埖埖迣鎅

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埖埖迣鎅 2025-02-21 00:40:07

您可以在宽度CSS内使用100VW
像这样

width:100vw

You can use 100vw inside your width css
Like this

width:100vw

我需要在我的部分组件中的框组件才能是全宽度

埖埖迣鎅 2025-02-20 18:30:52

我将端口设置更改为8443:8443,并将 /NIFI添加到URL,然后开始工作

I changed the port setting to 8443:8443 and added /nifi to the URL and it started working

NIFI容器运行但无法通过UI访问

埖埖迣鎅 2025-02-20 17:05:43

我尝试此示例:

QPushButton *button = new QPushButton();
button->setText("Clicke me ");
ui->gridLayout->addWidget(button);

connect(button,&QPushButton::clicked,this,[](){
qDebug()<<"button is clicked";
}, Qt::UniqueConnection);

您在Connect中写的内容是错误的,因为您应该遵循此样式:

connect(object,SIGNAL(mySig()), this,SLOT(mySlot())),Qt::QueuedConnection); 

您不能同时使用两个连接

“在此处输入图像说明”

来自 qt :: ConnectionType for qt :: iniqueConnection

这是一个可以与以上任何一个结合的标志
连接类型,使用位或。当qt :: iniqueConnection是
设置,qObject ::连接()如果连接已经存在
(即,如果同一信号已经连接到同一插槽的
同一对对象)。该标志是在QT 4.6中引入的。

注意到它是在QT 4.6中引入的,它说,如果连接已经存在 qobject :: connect() 将失败

当我尝试

  connect(button,&QPushButton::clicked,this,[](){
    qDebug()<<"button is clicked";
    }, Qt::UniqueConnection or Qt::QueuedConnection);

我也会遇到一个错误

时, href =“ https://stackoverflow.com/a/20717599/9484913”> https://stackoverflow.com/a/a/20717599/9484913 我尝试以下:

QPushButton *button = new QPushButton();
button->setText("Clicke me ");
ui->gridLayout->addWidget(button);

QObject::connect(button,&QPushButton::clicked,this,[](){
qDebug()<<"button is clicked";
}, static_cast<Qt::ConnectionType>(Qt::QueuedConnection | Qt::UniqueConnection));

“

I try this Example :

QPushButton *button = new QPushButton();
button->setText("Clicke me ");
ui->gridLayout->addWidget(button);

connect(button,&QPushButton::clicked,this,[](){
qDebug()<<"button is clicked";
}, Qt::UniqueConnection);

what you write In your connect is wrong, because you should follow this style :

connect(object,SIGNAL(mySig()), this,SLOT(mySlot())),Qt::QueuedConnection); 

you can't use two Connections at the same time

enter image description here

From Qt::ConnectionType for Qt::UniqueConnection :

This is a flag that can be combined with any one of the above
connection types, using a bitwise OR. When Qt::UniqueConnection is
set, QObject::connect() will fail if the connection already exists
(i.e. if the same signal is already connected to the same slot for the
same pair of objects). This flag was introduced in Qt 4.6.

Noted that it was introduced in Qt 4.6 and it said that if the connection already exists QObject::connect() will fail.

as I try

  connect(button,&QPushButton::clicked,this,[](){
    qDebug()<<"button is clicked";
    }, Qt::UniqueConnection or Qt::QueuedConnection);

I got an error too because I use the Qt 6 version and it may work in Qt 4.6.

From https://stackoverflow.com/a/20717599/9484913 I try this :

QPushButton *button = new QPushButton();
button->setText("Clicke me ");
ui->gridLayout->addWidget(button);

QObject::connect(button,&QPushButton::clicked,this,[](){
qDebug()<<"button is clicked";
}, static_cast<Qt::ConnectionType>(Qt::QueuedConnection | Qt::UniqueConnection));

and it works:

enter image description here

可以在QT Connect中使用QT :: UniqueConnection

埖埖迣鎅 2025-02-20 13:09:43

要添加到Web_designer的答案中,&lt; div&gt;将具有包含元素的其宽度的75%的高度(完全由底部填充)。这是一个很好的摘要: http://mattsnider.com/css-using-percent-percent-percent-percent-percent-for-保证金和衬托/。我不确定为什么会这样,但这就是这样。

如果您希望您的Div是100%以外的宽度,则需要另一个包装div来设置宽度:

div.ar-outer{
    width: 60%; /* container; whatever width you want */
    margin: 0 auto; /* centered if you like */
}
div.ar {
    width:100%; /* 100% of width of container */
    padding-bottom: 75%; /* 75% of width of container */
    position:relative;
}
div.ar-inner {
    position: absolute;
    top: 0; bottom: 0; left: 0; right: 0;
}

我最近使用了与Elliot类似的图像技巧相似的东西,以便我使用CSS媒体查询来根据不同的徽标文件提供其他徽标文件在设备分辨率上,但仍以成比例地缩放为&lt; img&gt;自然会执行(我将徽标作为背景图像设置为具有正确方面的透明.png 比率)。但是Web_designer的解决方案可以为我节省HTTP请求。

To add to Web_Designer's answer, the <div> will have a height (entirely made up of bottom padding) of 75% of the width of it's containing element. Here's a good summary: http://mattsnider.com/css-using-percent-for-margin-and-padding/. I'm not sure why this should be so, but that's how it is.

If you want your div to be a width other than 100%, you need another wrapping div on which to set the width:

div.ar-outer{
    width: 60%; /* container; whatever width you want */
    margin: 0 auto; /* centered if you like */
}
div.ar {
    width:100%; /* 100% of width of container */
    padding-bottom: 75%; /* 75% of width of container */
    position:relative;
}
div.ar-inner {
    position: absolute;
    top: 0; bottom: 0; left: 0; right: 0;
}

I used something similar to Elliot's image trick recently to allow me to use CSS media queries to serve a different logo file depending on device resolution, but still scale proportionally as an <img> would naturally do (I set the logo as background image to a transparent .png with the correct aspect ratio). But Web_Designer's solution would save me an http request.

维持使用CSS的DIV的纵横比

埖埖迣鎅 2025-02-20 04:14:56

因此,如果我让您正确,您想从样式表中使用HMTL中的新值更改 /覆盖您的默认CSS。

为此,只需在标签中插入“样式”即可。

例如:

<Multiselect class="multiselect" style="color: black;"/>

So if I have got you right, you want to change / overwrite your default CSS from your stylesheet with new values in your hmtl.

To do this, simply insert "style" within your tag.

For example:

<Multiselect class="multiselect" style="color: black;"/>

如何以其自己的vue&lt; style&gt;标签

埖埖迣鎅 2025-02-19 19:12:48

问题是您正在使用@State而不是@binding
视图重置的状态出现,但@bindings在视图中存储。您应该这样使用:

@Binding var activeDader1: dader1
@Binding var activeDader2: dader2
@Binding var activeDader3: dader3

The problem is you are using @State instead of @Binding.
The State of the view resets on appear, but @bindings are stored across the views. You should use like this:

@Binding var activeDader1: dader1
@Binding var activeDader2: dader2
@Binding var activeDader3: dader3

Swiftui使用一些枚举的绑定

埖埖迣鎅 2025-02-19 16:45:24

分发方法范围从导出您的应用程序的测试设备到将其上传到App Store Connect。您可以使用Usetestflight来分发iOS,TVOS和WatchOS Beta构建并收集反馈。如果要将您的应用程序分配给注册设备,使用TestFlight或通过App Store将应用程序分配给Beta测试仪,则需要加入Apple Developer程序。 Apple为您创建App Store Connect帐户,您可以启动上传构建。

Distribution methods range from exporting your app for test devices to uploading it to App Store Connect. You can useTestFlight to distribute iOS, tvOS, and watchOS beta builds to testers and collect feedback. If you want to distribute your app to registered devices, to beta testers using TestFlight, or through the App Store, you need to join the Apple Developer Program. Apple creates an App Store Connect account for you and you can start uploading builds.

颤音,不能在新机器中存档iOS

埖埖迣鎅 2025-02-19 04:54:17
 return GestureDetector(
    child: Row(children: [
  // alt image component
  SizedBox(
    height: 100,
    width: 100,
    child: Container(
      color: Colors.red,
    ),
  ),
  // item description
  Expanded(
    child: Column(
      children: [
        Text("user name"),
        Text(
            "user comment text: jump jump jump high jump high jump big jump big jump choo choo choo ya ya ya ri ri ri uh uh uh user comment text: jump jump jump high jump high jump big jump big jump choo choo choo ya ya ya ri ri ri uh uh uh"),
      ],
    ),
  ),
]));
 return GestureDetector(
    child: Row(children: [
  // alt image component
  SizedBox(
    height: 100,
    width: 100,
    child: Container(
      color: Colors.red,
    ),
  ),
  // item description
  Expanded(
    child: Column(
      children: [
        Text("user name"),
        Text(
            "user comment text: jump jump jump high jump high jump big jump big jump choo choo choo ya ya ya ri ri ri uh uh uh user comment text: jump jump jump high jump high jump big jump big jump choo choo choo ya ya ya ri ri ri uh uh uh"),
      ],
    ),
  ),
]));

我不知道如何将文字包裹在扑朔迷离中

埖埖迣鎅 2025-02-18 20:15:30

让我们解码程序中正在发生的事情。

questions = [a(), b(), c()]

此列表正在调用三个功能并存储其结果。如您所见,您的功能都没有返回任何东西。这使上述创建列表的内容为全部

但是,为什么您在输出中看到包含三个值的列表?

这是因为print(random.sample(问题,3))。这条线试图从具有所有无值的列表中获取三个随机值。

现在如何提出随机问题或在您的情况下如何调用随机功能?

这可以通过多种方式完成。我目前能想到的一种简单方法是:

确保将您的问题列表修改为:

questions = [a, b, c]

首先在问题范围内创建一个随机的问题编号:

question_num = random.randint(0,len(questions)-1)

然后使用问题号来调用适当的问题:

questions[question_num]()

这应该问一个一次随机问题。但是,如果您想继续提出一个随机的问题,则可以在循环中调用上述两行。

这个答案符合您的解决方案,但是如果您想做同样的事情,则有不同的有效方法。我将尝试在这里添加它们。

Let's decode what is happening in your program.

questions = [a(), b(), c()]

This list is calling three functions and storing their results. As you see, none of your functions are returning anything. This makes the contents of the above created list to be all None.

But why are you seeing a list containing three None values in your output?

That is because of print(random.sample(questions, 3)) . This line is trying to get three random values from a list that has all None values.

Now how to ask random questions or in your case, how to call random functions?

This can be done in multiple ways. One easy way I can think of at the moment is:

Make sure to modify your question list to:

questions = [a, b, c]

First create a random question number in the range of length of questions:

question_num = random.randint(0,len(questions)-1)

Then use the question number to call the appropriate question:

questions[question_num]()

This should ask one random question at a time. But if you want to keep asking a random question , you can call the above two lines in a loop.

This answer is in line with what your solutions is, but if you want to do the same thing, there are different efficient ways. I will try to add them here.

如何从列表中随机调用函数?

埖埖迣鎅 2025-02-18 17:37:03

如果是ASP.NET表单,则应该可以这样这样做。这应该在值中用x隐藏项目。

foreach (var itm in dd_mainAlan.Items)
{
    var it = (ListItem)itm;
    it.Enabled = !it.Value.Contains("x");
}

If it is ASP.NET Forms, you should be able to do it like this maybe. This should hide the items with an x in the Value.

foreach (var itm in dd_mainAlan.Items)
{
    var it = (ListItem)itm;
    it.Enabled = !it.Value.Contains("x");
}

如何获得ASP下拉列表中包含的数据的值?

埖埖迣鎅 2025-02-18 14:44:07

从Alex B中,C ++标准并未指定字节中积分类型的大小,但指定了它们必须能够保留的最小范围。您可以从所需范围内推断出最小尺寸。您可以从该字节中推断出最小尺寸,以及定义字节中的位数的char_bit宏的值(除了最晦涩的平台外,它是8个,并且不能少于8)。

char的另一个约束是其大小始终是1个字节或char_bit lit(因此名称)。

标准要求(第22页)所需的最小范围为:

MSDN上的数据类型范围:

签名char:-127至127(注意,不是-128至127;这可容纳1's -complement平台)
未签名的char:0至255
“普通” char:-127至127或0至255(取决于默认的char签名)
签名短:-32767至32767
未签名短:0至65535
签名INT:-32767至32767
未签名INT:0至65535
签名长:-2147483647至2147483647
未签名长:0至4294967295
长长签名:-922372036854775807至9223372036854775807
无签名长:0到184444444073709551615
C ++(或C)实现可以将字节大小(类型)中的类型大小定义为任何值,只要

表达式sizeof(type) * char_bit评估到足以包含所需范围的位数的数量,并且
类型的排序仍然有效(例如sizeof(int)&lt; = sizeof(long))。
实际实现特定的范围可以在C中的标头或C ++中找到(甚至更好的,甚至更好的STD :: Numeric_limits)。

例如,这是您如何找到INT的最大范围:

C:

#include <limits.h>
const int min_int = INT_MIN;
const int max_int = INT_MAX;

C ++:

#include <limits>
const int min_int = std::numeric_limits<int>::min();
const int max_int = std::numeric_limits<int>::max();

这是正确的,但是,您也是正确的说:
char:1字节
简:2个字节
int:4个字节
长:4个字节
浮点:4个字节
double:8字节,

因为32位体系结构仍然是默认和大多数使用的,并且自32位之前的内存较少时,它们一直保持这些标准尺寸,并且对于向后兼容和标准化,它们保持不变。即使是64位系统也倾向于使用这些并进行范围/修改。
请参考此信息以获取更多信息:

http://en.cppreference.com/w/cpp/语言/类型

From Alex B The C++ standard does not specify the size of integral types in bytes, but it specifies minimum ranges they must be able to hold. You can infer minimum size in bits from the required range. You can infer minimum size in bytes from that and the value of the CHAR_BIT macro that defines the number of bits in a byte (in all but the most obscure platforms it's 8, and it can't be less than 8).

One additional constraint for char is that its size is always 1 byte, or CHAR_BIT bits (hence the name).

Minimum ranges required by the standard (page 22) are:

and Data Type Ranges on MSDN:

signed char: -127 to 127 (note, not -128 to 127; this accommodates 1's-complement platforms)
unsigned char: 0 to 255
"plain" char: -127 to 127 or 0 to 255 (depends on default char signedness)
signed short: -32767 to 32767
unsigned short: 0 to 65535
signed int: -32767 to 32767
unsigned int: 0 to 65535
signed long: -2147483647 to 2147483647
unsigned long: 0 to 4294967295
signed long long: -9223372036854775807 to 9223372036854775807
unsigned long long: 0 to 18446744073709551615
A C++ (or C) implementation can define the size of a type in bytes sizeof(type) to any value, as long as

the expression sizeof(type) * CHAR_BIT evaluates to the number of bits enough to contain required ranges, and
the ordering of type is still valid (e.g. sizeof(int) <= sizeof(long)).
The actual implementation-specific ranges can be found in header in C, or in C++ (or even better, templated std::numeric_limits in header).

For example, this is how you will find maximum range for int:

C:

#include <limits.h>
const int min_int = INT_MIN;
const int max_int = INT_MAX;

C++:

#include <limits>
const int min_int = std::numeric_limits<int>::min();
const int max_int = std::numeric_limits<int>::max();

This is correct, however, you were also right in saying that:
char : 1 byte
short : 2 bytes
int : 4 bytes
long : 4 bytes
float : 4 bytes
double : 8 bytes

Because 32 bit architectures are still the default and most used, and they have kept these standard sizes since the pre-32 bit days when memory was less available, and for backwards compatibility and standardization it remained the same. Even 64 bit systems tend to use these and have extentions/modifications.
Please reference this for more information:

http://en.cppreference.com/w/cpp/language/types

C&#x2B;&#x2B;什么是什么标准说int的大小,长吗?

埖埖迣鎅 2025-02-18 13:06:18

Vite需要更新的节点版本。

您可以下载最新的 node版本然后运行npm npm install and NPM运行DEV

要创建您可以使用PHP Artisan服务的服务器

Vite needs an updated node version.

You can download the latest node version then run npm install and npm run dev

To create the server you can use php artisan serve

我可以运行&#x27; npm run dev&#x27;由于Laravel随Vite更新了

埖埖迣鎅 2025-02-18 12:56:53

我找到了解决方案:

{% for option in group.options %}
 {% set isActive = false %}
 {% set isCombinableCls = 'is-combinable' %}
 {% if option.id in page.product.optionIds %}
 {% set isActive = true %}
 {% endif %}
 {% if isActive %}
 {{ option.translated.name }}
 {% endif %}
{% endfor %}

I found the solution:

{% for option in group.options %}
 {% set isActive = false %}
 {% set isCombinableCls = 'is-combinable' %}
 {% if option.id in page.product.optionIds %}
 {% set isActive = true %}
 {% endif %}
 {% if isActive %}
 {{ option.translated.name }}
 {% endif %}
{% endfor %}

如何找到所选的变体值作为变量?

埖埖迣鎅 2025-02-18 07:14:26

我认为您应该这样做:

function TestClass:new(o)
    o = o or { param = { n = 5 } }
    setmetatable(o, self)
    self.__index = self
    return o
end

I think you should do it like this then:

function TestClass:new(o)
    o = o or { param = { n = 5 } }
    setmetatable(o, self)
    self.__index = self
    return o
end

表不作为我班上的属性

埖埖迣鎅 2025-02-18 04:27:34

这是一个尝试,但第二行中只有数字更改

df1$Inv <- cumsum(df1$Inv - df1$Inved)

df1$Inved <- cumsum(df1$Inved)

Here is a try but with only number changed in the second row

df1$Inv <- cumsum(df1$Inv - df1$Inved)

df1$Inved <- cumsum(df1$Inved)

根据日期在R中创建运行计数

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