Golang，解析XML网站
当我尝试解析XML站点时，对我无济于事，输出“ []”。结果，我决定下载本网站的XML文件，然后删除后 ＆lt;？XML版本=“ 1.0” encoding =“ Windows-1251”？＆gt;，然后一切都对我有用。是否可以以某种方式读取数据而不删除此片段？
type ValCurs struct {
XMLName xml.Name `xml:"ValCurs"`
Date string `xml:"Date, attr"`
Name string `xml:"name, attr"`
Valute []Valute `xml:"Valute"`
}
type Valute struct {
XMLName xml.Name `xml:"Valute"`
CharCode string `xml:"CharCode"`
Nominal string `xml:"Nominal"`
Name string `xml:"Name"`
Value string `xml:"Value"`
}
func main() {
resp, _ := http.Get("http://www.cbr.ru/scripts/XML_daily.asp")
defer resp.Body.Close()
req, _ := ioutil.ReadAll(resp.Body)
var val ValCurs
xml.Unmarshal(req, &val)
fmt.Println(val)
}
When I try to parse the xml site, nothing works for me and output "[]" . As a result, I decided to download the xml file of this site, and after I remove<?xml version="1.0" encoding="windows-1251"?>, then everything works out for me. Is it possible to somehow read the data without deleting this fragment?
type ValCurs struct {
XMLName xml.Name `xml:"ValCurs"`
Date string `xml:"Date, attr"`
Name string `xml:"name, attr"`
Valute []Valute `xml:"Valute"`
}
type Valute struct {
XMLName xml.Name `xml:"Valute"`
CharCode string `xml:"CharCode"`
Nominal string `xml:"Nominal"`
Name string `xml:"Name"`
Value string `xml:"Value"`
}
func main() {
resp, _ := http.Get("http://www.cbr.ru/scripts/XML_daily.asp")
defer resp.Body.Close()
req, _ := ioutil.ReadAll(resp.Body)
var val ValCurs
xml.Unmarshal(req, &val)
fmt.Println(val)
}
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好吧，也许我已经弄清楚了，但是我不确定我是否做得正确。
我安装了Charmap软件包“ github.com/aglyzov/charmap”
并切断BYTS
之后，一切都按照我想要的
Okay, maybe I figured it out, but I'm not sure if I did everything right.
I installed charmap package "github.com/aglyzov/charmap"
And cut off the byts
After that everything works as I would like