苏别ゝ

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苏别ゝ 2025-02-20 15:51:31

删除扩展的小部件。扩展的小部件将需要从其父窗口小部件中获得的界限。有关展开

@override
  Widget build(BuildContext context) {
    return Scaffold(
      appBar: AppBar(
        title: Text(title),
      ),
      body: Obx(() => SingleChildScrollView(
        child: Column(
              children: [
                Padding(
                  padding: EdgeInsets.symmetric(horizontal: (Get.find<SearchFormController>().searchFormModelHistoryList.length == 0) ? 260.0 : 15.0),
                  child: Row(children: [
                    Expanded(
                      flex: 1,
                      child: Container(
                        color: Color.fromARGB(255, 255, 252, 234),
                        margin: const EdgeInsets.only(left: 20.0, top: 20.0, right: 20.0),
                        child: SearchForm(),
                      ),
                    ),
                    Visibility(
                      // visible: !  state.getListApiCalled ? true : false,
                      visible: (Get.find<SearchFormController>().searchFormModelHistoryList.length > 0) ? true : false,
                      child: Expanded(
                        flex: 1, child: QueriesHistoryForm(),
                      ),
                    ),
                  ]),
                ),
      

                  SizedBox(
                    height: 700,
                    child: WebView(
                      initialUrl: 'http://localhost/index.html',
                      onWebViewCreated: (WebViewController controller) {
                        _webViewController.complete(controller);
                      },
                    ),
                  ),
      
              ],
            ),
      )),
    );
  }
}

edit edit ,
如果您想在不滚动的情况下做到这一点,则可以使用此方法

SizedBox(
 height: MediaQuery.of(context).size.height,
width: MediaQuery.of(context).size width,
  child: Column(
   children:[
      //Row widget here
     Expanded(//now this expanded has a bound same as that of the device height 
       child : WebView(),
     )
    ]
  )
)

Remove expanded widget. An expanded widget will need a bound which it takes from its parent widget. More about expanded

@override
  Widget build(BuildContext context) {
    return Scaffold(
      appBar: AppBar(
        title: Text(title),
      ),
      body: Obx(() => SingleChildScrollView(
        child: Column(
              children: [
                Padding(
                  padding: EdgeInsets.symmetric(horizontal: (Get.find<SearchFormController>().searchFormModelHistoryList.length == 0) ? 260.0 : 15.0),
                  child: Row(children: [
                    Expanded(
                      flex: 1,
                      child: Container(
                        color: Color.fromARGB(255, 255, 252, 234),
                        margin: const EdgeInsets.only(left: 20.0, top: 20.0, right: 20.0),
                        child: SearchForm(),
                      ),
                    ),
                    Visibility(
                      // visible: !  state.getListApiCalled ? true : false,
                      visible: (Get.find<SearchFormController>().searchFormModelHistoryList.length > 0) ? true : false,
                      child: Expanded(
                        flex: 1, child: QueriesHistoryForm(),
                      ),
                    ),
                  ]),
                ),
      

                  SizedBox(
                    height: 700,
                    child: WebView(
                      initialUrl: 'http://localhost/index.html',
                      onWebViewCreated: (WebViewController controller) {
                        _webViewController.complete(controller);
                      },
                    ),
                  ),
      
              ],
            ),
      )),
    );
  }
}

edit
If you wish to make it without scroll you can use this approach

SizedBox(
 height: MediaQuery.of(context).size.height,
width: MediaQuery.of(context).size width,
  child: Column(
   children:[
      //Row widget here
     Expanded(//now this expanded has a bound same as that of the device height 
       child : WebView(),
     )
    ]
  )
)

可以获取`singlechildscrollview`滚动工作

苏别ゝ 2025-02-20 10:32:41

我个人最喜欢 sprintf (或 vsprintf ,对于一系列参数)。它以预期的顺序将它们放置,根据需要胁迫类型,并具有更多高级功能。

示例:

$var = sprintf("%s costs %.2f dollars", "Cookies", 1.1);

这将导致价值 cookies的成本1.10美元

有一个用于不同用例的printf功能的全家函数,所有这些功能都列在“参见”下。

非常通用:提供变量,数组组件,功能结果等的相同方法。

I personally most like sprintf (or vsprintf, for an array of arguments). It places them in the intended order, coerces types as needed, and has a lot more advanced features available.

Example:

$var = sprintf("%s costs %.2f dollars", "Cookies", 1.1);

This will result in the value Cookies cost 1.10 dollars.

There's an entire family of printf functions for different use cases, all listed under "See Also".

Very versatile: same methods for providing variables, array components, function results, etc.

PHP是否具有Python的模板字符串之类的功能?

苏别ゝ 2025-02-20 07:56:15

尝试使用以下查询:

UPDATE <your_tab_to_be_updated>
INNER JOIN (SELECT cons_id, 
                   credited_date,
                   ROW_NUMBER() OVER (partition by cons_id order by cons_id) AS Row_Counter
            FROM fy23_jul_aug_anniv_jv) cte 
        ON <your_tab_to_be_updated>.cons_id       = cte.cons_id
       AND <your_tab_to_be_updated>.credited_date = cte.credited_date
SET <your_tab_to_be_updated>.Row_Counter = cte.Row_Counter;

它将在您在查询中选择的其他两个列上使用原始表加入子查询,并将Row_number分配给原始表。

要进行更多故障排除,如果您可以从输入表中共享样本并相应的预期输出,我可以进一步提供帮助。

Try using the following query:

UPDATE <your_tab_to_be_updated>
INNER JOIN (SELECT cons_id, 
                   credited_date,
                   ROW_NUMBER() OVER (partition by cons_id order by cons_id) AS Row_Counter
            FROM fy23_jul_aug_anniv_jv) cte 
        ON <your_tab_to_be_updated>.cons_id       = cte.cons_id
       AND <your_tab_to_be_updated>.credited_date = cte.credited_date
SET <your_tab_to_be_updated>.Row_Counter = cte.Row_Counter;

It will join the subquery with your original table on the two other columns that you're selecting in your query, and assign the row_number to your original table.

For more troubleshooting, I can help further if you can share samples from your input tables and corresponding expected output.

将行号添加到表中的字段

苏别ゝ 2025-02-18 21:13:22

错误&lt; menuitems /&gt;缺少父母&lt;菜单 /&gt;组件不是VUE特定错误。这是 headlessui/vue - source

menuitems component(以及 menubuton etceet et et eft-请参阅 doc )被设计为在菜单 component中使用。它正在使用注入来点击状态提供了通过菜单组件。您无能为力 - 它是这样设计的

问题是,在vue中始终在&lt; template#contentDropdown&gt; )始终呈现=“ https://vuejs.org/guide/components/slots.html#render-scope” rel =“ nofollow noreferrer”> parent scope

父模板中的所有内容都在父范围内编译;子模板中的所有内容都在子范围中编译。

这意味着 menuitems 作为插槽内容渲染的无法访问data 提供菜单组件组件呈现在您的下拉code 组件

我看不出任何方法可以克服此限制。您需要更改设计(或将用例描述为 Headlessui/vue 维护者,并要求他们实现替代方法来共享

The error <MenuItems /> is missing a parent <Menu /> component is not a Vue specific error. It is an error thrown by headlessui/vue - source

MenuItems component (as well as MenuButon etc - see doc) is designed to be used inside Menu component. It is using inject to tap into state provideded by the Menu component. There is nothing you can do about it - it is designed that way

Problem is that slot content (everything inside <template #contentdropdown> in the last code example) in Vue is always rendered in parent scope

Everything in the parent template is compiled in parent scope; everything in the child template is compiled in the child scope.

This means that MenuItems rendered as slot content has no access to data provideded by the Menu component rendered inside your Dropdown component

I don't see any way to overcome this limitation. You'll need to change your design (or describe your use case to headlessui/vue maintainers and ask them to implement alternative approach to share MenuContext with child components - for example using slot props)

&lt; menuitems /&gt;缺少父母&lt;菜单 /&gt;组件错误(插槽中的菜单)

苏别ゝ 2025-02-18 08:10:19

Mac OSX Monterey(12.x)当前使用端口5000和7000来控制中心。

尝试从 5000 7000 使用以外的端口运行您的应用程序

:然后运行以下内容:

if __name__ == "__main__":
    app.run(port=8000, debug=True)

然后运行烧瓶文件,例如: app.py

Python App.py

您还可以使用 flask 命令行接口运行此命令,只要您设置了烧瓶CLI所需的环境变量。

flask Run -Port 8000

您还可以通过系统偏好在共享中关闭 airplay接收器

在这里相关讨论: https://develoveling.apple.apple.com/forums/thread/682332

更新(2022年11月):

Mac OSX Ventura(13.x)仍然存在此问题,并与上述默认端口的更改固定。

Mac OSX Monterey (12.x) currently uses ports 5000 and 7000 for its Control centre hence the issue.

Try running your app from port other than 5000 and 7000

use this:

if __name__ == "__main__":
    app.run(port=8000, debug=True)

and then run your flask file, eg: app.py

python app.py

You can also run using the flask command line interface using this command provided you have set the environment variable necessary for flask CLI.

flask run --port 8000

You can also turn off AirPlay Receiver in the Sharing via System Preference.

Related discussion here: https://developer.apple.com/forums/thread/682332

Update(November 2022):

Mac OSX Ventura(13.x) still has this problem and is fixed with the change in default port as mentioned above.

如何在Python中使用烧瓶解决403错误?

苏别ゝ 2025-02-17 20:57:36

这比较了2个未分类的阵列:

function areEqual(a, b) {
  if ( a.length != b.length) {
    return false;
  }
  return a.filter(function(i) {
    return !b.includes(i);
  }).length === 0;  
}

This compares 2 unsorted arrays:

function areEqual(a, b) {
  if ( a.length != b.length) {
    return false;
  }
  return a.filter(function(i) {
    return !b.includes(i);
  }).length === 0;  
}

如何在JavaScript中比较数组?

苏别ゝ 2025-02-17 06:34:46

如果您使用Elementor创建了此功能,则可以将其删除,如果它的主题部分,则可以从自定义中删除它

,而删除它的最佳方法是使用CSS。

如果您可以告诉我URL,那么我可以给您CSS代码以删除此栏。

if you created this using elementor then you can just remove that and if it's theme part then you can remove it from customization

and the best way to remove it is by using CSS.

if you can tell me the URL then I can give you the CSS code to remove this bar.

WordPress Elementor:如何摆脱垂直线?

苏别ゝ 2025-02-16 16:25:26

尝试使用二倍度来使宽度动画,例如:

double width = ((playTimePercent > 0 && playTimePercent < 1) ? playTimePercent : 1) * MainBackLine.ActualWidth;
DoubleAnimation doubleAnimation = new DoubleAnimation(width, new Duration(TimeSpan.FromMilliseconds(100)));
MainColorLine.BeginAnimation(FrameworkElement.WidthProperty, doubleAnimation);

Try to use a DoubleAnimation to animate the width, e.g.:

double width = ((playTimePercent > 0 && playTimePercent < 1) ? playTimePercent : 1) * MainBackLine.ActualWidth;
DoubleAnimation doubleAnimation = new DoubleAnimation(width, new Duration(TimeSpan.FromMilliseconds(100)));
MainColorLine.BeginAnimation(FrameworkElement.WidthProperty, doubleAnimation);

当我尝试更改wpf中的项目范围的宽度时,UI性能问题

苏别ゝ 2025-02-16 09:06:12

我认为您正在寻找的是固定宽度整数类型。这些是在标题&lt; cstdint&gt; 中定义的。

出于您的目的,您可以坚持使用 int [xx] _t ,其中 [xx] 用所需的整数类型的宽度替换为位。 uint [xx] _t 使用无符号整数类型做类似的操作。

例如,您可以使用 int8_t int16_t uint8_t uint_16t ,等等。

I think what you're looking for is fixed width integer types. These are defined in the header <cstdint>.

For your purposes, you could stick with int[xx]_t, where you replace [xx] with the width of the integer type you need, in bits. uint[xx]_t does something similar, with unsigned integer types.

You could, for example, use int8_t, int16_t, uint8_t, uint_16t, etc.

如何在C&#x2B;&#x2B;中使用特定大小的整数类型?

苏别ゝ 2025-02-16 05:45:01

https://github.com/azure/sazure/static-web-apps/discussions/ 921

这将很快得到支持,Microsoft正在研究此事

https://github.com/Azure/static-web-apps/discussions/921

This will be supported soon, Microsoft is working on this

将nextJS SSR部署到Azure静态Web应用程序

苏别ゝ 2025-02-16 02:47:39

认为您需要使用聚合管道来进行更新。

  1. 地图 - 用作业数组返回并返回新数组。


    1.1。 $ cond - 检查条件(匹配作业的当前文档 type 技术不是一个空数组) 。如果满足,则更新文档,否则仍然存在。

    1.1.1。 $ MergeObjects - 将当前文档与 it_technologies 合并。

db.collection.update({},
[
  {
    $set: {
      "jobs": {
        $map: {
          input: "$jobs",
          in: {
            $cond: {
              if: {
                $and: [
                  {
                    $eq: [
                      "$this.type",
                      "programmer"
                    ]
                  },
                  {
                    $ne: [
                      "$this.technologies",
                      []
                    ]
                  }
                ]
              },
              then: {
                $mergeObjects: [
                  "$this",
                  {
                    it_technologies: "$this.technologies.name"
                  }
                ]
              },
              else: "$this"
            }
          }
        }
      }
    }
  }
],
{
  upsert: false,
  multi: true,
  
})

示例mongo playground

Think that you need to work the update with the aggregation pipeline.

  1. map - Iterate with the jobs array and return a new array.

    1.1. $cond - Check the condition (Match the current document of jobs type and technology is not an empty array). If fulfilled, then update the document, else remains existing.

    1.1.1. $mergeObjects - Merge current document with the document with it_technologies.

db.collection.update({},
[
  {
    $set: {
      "jobs": {
        $map: {
          input: "$jobs",
          in: {
            $cond: {
              if: {
                $and: [
                  {
                    $eq: [
                      "$this.type",
                      "programmer"
                    ]
                  },
                  {
                    $ne: [
                      "$this.technologies",
                      []
                    ]
                  }
                ]
              },
              then: {
                $mergeObjects: [
                  "$this",
                  {
                    it_technologies: "$this.technologies.name"
                  }
                ]
              },
              else: "$this"
            }
          }
        }
      }
    }
  }
],
{
  upsert: false,
  multi: true,
  
})

Sample Mongo Playground

MongoDB-基于其当前内容的更新嵌套文档

苏别ゝ 2025-02-15 08:12:32

这与Python无关,大多数OO语言就是这种情况。您应该在基类中定义一个抽象方法,使其不公开(但可用于子类覆盖),并在父类中创建一个公共模板方法,该方法将称为此抽象方法(在您的子类中定义)。客户端代码将无法直接调用有关方法,但将能够调用模板方法,该方法依次确保所讨论的方法在正确的顺序/上下文中调用。

换句话说,您的系统不得取决于调用父级实现的子类。如果是必须的,那么您确实应该查看实现并分解有关方法(例如,使用模板方法模式)。

另外,如果子类构造函数不明确地执行(虽然不适合普通方法),则某些语言(例如Java)隐式称为父构建器。

无论如何,请不要依靠“黑客”。这不是解决问题的正确方法。

This does not relate directly to Python, it would be the case for most OO languages. You should define an abstract method in your base class, make it non-public (but available for overriding by subclasses) and also create a public template method in the parent class, that will call this abstract method (defined in your subclass). The client code will not be able to call the method in question directly, but will be able to call the template method which, in turn, will make sure that the method in question is called in the correct order/context.

In other words, your system must not depend on the subclasses calling parent's implementation. If that is a must, then you indeed should review your implementation and decompose the method in question (eg, use the template method pattern).

Also, some languages (like Java) implicitly call the parent's constructor, if the subclass'es constructor does not do it explicitly (does not work for plain methods though).

In any case, please never rely on "hacks". that is not the right way to solve problems.

强迫儿童课程覆盖父级的方法

苏别ゝ 2025-02-15 02:07:58

[dcl.manting]在标准中说:

在声明中>与声明 t d1

括号不会更改嵌入式声明器-ID 的类型,但它们可以改变复杂声明器的结合。

更简单地说,您可以在C ++语法中围绕被认为是“宣告者”的任何内容。 (松散地说,声明器是声明的一部分,没有初始指定符和包含一个名称的类型。)

在您的示例中,标识符 s 是声明器,因此您可以放置​​括号周围及其含义不会改变。

正如第二个引用的句子暗示,这样做的原因是,当事情变得更加复杂时,可能是必要的。一个例子:

int * a [10];     // a is an array of ten pointers to int.
int ( * b ) [10]; // b is a pointer to an array of ten ints.

[dcl.meaning] in the Standard says:

In a declaration T D where D has the form ( D1 ) the type of the contained declarator-id is the same as that of the contained declarator-id in the declaration T D1.

Parentheses do not alter the type of the embedded declarator-id, but they can alter the binding of complex declarators.

More simply, you can put parentheses around anything considered a "declarator" in the C++ grammar. (Loosely speaking, a declarator is a part of a declaration without the initial specifiers and types which contains one name.)

In your example, the identifier s is a declarator, so you're allowed to put parentheses around it and the meaning doesn't change.

The reason for this, as the second quoted sentence hints, is that it can be necessary when things get more complicated. One example:

int * a [10];     // a is an array of ten pointers to int.
int ( * b ) [10]; // b is a pointer to an array of ten ints.

C&#x2B;&#x2B;的哪一部分标准允许在括号中声明变量?

苏别ゝ 2025-02-14 22:37:27

创建一个嵌套在另一类中的类的实例

var ren = new Kitchen.Ren() ;

string actChoice = Console.ReadLine();

switch (actChoice)
{
    case "1":
        
        break;
        case "2":
            Kitchen.Ren ren = new(); // One way to do it
        ren.Meal();
        break;
    default:
        break;
}
class Kitchen
{
    public class Ren
    {
        public void Meal()
        {
            Console.WriteLine("OK Meal");
        }
    }
}

Create an instance of a class nested inside another class

var ren = new Kitchen.Ren() ;

.

string actChoice = Console.ReadLine();

switch (actChoice)
{
    case "1":
        
        break;
        case "2":
            Kitchen.Ren ren = new(); // One way to do it
        ren.Meal();
        break;
    default:
        break;
}
class Kitchen
{
    public class Ren
    {
        public void Meal()
        {
            Console.WriteLine("OK Meal");
        }
    }
}

如何从主机上调用公共课程?

苏别ゝ 2025-02-14 06:38:57

绘制了您的节点,但 nx.spectral_layout 将它们彼此放置。

如果您打印了位置:

pos = nx.spectral_layout(G)
print(pos)

您得到:

{0: array([0.00927318, 0.01464153]), 1: array([0.00927318, 0.01464153]), 2: array([0.00927318, 0.01464153]), 3: array([0.00927318, 0.01464153]), 4: array([0.00927318, 0.01464153]), 5: array([-1.        , -0.86684471]), 6: array([-1.        , -0.86684471]), ...

并且可以通过比较位置看到重叠。

相反,您可以使用 nx.circular_layout 如果要查看所有节点:

fig=plt.figure(figsize=(16,12))
pos = nx.circular_layout(G)
nx.draw(G, pos, nodelist=nodes,node_size=40)

并且您将获得:

Your nodes are being drawn but the the nx.spectral_layout positions them on top of each other.

If you print the positions:

pos = nx.spectral_layout(G)
print(pos)

You get:

{0: array([0.00927318, 0.01464153]), 1: array([0.00927318, 0.01464153]), 2: array([0.00927318, 0.01464153]), 3: array([0.00927318, 0.01464153]), 4: array([0.00927318, 0.01464153]), 5: array([-1.        , -0.86684471]), 6: array([-1.        , -0.86684471]), ...

And you can already see the overlap by comparing the positions.

You could instead use nx.circular_layout if you want to see all the nodes:

fig=plt.figure(figsize=(16,12))
pos = nx.circular_layout(G)
nx.draw(G, pos, nodelist=nodes,node_size=40)

And you will get:

enter image description here

NetworkX未显示数据框中的所有节点

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