列表guilds discord.py

发布于 2025-02-13 17:31:47 字数 380 浏览 0 评论 0原文

这是我的代码：

@client.event
async def on_ready():
    print('CONSOLE: We have logged in as {0.user}'.format(client))

      async def serverList():
        for guild in client.guilds:
          print(guild.id)

client.run(token)

I am trying to list the guild/servers the bot is in but this code does not work

原文

This is my code:

@client.event
async def on_ready():
    print('CONSOLE: We have logged in as {0.user}'.format(client))

      async def serverList():
        for guild in client.guilds:
          print(guild.id)

client.run(token)

I am trying to list the guild/servers the bot is in but this code does not work

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真心难拥有 2025-02-20 17:31:47

为了使您的代码工作要工作，您需要删除行async def serverlist（）：和正确的凹痕，因此循环的与第一个级别相同print（'console ...

@client.event
async def on_ready():
    print('CONSOLE: We have logged in as {0.user}'.format(client))

    for guild in client.guilds:
        print(guild.id)

client.run(token)

代码可能是由于划痕错误而无法运行的 - 您在async def serverlist（）中都有额外的不必要缩进，

或者如果有问题guild.id s不会打印，然后发生，因为您使用async def定义功能，但最终不会在代码中使用它。

In order to get your code to work you need to delete the line async def serverList(): and correct indents so the for loop is on the same level with the very first print('CONSOLE...

@client.event
async def on_ready():
    print('CONSOLE: We have logged in as {0.user}'.format(client))

    for guild in client.guilds:
        print(guild.id)

client.run(token)

Code does not run probably because of wrong indents - you have an extra unnecessary indent in your async def serverList(),

or if the problem that guild.ids do not get printed then is happening because you define the function with async def but you don't end up using it in your code.

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