如何使用Google功能连接到Google存储

Question

我正在尝试执行一项快速解析和清洁数据的快速自动化任务，例如：

• 当数据输入bucket1函数会自动启动
• 数据时，将被解析，清洁，如果我这样说，
• 数据将保存到bucket2，

所以我选择了Google功能触发了通过Bucket1的更改，但是现在我无法访问Bucket1的文件，知道我在做什么错？

import pandas as pd
import glob
from google.cloud import storage
storage_client = storage.Client(project='MyProjectName')

paths = []
all_dfs = []

def hello_gcs(event, context):
    #"""Triggered by a change to a Cloud Storage bucket.
    #Args:
    #     event (dict): Event payload.
    #     context (google.cloud.functions.Context): Metadata for the event.
    #"""
    #file = event
    #print(f"Processing file: {file['name']}.")

    for files in glob.glob("gs:/BUCKET1/*/*.csv"):
        paths.append(files)
    print(paths)
    print("testingtesting")
    for i in range(len(paths)):

    temp_list = (paths[i].split("_"))
    date_temp_list = (temp_list[2])
    read_date = (date_temp_list.split("T")[0])

    globals()['table%s' % i] = pd.read_csv('{}' .format(paths[i]), index_col=None, header=0) #create new dfs based on subfolder structure
    globals()['table%s' % i]["Read Date"] = read_date
    all_dfs.append(globals()['table%s' % i])

output_df = pd.concat(all_dfs, axis=0, ignore_index=True)
output_df.to_csv("gs:/BUCKET2/Filename.csv")

该代码在Jupyter笔记本电脑中本地执行，但是在Google功能中执行时，它甚至不会加载“路径”（因此我是在print（路径）检查（路径）并返回一个空列表。如何更好地访问GS？