linux bash，只能用grep获取单个单词

发布于 2025-02-13 11:50:58 字数 313 浏览 0 评论 0原文

我有一个很大的文本文件，我必须找到所有的“ knr” - alias。我删除了所有评论和空排：

cat file | grep -v ^# | grep -v ^$ >> Test.txt

我只能得到一个单词，我需要从“ test.txt”文件中写出一个单词？我真的只需要一个单词，它的结构是： “ KNR00000000000000000_THITS” 我不知道这是否可能，但是在这种结构之后。总有一个空间。

我还需要一些帮助，如何使第一行代码在脚本中起作用。

任何帮助将不胜感激。善良的是埃利亚斯

原文

I have a large textfile and I have to find all of the "KNR"-alias. I removed all comments and empty lines with this:

cat file | grep -v ^# | grep -v ^$ >> Test.txt

How can I only get this one word, that I need to write out of the "Test.txt" file?
I really only need one word, which has the structure of:
"KNR00000000000000000_THING"
I don´t know if this is possible, but after that structure. there is always a space.

I also need some help with how to make that first line of code work in a script.

Any help would be very appreciated.
Kind regards Elias

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葬シ愛 2025-02-20 11:50:58

根据注释：

grep -ohE 'KNR[^ ]*' file

将使用grep来匹配您的模式。 [^]表示空间之外的任何内容。

其他可能性是sed：

sed -nE "s/.*(KNR.*) .*/\1/p

或 @f.hauri的

tr < file \  \\n | grep ^KNR

这是假设knr是在空间之后或线路开始时。

As per comments:

grep -ohE 'KNR[^ ]*' file

will use grep to match your pattern as I understand it. [^ ] means anything but a space.

Other possibilities are sed:

sed -nE "s/.*(KNR.*) .*/\1/p

or @F.Hauri's

tr < file \  \\n | grep ^KNR

This assumes that the KNR is either after a space or at the start of a line.

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旧竹 2025-02-20 11:50:58

如果您只需要这个单词并注意，那么

grep -vE '^#|^
如果有几个单词与此模式匹配，您当然可以做一个。
说明：
 -o：仅输出匹配模式的零件

-w：只匹配单词

-e：打开扩展的正则是（以便可以使用+）。
我还修改了您的测试以删除。我的模式以＃＃以及包含零字符的所有行删除所有行。
 file | grep -owE KNR0+_THING

如果有几个单词与此模式匹配，您当然可以做一个。

说明：

-o：仅输出匹配模式的零件
-w：只匹配单词
-e：打开扩展的正则是（以便可以使用+）。

我还修改了您的测试以删除。我的模式以＃＃以及包含零字符的所有行删除所有行。

If you only need this word and noting else, you could do a

grep -vE '^#|^
Of course if there are several words matching this pattern, you get all of them.
Explanation:
-o : Output only the part matching the pattern

-w : Match only words

-E : Turn on extended regex (so that + can be used).
I also modified your test for lines to remove.My pattern removes all lines starting with a #, and those which contain zero characters.
 file | grep -owE KNR0+_THING

Of course if there are several words matching this pattern, you get all of them.

Explanation:

-o : Output only the part matching the pattern
-w : Match only words
-E : Turn on extended regex (so that + can be used).

I also modified your test for lines to remove.My pattern removes all lines starting with a #, and those which contain zero characters.

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