获取“错误”除非 - python

Question

我得到了一种错误messagge，我不应该使用“裸露的...” 我必须检查第三个charachter是一个点（'。'）的“文本文件的行”（保存在RAW_RESULTS ...）中。 有其他方法避免使用尝试...除外吗？

THX寻求帮助

with open(file_to_read, 'r') as fi:
    raw_results = fi.readlines()

date_of_game = []
home_team = []
away_team = []
home_team_goals = []
away_team_goals = []

for i in range(len(raw_results)):
    try:
        if raw_results[i][2] == '.':
            date_of_game.append(raw_results[i][:5])
            if raw_results[i + 1] != "A Tav.":
                home_team.append(raw_results[i + 1].strip('\n'))
                away_team.append(raw_results[i + 2].strip('\n'))
                home_team_goals.append(raw_results[i + 3].strip('\n'))
                away_team_goals.append(raw_results[i + 4].strip('\n'))
            else:
                home_team.append(raw_results[i + 2].strip('\n'))
                away_team.append(raw_results[i + 3].strip('\n'))
                home_team_goals.append(raw_results[i + 4].strip('\n'))
                away_team_goals.append(raw_results[i + 5].strip('\n'))
    except:
        ''' ... do nothing '''

Answer 1

解决裸露的异常错误：
您可以添加

except Exception as error :
   print(error)
   continue

以继续循环