LazyMan('Tony')
// Hi I am Tony
LazyMan('Tony')
.sleep(10)
.eat('lunch')
// Hi I am Tony
// 等待了10秒...
// I am eating lunch
LazyMan('Tony')
.eat('lunch')
.sleep(10)
.eat('dinner')
// Hi I am Tony
// I am eating lunch
// 等待了10秒...
// I am eating diner
LazyMan('Tony')
.eat('lunch')
.eat('dinner')
.sleepFirst(5)
.sleep(10)
.eat('junk food')
// Hi I am Tony
// 等待了5秒...
// I am eating lunch
// I am eating dinner
// 等待了10秒...
// I am eating junk food
下面是实现
let man = {
queue: []
}
function LazyMan(name) {
console.log(`Hi I am ${name}`)
setTimeout(() => {
man.next()
}, 0)
return man
}
man.eat = food => {
man.queue.push(() => {
console.log(`I am eating ${food}`)
man.next()
})
return man
}
man.sleep = timeout => {
man.queue.push(() => {
setTimeout(() => {
console.log(`等待了${timeout}秒`)
man.next()
}, timeout * 1000)
})
return man
}
man.sleepFirst = timeout => {
man.queue.unshift(() => {
setTimeout(() => {
console.log(`等待了${timeout}秒`)
man.next()
}, timeout * 1000)
})
return man
}
man.next = () => {
if (man.queue.length > 0) {
man.queue.shift()()
}
}
不用类的实现,js里基本用类实现的用对象也可以实现。
下面是实现
第 56 题:要求设计 LazyMan 类,实现以下功能