返回类型＆＃x27;对象＆＃x27; Isn; ta; ta; ta; widget; widget;

发布于 2025-02-13 19:34:48 字数 1450 浏览 0 评论 0原文

我尝试使用list.generate构建，但它们有错误的返回类型“对象”不是“窗口小部件”，这是封闭情况下的要求。但是，当我使用listView.builder时，我的应用程序正常工作。

Here my code
    List.generate(
                        data.length,
                        (index) {
                          return GestureDetector(
                            child: Padding(
                              padding: const EdgeInsets.only(
                                  bottom: 20, left: 20, right: 20),
                              child: CustomPromotionNew(
                                thumbNail: (snapshot.data as List)[index].imgUrl,
                                title:
                                    (snapshot.data as List)[index].promotionName,
                              ),
                            ),
                            onTap: () {
                              Navigator.push(
                                  context,
                                  MaterialPageRoute(
                                    builder: (context) =>
                                        PromotionNewsDetailScreen(
                                            items:
                                                (snapshot.data as List)[index]),
                                  ));
                            },
                          );
                        },)
 : const Center(
                          child: CircularProgressIndicator(),
                        );

原文

I try to build with List.generate but they has error The return type 'Object' isn't a 'Widget', as required by the closure's context. But when i use ListView.builder, my application work fine.

Here my code
    List.generate(
                        data.length,
                        (index) {
                          return GestureDetector(
                            child: Padding(
                              padding: const EdgeInsets.only(
                                  bottom: 20, left: 20, right: 20),
                              child: CustomPromotionNew(
                                thumbNail: (snapshot.data as List)[index].imgUrl,
                                title:
                                    (snapshot.data as List)[index].promotionName,
                              ),
                            ),
                            onTap: () {
                              Navigator.push(
                                  context,
                                  MaterialPageRoute(
                                    builder: (context) =>
                                        PromotionNewsDetailScreen(
                                            items:
                                                (snapshot.data as List)[index]),
                                  ));
                            },
                          );
                        },)
 : const Center(
                          child: CircularProgressIndicator(),
                        );

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情话难免假 2025-02-20 19:34:48

您会遇到此错误，因为您已定义了列表中的widget树类型。而不是您需要定义ListView。为了解决此错误，您需要在代码下方放置

ListView.builder(
        itemCount: data.length,
          itemBuilder: (context, i) {
            return GestureDetector(
              child: Padding(
                padding: const EdgeInsets.only(
                    bottom: 20, left: 20, right: 20),
                child: CustomPromotionNew(
                  thumbNail: (snapshot.data as List)[index].imgUrl,
                  title:
                  (snapshot.data as List)[index].promotionName,
                ),
              ),
              onTap: () {
                Navigator.push(
                    context,
                    MaterialPageRoute(
                      builder: (context) =>
                          PromotionNewsDetailScreen(
                              items:
                              (snapshot.data as List)[index]),
                    ));
              },
            );
          },)
            : const Center(
        child: CircularProgressIndicator(),
    )

You getting this error because you have defined list type in widget tree. instead of that you need to define listview. For solve this error you need to put below code

ListView.builder(
        itemCount: data.length,
          itemBuilder: (context, i) {
            return GestureDetector(
              child: Padding(
                padding: const EdgeInsets.only(
                    bottom: 20, left: 20, right: 20),
                child: CustomPromotionNew(
                  thumbNail: (snapshot.data as List)[index].imgUrl,
                  title:
                  (snapshot.data as List)[index].promotionName,
                ),
              ),
              onTap: () {
                Navigator.push(
                    context,
                    MaterialPageRoute(
                      builder: (context) =>
                          PromotionNewsDetailScreen(
                              items:
                              (snapshot.data as List)[index]),
                    ));
              },
            );
          },)
            : const Center(
        child: CircularProgressIndicator(),
    )

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