0] , parts[1] ) ;
results.add( d ) ;

如何将字符串值映射到特定的数据结构Java

无所的.畏惧 2025-02-17 06:19:23

在您的API响应中,有一个画廊对象列表,因此您必须穿越所有内容。

User.fromJson(Map<String, dynamic> json) {
    json = json['data'];
    id = json['id'];
    pictureUrl = json['picture_url'];
    emailConfirmed = json['email_confirmed'];
    if (json['gallery'] != null) {
      gallery = <Gallery>[];
      json['gallery'].forEach((v) {
        gallery!.add(new Gallery.fromJson(v));
      });
    }
    updatedAt = json['updated_at'];
    createdAt = json['created_at'];
  }

有多种工具可以帮助您创建该.fromjson方法,例如 this 。在那里粘贴您的JSON,它将为您生成Dart代码,真的对我有帮助。

用法应该这样:

User user = User.fromJson(yourApiResponseJson);
print(user.id);
print(user.gallery); //prints entire list of gallery
print(user.gallery.first.url); //prints only first object url

In your API response, there is a list of gallery objects therefore you have to traverse through all of them.

User.fromJson(Map<String, dynamic> json) {
    json = json['data'];
    id = json['id'];
    pictureUrl = json['picture_url'];
    emailConfirmed = json['email_confirmed'];
    if (json['gallery'] != null) {
      gallery = <Gallery>[];
      json['gallery'].forEach((v) {
        gallery!.add(new Gallery.fromJson(v));
      });
    }
    updatedAt = json['updated_at'];
    createdAt = json['created_at'];
  }

There are multiple tools that helps you create that .fromJson method, like this. Paste your json there and it will generate dart code for you, really helps me.

The usage should like this:

User user = User.fromJson(yourApiResponseJson);
print(user.id);
print(user.gallery); //prints entire list of gallery
print(user.gallery.first.url); //prints only first object url

从API获取数据时,我遇到了一个错误,如果颤抖,我应该如何获取数据?

无所的.畏惧 2025-02-17 04:32:07

从iD中选择来自table_name组的sum(量)

SELECT SUM(AMOUNT) from table_name GROUP BY ID, TYPE

显示线从同一列中过滤的不同值

无所的.畏惧 2025-02-16 19:18:35

启动仅被调用一次,当对象实例化时,您应该将代码移至更新()或更好地使用InputField的valuechanged事件:

void Start(){
    convertInput.onValueChanged.AddListener(HandleValueChanged);
}

void HandleValueChanged(string newValue){
    int d = int.Parse("0"+newValue);
}

Start is called only once, when the object is instantiated, you should move that code to Update() or better use onValueChanged event from InputField like that:

void Start(){
    convertInput.onValueChanged.AddListener(HandleValueChanged);
}

void HandleValueChanged(string newValue){
    int d = int.Parse("0"+newValue);
}

int从inputfield文本转换在输入字段中的数字时未更新

无所的.畏惧 2025-02-16 13:56:40

使用工作表和嵌套迭代的替代方案:

DROP TABLE IF EXISTS #Work;

SELECT 
    TT.*, 
    jsn = CONVERT(nvarchar(max), NULL) 
INTO #Work 
FROM #tTree AS TT;

CREATE UNIQUE CLUSTERED INDEX cuq ON #Work (depth, parentId, id);
DECLARE @depth integer = (SELECT MAX(TT.depth) FROM #tTree AS TT);

WHILE @depth >= 1
BEGIN
    UPDATE W
    SET W.jsn =
        (
            SELECT 
                W.*, 
                children = 
                    JSON_QUERY
                    (
                        (
                            SELECT 
                                N'[' + 
                                STRING_AGG(W2.jsn, N',') 
                                    WITHIN GROUP (ORDER BY W2.id) + 
                                N']'
                            FROM #Work AS W2
                            WHERE 
                                W2.depth = @depth + 1
                                AND W2.parentId = W.id
                        )
                    )
            FOR JSON PATH, WITHOUT_ARRAY_WRAPPER
        )
    FROM #Work AS W
    WHERE 
        W.depth = @depth
        AND W.jsn IS NULL;

    SET @depth -= 1;    
END;
SELECT 
    N'[' + 
    STRING_AGG(W.jsn, N',') 
        WITHIN GROUP (ORDER BY W.id) + 
    N']'
FROM #Work AS W
WHERE 
    W.depth = 1;

An alternative using a work table and nested iteration:

DROP TABLE IF EXISTS #Work;

SELECT 
    TT.*, 
    jsn = CONVERT(nvarchar(max), NULL) 
INTO #Work 
FROM #tTree AS TT;

CREATE UNIQUE CLUSTERED INDEX cuq ON #Work (depth, parentId, id);
DECLARE @depth integer = (SELECT MAX(TT.depth) FROM #tTree AS TT);

WHILE @depth >= 1
BEGIN
    UPDATE W
    SET W.jsn =
        (
            SELECT 
                W.*, 
                children = 
                    JSON_QUERY
                    (
                        (
                            SELECT 
                                N'[' + 
                                STRING_AGG(W2.jsn, N',') 
                                    WITHIN GROUP (ORDER BY W2.id) + 
                                N']'
                            FROM #Work AS W2
                            WHERE 
                                W2.depth = @depth + 1
                                AND W2.parentId = W.id
                        )
                    )
            FOR JSON PATH, WITHOUT_ARRAY_WRAPPER
        )
    FROM #Work AS W
    WHERE 
        W.depth = @depth
        AND W.jsn IS NULL;

    SET @depth -= 1;    
END;
SELECT 
    N'[' + 
    STRING_AGG(W.jsn, N',') 
        WITHIN GROUP (ORDER BY W.id) + 
    N']'
FROM #Work AS W
WHERE 
    W.depth = 1;

db<>fiddle

在SQL Server(Web树的结构)中创建带子女的JSON

无所的.畏惧 2025-02-15 23:29:40

在你的情况下

l = []
for record in data:
    doc = textacy.make_spacy_doc(record, lang="en_core_web_sm")
    l.append(list(textacy.extract.triples.direct_quotations(doc)))

out = pd.Series(l).explode().apply(pd.Series)

In your case

l = []
for record in data:
    doc = textacy.make_spacy_doc(record, lang="en_core_web_sm")
    l.append(list(textacy.extract.triples.direct_quotations(doc)))

out = pd.Series(l).explode().apply(pd.Series)

输出到熊猫数据框架

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