从循环中的文件中添加并删除字节

发布于 2025-02-13 20:36:32 字数 421 浏览 2 评论 0原文

我是一名安全研究人员，想知道如何从文件中删除添加的字节。下面的此功能每4个字节添加一个字节。但是我想知道如何也可以删除这些字节。需要一个可以按添加的顺序删除这些字节的函数。

特拉维斯

int AddByte(BYTE* bIn, BYTE* bOut, DWORD dwSize, int inc_every)
{
    int increased = 0;

    for (int i = 0; i < dwSize; i++)
    {
        *(bOut + increased) = *(bIn + i);
        increased++;

        if (i % inc_every == 0)
            increased += 1;
    }

    return increased;
}

原文

I'm a security researcher and am wondering how I could remove the added bytes from a file. This function below adds a byte every 4 bytes. But I'd like to know how I could remove those bytes as well. Need a function that will remove these bytes in the order they were added.

Travis

int AddByte(BYTE* bIn, BYTE* bOut, DWORD dwSize, int inc_every)
{
    int increased = 0;

    for (int i = 0; i < dwSize; i++)
    {
        *(bOut + increased) = *(bIn + i);
        increased++;

        if (i % inc_every == 0)
            increased += 1;
    }

    return increased;
}

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a√萤火虫的光℡ 2025-02-20 20:36:32

int RemoveByte(BYTE* bIn, BYTE* bOut, DWORD dwSize, int inc_every)
{
    int increased = 0;

    for (int i = 0; i < dwSize; i++)
    {

        if ((i - 1) % inc_every != 0)
        {
             *(bOut + increased) = *(bIn + i);
            increased++;
        }
    }

    return increased;
}

在addByte（）后应用此功能将回馈原始字符串。您的原始功能的偏移为1（它将跳过第二个字节），因此此功能包含相同的偏移

int RemoveByte(BYTE* bIn, BYTE* bOut, DWORD dwSize, int inc_every)
{
    int increased = 0;

    for (int i = 0; i < dwSize; i++)
    {

        if ((i - 1) % inc_every != 0)
        {
             *(bOut + increased) = *(bIn + i);
            increased++;
        }
    }

    return increased;
}

Applying this function after AddByte() would give back the original string. Your original function has an offset of 1 (it will skip the second byte), so this function includes the same offset

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