Godot读了嵌套词典

Question

我正在尝试在Nest词典中访问项目。硬编码是很好的dict [string_1] [string_1a]，但是当用户选择UI中的项目并向下钻探时，我不确定如何“关注”它们。我有一个小lendedit，可以显示诸如String_1/String_1之类的路径（类似于计算机显示文件夹的方式）。但是，如果我想创建一个新项目，例如[string_1] [string_1b]，我不确定该怎么做。我能够用路径[string_1] [string_1b]打印字符串，但是我不知道如何将其实际添加到字典中，因为我无法做str2var（我知道），我可以t只需传递字符串_1b，就必须在String_1内部。

func update_path(object, full_path):
    var new_path = ""
    
    full_path.insert(0, object.get_text(0))
    new_path = object.get_parent()
    
    if new_path != null:
        update_path(new_path, full_path)
    
    else:
        pathEdit.text =  ""
        
        # for some stupid reason I can't remove 0, it throws an error
        for item in full_path:
            if item != "":
                pathEdit.text += item + "/"

    print("saving subcategory")
    print(pathEdit.text)
    
    var save_path= pathEdit.text.split("/")
    print(save_path)
    
    var dumb_string = "Globals.notebook_data"
    
    for path in save_path:
        if path != "":
            print(path)
            #print(Globals.notebook_data[path])
            #print(Globals.notebook_data[save_path])
            #print("Globals.notebook_data"+ )
            dumb_string += "[" + path + "]"
    
    print(dumb_string)
    print(str2var(dumb_string))

字符串是正确的路径，我只是不知道如何“访问”它。我正在考虑循环浏览数组，但是我不确定如何处理它，如果我只是访问该级别，它就不会使字典保持整体。

Answer 1

找到答案，需要递归保存。

https://godotengengine.orgg/qa/ 81247/by-a-dictionary-by-titerrating-on-it-its-keys

func set_path(path, value):
    var keypath: PoolStringArray = ["key1","key1_1","key1_1_1","foo"] 
    _set_path(dictionary,keypath,value)

func _set_path(dict,keypath, value):
    var current = keypath[0]
    if dict.has(current):
        if typeof(dict[current]) == TYPE_DICTIONARY:
            keypath.remove(0)
            _set_path(dict[current],keypath, value) # recursion happens here
            return
        else:
            print_debug("found")
            dict[current] = value
            return
    print_debug("not found")