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就此别过 2025-02-21 00:49:38

这是另一种有用的语法:

UPDATE suppliers
SET supplier_name = (SELECT customers.name
                     FROM customers
                     WHERE customers.customer_id = suppliers.supplier_id)
WHERE EXISTS (SELECT customers.name
              FROM customers
              WHERE customers.customer_id = suppliers.supplier_id);

它通过使用“存在的地方”检查是否为null进行检查。

Here is another useful syntax:

UPDATE suppliers
SET supplier_name = (SELECT customers.name
                     FROM customers
                     WHERE customers.customer_id = suppliers.supplier_id)
WHERE EXISTS (SELECT customers.name
              FROM customers
              WHERE customers.customer_id = suppliers.supplier_id);

It checks if it is null or not by using "WHERE EXIST".

如何从SQL Server中的选择中更新?

就此别过 2025-02-20 23:54:42

如果我们谈论 swashbuckle 软件包,我们需要使用inlare enasle image> idocumentFilter

您可以从此 post

基本方案:

  • 定义自定义属性
  • 设置此属性为Controllers/action
  • 中实现过滤逻辑

在您的docuct> docuct> documentfilter 类代码示例 在这里可用:

[AttributeUsage(AttributeTargets.Class | AttributeTargets.Method)]
public class LicenseValidatorAttribute : Attribute
{
    public FeatureType Feature { get; set; }
}

public class FeatureDocumentFilter : IDocumentFilter
{
    private readonly IFeatureService _featureService;

    public FeatureDocumentFilter(IFeatureService featureService)
    {
        _featureService = featureService;
    }

    public void Apply(OpenApiDocument swaggerDoc, DocumentFilterContext context)
    {
        foreach (var api in context.ApiDescriptions)
        {
            var attribute = api.CustomAttributes().OfType<FeatureValidatorAttribute>().FirstOrDefault();

            if (attribute != null)
            {
                var success = _featureService.ValidateFeature(attribute.Feature);

                if (!success.Valid)
                {
                    var route = "/" + api.RelativePath;
                    swaggerDoc.Paths.Remove(route);
                }
            }
        }
    }
}

If we talk about Swashbuckle package then we need to use implement IDocumentFilter.

Some initial information you can review from this post.

Basic scenario:

  • Define custom Attribute
  • Setup this attribute to Controllers / Actions
  • Implement filtration logic in your DocumentFilter class

Code sample available here:

[AttributeUsage(AttributeTargets.Class | AttributeTargets.Method)]
public class LicenseValidatorAttribute : Attribute
{
    public FeatureType Feature { get; set; }
}

public class FeatureDocumentFilter : IDocumentFilter
{
    private readonly IFeatureService _featureService;

    public FeatureDocumentFilter(IFeatureService featureService)
    {
        _featureService = featureService;
    }

    public void Apply(OpenApiDocument swaggerDoc, DocumentFilterContext context)
    {
        foreach (var api in context.ApiDescriptions)
        {
            var attribute = api.CustomAttributes().OfType<FeatureValidatorAttribute>().FirstOrDefault();

            if (attribute != null)
            {
                var success = _featureService.ValidateFeature(attribute.Feature);

                if (!success.Valid)
                {
                    var route = "/" + api.RelativePath;
                    swaggerDoc.Paths.Remove(route);
                }
            }
        }
    }
}

根据API键显示/隐藏Swagger UI端点

就此别过 2025-02-20 23:14:32

对项目进行备份,然后尝试此

  1. 删除iOS文件夹
  2. flutter创建(带有同名的新项目)
  3. 将iOS文件夹复制到替换删除的文件
  4. 颤动清洁
  5. 扑面运行

make a backup of the project and try this

  1. delete iOS folder
  2. flutter create (new project with same name)
  3. copy iOS folder to the replace deleted file
  4. flutter clean
  5. flutter run

Flutter Build iOS命令总是被卡在&#x2514;&#x2500;编译,链接和签名...&#x28ef;

就此别过 2025-02-20 21:25:10

不幸的是,您不能。

这不是可以在编译时确定的。

参见 https://en.wikipedia.org/wiki/wiki/halting_problem

Unfortunately, you cannot.

This is not something that can be determined at compile time.

See https://en.wikipedia.org/wiki/Halting_problem

如何计数特定函数的数量在编译时间调用

就此别过 2025-02-20 21:18:01

您无法在宏之外构建非线性表达式。

请参阅文档: https://jump.dev/jump.dev/jump.jump.jl/stable/smanual/stable/manual/manual /nlp/

您可以使用用户定义的功能,但我不明白您的示例。它硬编码返回1,所以我不知道uh是什么。

您的示例也不可复制,因为我不知道hvfun是什么。

PS,如果您想进行更长的讨论,请在社区论坛上发布: https:https:https:https:https:https: //discourse.julialang.org/c/domain/opt/13 。具有后卫比在堆栈溢出上要容易得多。

You can't construct nonlinear expressions outside the macros.

See the documentation: https://jump.dev/JuMP.jl/stable/manual/nlp/

You can use a user-defined function, but I don't understand your example. It hard-codes return 1, so I don't know what u and h are for.

Your example is also non-reproducible, because I don't know what hvfun is.

p.s., If you want to have a longer discussion, please post on the community forum: https://discourse.julialang.org/c/domain/opt/13. It's a bit easier to have a back-and-forward than on stack overflow.

/(:: variableref,:: quadexpr)未定义

就此别过 2025-02-20 17:19:34

您需要使用。redirect(code,url)

res.redirect(301, `${success_url}${query}`);

You want to use .redirect(code, url).

res.redirect(301, `${success_url}${query}`);

通过nodejs重定向到URL

就此别过 2025-02-20 16:09:54

我忘了在这里粘贴解决方案,以防任何人遇到相同的问题。实际上,我只是将组件从GAC复制到应用程序文件夹中,然后.NET Core能够找到组件。

I forgot to paste the solution here in case anybody runs into the same problem. I actually just copied the assembly from the GAC into the application folder and then, .NET Core was able to find the assembly.

调整.NET交互式笔记本的运行时标识符

就此别过 2025-02-20 09:53:41

这些解决方案很棒,但是当您的列太多时,您不想键入所有列名。所以这是我想到的:

column_map = {col: "first" for col in df.columns}
column_map["col_name1"] = "sum"
column_map["col_name2"] = lambda x: set(x) # it can also be a function or lambda

现在您可以做

df.groupby(["col_to_group"], as_index=False).aggreagate(column_map)

These solutions are great, but when you have too many columns, you do not want to type all of the column names. So here is what I came up with:

column_map = {col: "first" for col in df.columns}
column_map["col_name1"] = "sum"
column_map["col_name2"] = lambda x: set(x) # it can also be a function or lambda

now you can simply do

df.groupby(["col_to_group"], as_index=False).aggreagate(column_map)

与groupby一起使用sum()时,请保留其他列

就此别过 2025-02-20 07:31:55
  1. isprime是一个标志,指示该数字可能是素数(即我们没有证明相反)

  2. p/primes [i]&gt; = primes [i]检查如果检查以前发现的质数是否为Divisor

    是有意义的

  3. p%primes [ i] == 0检查数字不是素数 - 从点1设置标志。

  1. isPrime is a flag indicating that the number is potentially prime (ie we do not proved opposite)

  2. p / primes[i] >= primes[i] checks if it makes sense to check if the number is prime for the previously found prime as a divisor

  3. p % primes[i] == 0 checks if the number is not prime - setting the flag from point 1.

循环做什么?我不了解此处的for循环功能

就此别过 2025-02-20 05:33:30
  • 如果路径为空或未设置,则您的代码添加了一个空路径条目(),导致当前目录始终处于路径中。

  • 您应该设置路径,例如:导出路径=/my/path $ {path+:$ path},或export path =/my/my/path $ {路径:+:$:$ path }

  • 如果路径不设,第一个避免了空条目,但是如果已经设置为空,则不是。第二个总是避开空路进入。

  • 尽管不太可能是不设置或空的路径,但如果您想要“完美的替代”,则应使用第一个示例。如果您认为空的路径始终是您应用程序的错误,则可以使用第二个示例。

  • 除此之外,exec命令“ $@”是非常标准的(如前所述添加引号)。

  • If PATH is empty or unset, your code adds an empty path entry (after :), causing the current directory to always be in PATH.

  • You should set PATH like: export PATH=/my/path${PATH+:$PATH}, or export PATH=/my/path${PATH:+:$PATH}.

  • The first one avoids an empty entry if PATH is unset, but not if it has already been set to empty. The second one always avoids an empty PATH entry.

  • Although it's unlikely PATH will be unset or empty, if you want "perfect substitution", you should use the first example. If you believe empty PATH is always a bug for your application, you could use the second example.

  • Apart from that, exec command "$@" is pretty standard (add quotes as already mentioned).

如何制作完美的bash包装脚本

就此别过 2025-02-20 03:43:16

如果将项目放在git scm下,然后使用 setUptoopools_scm 从git标签管理版本。这包括在建造时标记“脏”。构建版本会自动调整。

If you put your project under git SCM, and then use setuptools_scm it will manage the version for you from git tags. that includes marking it "dirty" when building. The built version is automatically adjusted.

Python车轮套餐 - 如何将时间戳添加到轮子名称中?

就此别过 2025-02-20 01:33:42


从源代码。看来reschedule_job无法修改其他参数。
您可以使用修改而不是reschedule_job

示例:

scheduler = BackgroundScheduler()
scheduler.add_job(test, 'interval', seconds=3, args=['old params'], id="y")

job = scheduler.get_job(job_id="y")
job.modify(
    trigger='interval',
    seconds=10
)

enter image description here
from the source code. it seems that reschedule_job can not modify other parameters.
you can use modify instead of reschedule_job

example:

scheduler = BackgroundScheduler()
scheduler.add_job(test, 'interval', seconds=3, args=['old params'], id="y")

job = scheduler.get_job(job_id="y")
job.modify(
    trigger='interval',
    seconds=10
)

关于apscheduler.reschedule_job()如何更新新参数

就此别过 2025-02-19 06:07:14

让我们考虑一下这些双重数字的实际位表示:

我们可以使用system.out.println(long.tobinarystring(double.doubletorawlawlongbits(c)));打印位表示。

900719254740990.99007199254740990.8在IEEE 754之后具有相同的位表示:

0 10000110011 1111111111111111111111111111111111111111111111111111

s(sign) = 0
exp = 10000110011 (binary value, which equals 1075 in decimal)
frac = 111...111 (52 bits)

此表示的确切值是:

“值计算”

使用IEEE 754,从2^53开始,双重类型不再能够精确地表示大于2 ^ 53的所有整数,更不用说浮点数了。

关于操作问题,如其他答案中所述,没有准确的范围。例如,以下语句将评估为真实。我们不会说双重比较的浮动数范围小于1.1。一般来说,数字越大,双重类型所代表的精确度就越少。

double x1 = 1.1;
double x2 = 1.1000000000000001;
System.out.println(x1 == x2); // true

Let's think about the actual bit representation of these double numbers:

We can use System.out.println(Long.toBinaryString(Double.doubleToRawLongBits(c))); to print the bit representation.

Both 9007199254740990.9 and 9007199254740990.8 has the same bit representation following IEEE 754:

0 10000110011 1111111111111111111111111111111111111111111111111111

s(sign) = 0
exp = 10000110011 (binary value, which equals 1075 in decimal)
frac = 111...111 (52 bits)

The precise value of this representation is:

value calculation

With IEEE 754, starting from 2^53, the double type is no longer able to precisely represent all integers larger than 2 ^ 53, let alone floating point numbers.

Regarding the OP question, as mentioned in other answers, there's not an accurate range. For example, the following statement will evaluate as true. We won't say that the range of floating numbers that double can compare is less than 1.1. Generally speaking, the larger the number is, the less precise the double type could represent.

double x1 = 1.1;
double x2 = 1.1000000000000001;
System.out.println(x1 == x2); // true

IEEE754可以正确比较浮点数的大小的范围是多少

就此别过 2025-02-18 17:58:02

要访问this.componentlevelproperty,您可以使用提供箭头功能的范围。

  dataLabels: {
    enabled: true,
    formatter: () => {
      console.log(this.somePropertyOnTheAppComponent);

      return 'update';
    },
  },

To access this.componentLevelProperty you can use a scope that gives arrow function.

  dataLabels: {
    enabled: true,
    formatter: () => {
      console.log(this.somePropertyOnTheAppComponent);

      return 'update';
    },
  },

Demo

HighCharts访问Angular成分值在格式化函数内部函数

就此别过 2025-02-18 05:34:29

与@dominik的另一种方法是

I = np.stack((I1,I2,I3))

stack 创建一个新的Axis 。

A different way from @Dominik is

I = np.stack((I1,I2,I3))

stack creates a new axis.

python中的3个多维阵列

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