JS中的守护程序
我正在编写一个node.js库，该库需要设置才能运行。如果在5秒内未运行设置功能，我已经使用SettiMeout显示了警告。
但是，这使程序在退出之前等待5秒钟，即使所有其他代码都已完成。
我想显示一条警告消息，如果尚未调用设置功能，并且该程序在5秒后仍在运行。有没有办法使用香草JS来做到这一点？
const done = new Event(); // Event is a simple class I made for a one-time event multicast
function setup() {
done.emit();
}
const timeoutHandle = setTimeout(() => showWarning(), 5000);
done.subscribe(() => {
clearTimeout(timeoutHandle);
});
console.log("The program should end here");
// The program keeps going for 5 seconds even after the last statement
I am writing a node.js library that requires setup in order to run. I have used setTimeout to show a warning if the setup function isn't run within 5 seconds.
However, this makes the program wait for 5 seconds before exiting, even if all the other code is finished.
I want to show a warning message iff the setup function hasn't been called and the program is still running after 5 seconds. Is there a way to do this with vanilla JS?
const done = new Event(); // Event is a simple class I made for a one-time event multicast
function setup() {
done.emit();
}
const timeoutHandle = setTimeout(() => showWarning(), 5000);
done.subscribe(() => {
clearTimeout(timeoutHandle);
});
console.log("The program should end here");
// The program keeps going for 5 seconds even after the last statement
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您可以利用
timeout ute> timeout.unref（）：因此
const timeouthandle = settimeout（（）=＆gt; showwarning（），5000）; timeouthandle.unref（）;这将阻止
settimeout保持该过程活动。You can utilize
timeout.unref():So
const timeoutHandle = setTimeout(() => showWarning(), 5000); timeoutHandle.unref();This will prevent the
setTimeoutto keep the process active.