Elifs条件在我的计划中不起作用

Question

这是我的代码，需要许多密码子。密码子是一组三个核苷酸，每个核苷酸都编码为氨基酸
codon_sequence = []

print（“您想要的密码子no。输入”）

n = int（input（））

for range（n）中的i：

codon=str(input())

codon_sequence.append(codon)

print（codon_sequence）

for range（n）中的i：

if(codon_sequence[i]=="UUU" or "UUC" or "TTT" or "TTC"):

    print("Phe_")

elif(codon_sequence[i]=="UUA" or "UUG" or "CUU" or "CUC" or "CUG" or "CUA" or "TTA" or "TTG" or "CTT" or "CTC" or "CTG" or "CTA"):

    print("Leu_")

elif(codon_sequence[i]=="UCU" or "UCC" or "UCG" or "UCA" or "AGU" or "AGC" or "TCT" or "TCC" or "TCG" or "TCA" or "AGT" or "AGC"):

    print("Ser_")

elif(codon_sequence[i]=="UAU" or "UAC" or "TAT" or "TAC"):

    print("Tyr_")

elif(codon_sequence[i]=="UGU" or "UGC" or "TGT" or "TGC"):

    print("Cys_")

elif(codon_sequence[i]=="UGG" or "TGG"):

    print("Trp_")

elif(codon_sequence[i]=="CCU" or "CCC" or "CCA" or "CCG" or "CCT"):

    print("Pro_")

elif(codon_sequence[i]=="CGU" or "CGC" or "CGA" or "CGG" or "AGA" or "AGG" or "CGT"):

    print("Arg_")

elif(codon_sequence[i]=="CAU" or "CAC" or "CAT"):

    print("His_")

elif(codon_sequence[i]=="CAA" or "CAG"):

    print("Gln_")

elif(codon_sequence[i]=="AUU" or "AUC" or "AUA" or "ATT" or "ATC" or "ATA"):

    print("Ile_")

elif(codon_sequence[i]=="AUG"):

    print("Met_")

elif(codon_sequence[i]=="ACU" or "ACC" or "ACA" or "ACG" or "ACT"):

    print("Thr_")

elif(codon_sequence[i]=="GUU" or "GUC" or "GUA" or "GUG" or "GTT" or "GTC" or "GTA" or "GTG"):

    print("Val_")

elif(codon_sequence[i]=="GCU" or "GCC" or "GCA" or "GCG" or "GCT"):

    print("Ala_")

elif(codon_sequence[i]=="GGU" or "GGC" or "GGA" or "GGG" or "GGT"):

    print("Gly_")

elif(codon_sequence[i]=="GAU" or "GAC" or "GAT"):

    print("Asp_")

elif(codon_sequence[i]=="GAA" or "GAG"):

    print("Glu_")

elif(codon_sequence[i]=="AAU" or "AAC" or "AAT"):

    print("Asn_")

elif(codon_sequence[i]=="AAA" or "AAG"):

    print("Lys_")

else:

    print("Stop_")

但是，这是给我的结果仅是“ phe_”，而忽略了所有其他条件

Answer 1

这将是Switch语句的绝佳候选人，但是正如先前的答案所述，您不能像您一样在每个字符串之间放置“或”。

Answer 2

您的代码没有击中elif阻止

您的 和elif块的原因。

它应该检查codon_sequence [i]等于兴趣的字符串。

if(codon_sequence[i]=="UUU" or codon_sequence[i]=="UUC" or codon_sequence[i]=="TTT" or codon_sequence[i]=="TTC"):

取而代
如果条件始终为 true 。
，这将导致第一个。
因此，您永远不会击中elif块。

如果语句是：编写的更好方法是：

if codon_sequence[i] in ["UUU", "UUC", "TTT", "TTC"]:
    print("Phe_")