使用此代码,我将如何打印功能的价值,“ shout”&quot?

发布于 2025-02-13 23:07:46 字数 247 浏览 4 评论 0原文

def shout(phrase):
    if phrase == phrase.upper():
        return ("YOU'RE TOO LOUD")
    else:
        return ("Can you speak up, I can barely hear you")

shout("I'M INTERESTED IN SHOUTING")
def shout(phrase):
    if phrase == phrase.upper():
        return ("YOU'RE TOO LOUD")
    else:
        return ("Can you speak up, I can barely hear you")

shout("I'M INTERESTED IN SHOUTING")

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评论(2

你另情深 2025-02-20 23:07:48

您只需要在打印语句中包装函数调用即可。

def shout(phrase): 
    if phrase == phrase.upper(): 
        return ("YOU'RE TOO LOUD") 
    else: 
        return ("Can you speak up, I can barely hear you")

print(shout('hello'))
print(shout('HELLO'))

# Can you speak up, I can barely hear you
# YOU'RE TOO LOUD

You just need to wrap the function call in a print statement.

def shout(phrase): 
    if phrase == phrase.upper(): 
        return ("YOU'RE TOO LOUD") 
    else: 
        return ("Can you speak up, I can barely hear you")

print(shout('hello'))
print(shout('HELLO'))

# Can you speak up, I can barely hear you
# YOU'RE TOO LOUD
吾性傲以野 2025-02-20 23:07:48

用print()函数替换返回

def shout(phrase):
    if phrase == phrase.upper():
        print("YOU'RE TOO LOUD")
    else:
        print("Can you speak up, I can barely hear you")

shout("I'M INTERESTED IN SHOUTING")

Replace return with the print() function

def shout(phrase):
    if phrase == phrase.upper():
        print("YOU'RE TOO LOUD")
    else:
        print("Can you speak up, I can barely hear you")

shout("I'M INTERESTED IN SHOUTING")
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