如何监视和测试是否“ Usenavigate”是否方法称为或不称为React-Router-dom软件包

发布于 2025-02-13 22:58:53 字数 1014 浏览 2 评论 0原文

我正在尝试添加React-Router-Dom软件包的“ Usenavigate”方法,以测试其在导航时是否被调用。但是我会遇到此错误“ TypeError:不能重新定义属性:USENAVIGATE”

app.js

const navigate = useNavigate();
.......
return (
 <a href="" data-testid={recipe.id} onClick={() => {
    console.log("called");
    navigate(`/recipes/edit/${recipe.id}`, {state: {recipe: recipe}});
    }}>
    Edit
 </a>

app.test.js,

import * as ReactRouterDom from "react-router-dom";

const useNavigateSpy = jest.spyOn(ReactRouterDom, "useNavigate");

it("clicking on edit takes to edit view", async() => {
    useNavigateSpy.mockImplementation(() => jest.fn());
    
    await act(async () =>
      render(<BrowserRouter>
        <List />
      </BrowserRouter>));

      const user = userEvent.setup();
      await user.click(screen.getByTestId("R1"));

      expect(useNavigateSpy).toHaveBeenCalled();

  });

我可以看到“呼叫”正在打印,所以单击是有效的,但是是的,我无法测试是否navegate是被打电话。

任何指导都将真正有用。

I am trying to add spy on "useNavigate" method of react-router-dom package to test whether its being called or not on navigation. But I am getting this error "TypeError: Cannot redefine property: useNavigate"

app.js

const navigate = useNavigate();
.......
return (
 <a href="" data-testid={recipe.id} onClick={() => {
    console.log("called");
    navigate(`/recipes/edit/${recipe.id}`, {state: {recipe: recipe}});
    }}>
    Edit
 </a>

app.test.js

import * as ReactRouterDom from "react-router-dom";

const useNavigateSpy = jest.spyOn(ReactRouterDom, "useNavigate");

it("clicking on edit takes to edit view", async() => {
    useNavigateSpy.mockImplementation(() => jest.fn());
    
    await act(async () =>
      render(<BrowserRouter>
        <List />
      </BrowserRouter>));

      const user = userEvent.setup();
      await user.click(screen.getByTestId("R1"));

      expect(useNavigateSpy).toHaveBeenCalled();

  });

I can see that that "called" is getting printed, so click is working but yes I am not able to test if navigate is getting called or not.

Any guidance will be really useful.

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卸妝后依然美 2025-02-20 22:58:53

您可以在不监视Usenavigate的情况下做到这一点,而是通过嘲笑它。这是您可以做到的(例如用打字稿):

import { render, screen } from '@testing-library/react';
import userEvent from '@testing-library/user-event';
import { BrowserRouter, useNavigate } from 'react-router-dom';

jest.mock('react-router-dom', () => ({
    ...jest.requireActual('react-router-dom'),
    useNavigate: jest.fn(),
}));

const mockedUseNavigate = useNavigate as jest.MockedFunction<typeof useNavigate>;

describe('List', () => {
  test("clicking on edit takes to edit view", async() => {
      const navigate = jest.fn().mockImplementation((to: string) => console.log(to));

      mockedUseNavigate.mockImplementationOnce(() => navigate);

      render(<BrowserRouter>
        <List />
      </BrowserRouter>);

      await userEvent.click(screen.getByTestId("R1"));

      expect(navigate).toHaveBeenCalledTimes(1);
      expect(navigate).toHaveBeenCalledWith('someTestPath');

  });
});

我用来提出此响应的资源:
https://stackoverflow.com/a/66950016

You can do that without spying on useNavigate but by mocking it. Here is how you can do it (example with TypeScript):

import { render, screen } from '@testing-library/react';
import userEvent from '@testing-library/user-event';
import { BrowserRouter, useNavigate } from 'react-router-dom';

jest.mock('react-router-dom', () => ({
    ...jest.requireActual('react-router-dom'),
    useNavigate: jest.fn(),
}));

const mockedUseNavigate = useNavigate as jest.MockedFunction<typeof useNavigate>;

describe('List', () => {
  test("clicking on edit takes to edit view", async() => {
      const navigate = jest.fn().mockImplementation((to: string) => console.log(to));

      mockedUseNavigate.mockImplementationOnce(() => navigate);

      render(<BrowserRouter>
        <List />
      </BrowserRouter>);

      await userEvent.click(screen.getByTestId("R1"));

      expect(navigate).toHaveBeenCalledTimes(1);
      expect(navigate).toHaveBeenCalledWith('someTestPath');

  });
});

The resources I used to come up with this response:
https://stackoverflow.com/a/66950016

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