从数组中删除特定对象，然后在同一数组的0索引上移动此对象

Question

我有一个具有多个对象的数组。我只想通过比较标题并在同一数组上的0索引上移动该对象来删除对象。我该怎么做。请建议我解决方案。

输入阵列：

 const inputArr = [{id:1, title:"John",age:20},{id:2, title:"smith",age:22},{id:3, title:"stokes",age:24},{id:4, title:"david",age:30},{id:5, title:"William",age:28},{id:6, title:"Andy",age:32}]

输出数组：

const outputArr = [{id:5, title:"William",age:28},{id:1, title:"John",age:20},{id:2, title:"smith",age:22},{id:3, title:"stokes",age:24},{id:4, title:"david",age:30},{id:6, title:"Andy",age:32}]

用标题=== William从数组中删除对象，然后移动到0索引

Answer 1

您可以简单地使用排序

const inputArr = [{id:1, title:"John",age:20},{id:2, title:"smith",age:22},{id:3, title:"stokes",age:24},{id:4, title:"david",age:30},{id:5, title:"William",age:28},{id:6, title:"Andy",age:32}]


const outputArray =  [...inputArr].sort((a, b) => {
  if(a.title === 'William') return -1
  if(b.title === 'William') return 1
  return a.id - b.id
})


console.log(outputArray)

Answer 2

const inputArr = [{id:1, title:"John",age:20},{id:2, title:"smith",age:22},{id:3, title:"stokes",age:24},{id:4, title:"david",age:30},{id:5, title:"William",age:28},{id:6, title:"Andy",age:32}];

// `findIndex` of the appropriate object
const index = inputArr.findIndex(obj => obj.title === 'William');

// `splice` out the object and then `unshift` it
// to the start of the array (Note: we don't have
// to make any changes if the index is 0)
if (index > 0) {
  inputArr.unshift(inputArr.splice(index, 1));
}

console.log(inputArr);

附加文档

• splice> splice

• 
  

Answer 3

const inputArr = [{id:1, title:"John",age:20},{id:2, title:"smith",age:22},{id:3, title:"stokes",age:24},{id:4, title:"david",age:30},{id:5, title:"William",age:28},{id:6, title:"Andy",age:32}]
    
    const getTitle = inputArr.filter((item) => item.title === 'William')
    const getRest = inputArr.filter((item) => item.title !== 'William')
    
    
    console.log(getTitle.concat(getRest))