URLSearchParams.getAll() - Web APIs 编辑

The getAll() method of the URLSearchParams interface returns all the values associated with a given search parameter as an array. 

Note:

Syntax

URLSearchParams.getAll(name)

Parameters

name

The name of the parameter to return.

Return value

An array of USVStrings.

Examples

let url = new URL('https://example.com?foo=1&bar=2');
let params = new URLSearchParams(url.search.slice(1));

//Add a second foo parameter.
params.append('foo', 4);

console.log(params.getAll('foo')) //Prints ["1","4"].

Specifications

Browser compatibility

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