用工人的意图开始活动，在某些设备上不起作用

发布于 2025-02-13 11:51:06 字数 1556 浏览 2 评论 0原文

我正在尝试使用Worker使用Workmanager API在应用程序在后台时仅在特定时间/日期打开一次活动，它在我的模拟器中确实可以工作在Android 12上，但是当我在Redmi Note 8手机上运行它时，它并没有打开活动，尽管工人正常在同一手机上工作
openActivityWorker.kt

class OpenActivityWorker(val context: Context, private val workerParameters: WorkerParameters) : Worker(context, workerParameters) {
    @OptIn(DelicateCoroutinesApi::class)
    override fun doWork(): Result {
        Handler(Looper.getMainLooper()).post(Runnable {
            val intent = Intent(context, MainActivity::class.java)
            intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK)
            val res = context.startActivity(intent)
            Log.d("OpenActivityWorker", "doWork: $res")
        })
        return Result.success()
    }
}

，我注册了以下内容：

val oneTimeWorkRequestActivity = OneTimeWorkRequest.Builder(OpenActivityWorker::class.java)
            .setInitialDelay(SOME_MILLIS,
                TimeUnit.MILLISECONDS
            )
            .setInputData(
                Data.Builder()
                    .putLong("startAt", SOME_MILLIS)
                    .putLong("id", SOME_ID)
                    .build()
            )
            .build()

WorkManager.getInstance(requireContext()).enqueueUniqueWork(
            "$SOME_ID",
            ExistingWorkPolicy.REPLACE,
            oneTimeWorkRequestActivity
        )

如何解决此问题，并且是否需要某种许可，我需要要求能够从workmanager ？

原文

I am trying to implement a Worker using WorkManager API to open an activity only once on a specific time/date when the app is in background, It does work in my emulator even on Android 12 but when I run it on my Redmi note 8 phone it does not open the activity although the workers are working normally on the same phone
OpenActivityWorker.kt

class OpenActivityWorker(val context: Context, private val workerParameters: WorkerParameters) : Worker(context, workerParameters) {
    @OptIn(DelicateCoroutinesApi::class)
    override fun doWork(): Result {
        Handler(Looper.getMainLooper()).post(Runnable {
            val intent = Intent(context, MainActivity::class.java)
            intent.addFlags(Intent.FLAG_ACTIVITY_NEW_TASK)
            val res = context.startActivity(intent)
            Log.d("OpenActivityWorker", "doWork: $res")
        })
        return Result.success()
    }
}

And I register the worker as follows:

val oneTimeWorkRequestActivity = OneTimeWorkRequest.Builder(OpenActivityWorker::class.java)
            .setInitialDelay(SOME_MILLIS,
                TimeUnit.MILLISECONDS
            )
            .setInputData(
                Data.Builder()
                    .putLong("startAt", SOME_MILLIS)
                    .putLong("id", SOME_ID)
                    .build()
            )
            .build()

WorkManager.getInstance(requireContext()).enqueueUniqueWork(
            "$SOME_ID",
            ExistingWorkPolicy.REPLACE,
            oneTimeWorkRequestActivity
        )

How to solve this, and is there some kind of permission I need to ask for to be able to start the activities from WorkManager?

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愛上了 2025-02-20 11:51:06

在您的第一个代码块中，您什么时候打电话给此行？

class OpenActivityWorker(val context: Context, private val workerParameters: WorkerParameters) : Worker(context, workerParameters) {
...
override fun doWork(): Result {
    Handler(Looper.getMainLooper()).post(Runnable {
        ... 
        val res = context.startActivity(intent)
        ...
    })
    return Result.success()
}

将表达式称为以外的变量；

context.startActivity(intent)

In your first code block, when do you call this line?

class OpenActivityWorker(val context: Context, private val workerParameters: WorkerParameters) : Worker(context, workerParameters) {
...
override fun doWork(): Result {
    Handler(Looper.getMainLooper()).post(Runnable {
        ... 
        val res = context.startActivity(intent)
        ...
    })
    return Result.success()
}

Call the expression outside a variable like;