Julia QPDA：无匹配四边形的方法

Question

我正在尝试通过软件包QPDA解决数学问题。毫无疑问，每当我称之为此操作时，我都会收到以下错误：

    ERROR: LoadError: MethodError: no method matching QuadraticProgram(::Array{Float64,2}, ::Array{Float64,1}, ::Array{F loat64,2}, ::Array{Float64,1}, ::Array{Float64,1}, ::UniformScaling{Bool}; z=[1.0, 1.0, 1.0, 1.0, 1.0, 1.0], P=[5.0 9.0 … -6.0 -10.0; 9.0 17.0 … -8.0 -16.0; … ; -6.0 -8.0 … 17.0 19.0; -10.0 -16.0 … 19.0 25.0], semidefinite=true, ϵ=1.4901161193847656e-8, smartstart=true, scaling=true)
Closest candidates are:
  QuadraticProgram(::MT, ::VT, ::MT, ::VT, ::VT, ::Any; semidefinite, ϵ, smartstart, scaling) where {T, VT<:AbstractArray{T,1}, MT<:AbstractArray{T,2}} at .../.julia/packages/QPDAS/CvMCc/src/quadraticProgram.jl:38 got unsupported keyword arguments "z", "P"
  QuadraticProgram(::MT, ::VT, ::MT, ::VT, ::VT) where {T, VT<:AbstractArray{T,1}, MT<:AbstractArray{T,2}} at .../.julia/packages/QPDAS/CvMCc/src/quadraticProgram.jl:38 got unsupported keyword arguments "z", "P", "semidefinite", "ϵ", "smartstart", "scaling"
  QuadraticProgram(::MT, !Matched::MT, !Matched::VT, ::VT, ::VT, ::PT, !Matched::PFT, !Matched::VT, !Matched::VT, !Matched::Bool, !Matched::VT, !Matched::VT, !Matched::BoxConstrainedQP{T,GT,VT}) where {T, GT<:(QPDAS.AbstractCholeskySpecial{T,MT} where MT), VT<:AbstractArray{T,1}, MT<:AbstractArray{T,2}, PT, PFT} at .../.julia/packages/QPDAS/CvMCc/src/quadraticProgram.jl:22 got unsupported keyword arguments "z", "P", "semidefinite", "ϵ", "smartstart", "scaling"

这是我的代码：

function getSolution(points)    # array of tuples with a tuple and an Int64
    A = [points[i][2] for i=1:length(points)]
    A = reshape(A, 1, length(points))
    b = [0.0 for i=1:length(points)]
    C = diagm(-1 .* ones(length(points)))
    d = b
    M = constructMatrix(points)

    qp = QuadraticProgram(A, b, C, d, z = ones(length(points)), P = M;
            semidefinite = true, ϵ = sqrt(eps(Float64)), smartstart = true, scaling = true)

    sol, val = solve!(qp)
    return sol
end

我知道它的类型我的变量类型与方法QuadraticProgram所期望的变量不匹配，但是我可以't以什么方式弄清楚。 类型

matrix, vector, matrix, vector, vector, any; semidefinite, ϵ, smartstart, scaling

在我的理解中，它期望我应该拥有的 。我在做什么错？

Answer 1

第一个“候选”方法（长）线的末端说明了问题是什么：

获得了不支持的关键字参数“ z”，“ p”

，即使它们处于正确的位置，也不能按名称传递位置参数。即，在此调用中，

    qp = QuadraticProgram(A, b, C, d, z = ones(length(points)), P = M;
        semidefinite = true, ϵ = sqrt(eps(Float64)), smartstart = true, scaling = true)

z =和p =使其不再被视为位置参数。因此，错误，因为朱莉娅（Julia）试图在匹配这些功能定义中找到关键字参数，并且在其中失败。 （即使无法通过名称传递的位置论据 - 甚至是选择 - 是我与朱莉娅的小宠儿之一。关键字参数的半彩龙定界符是可选的，而是可以成为逗号，也可以使它成为逗号在这种情况下，问题不太明显。）

将该行更改为：

qp = QuadraticProgram(A, b, C, d, ones(length(points)), M;
        semidefinite = true, ϵ = sqrt(eps(Float64)), smartstart = true, scaling = true)

IE只是删除z =和p =应该解决问题并调用正确的方法。