为什么我的方法扫描文件并打印出结果比上一次打印1空间？

Question

我目前正在编写一个很长的代码来重现康威的生活游戏，并且刚刚意识到，当我运行代码时，我通过文件扫描并将其打印出来的方法是因为矩阵无法正常工作。我已经尝试解决它，但无济于事。

public static String[][] originalBoardCreation() {
        Scanner sc= MyUtils.readFile(inpFileName);
        
        width = sc.nextInt();
        height = sc.nextInt();  
        sc.nextLine();
        
        String[][] board = new String[width][height];
        String[] line = new String[board.length];
        
        while (sc.hasNext()) {
            for (int i = 0; i < board.length; i++) {
                line[i] = sc.nextLine().trim();
                
                for (int j = 0; j < line.length; j++) {
                    board[i][j] = line[j];
                }
            }
        } 
        
        return board;
    }

当我使用system.out.println（arrays.deeptoString（oinartionBoardCreation（）））调用Main

[[.xxxxxxxx., null, null, null, null, null, null, null, null, null], [.xxxxxxxx., x.x.x.x.x., null, null, null, null, null, null, null, null], [.xxxxxxxx., x.x.x.x.x., .x.x.x.x.., null, null, null, null, null, null, null], [.xxxxxxxx., x.x.x.x.x., .x.x.x.x.., xxxxxxx..., null, null, null, null, null, null], [.xxxxxxxx., x.x.x.x.x., .x.x.x.x.., xxxxxxx..., .........., null, null, null, null, null], [.xxxxxxxx., x.x.x.x.x., .x.x.x.x.., xxxxxxx..., .........., .........., null, null, null, null], [.xxxxxxxx., x.x.x.x.x., .x.x.x.x.., xxxxxxx..., .........., .........., .........., null, null, null], [.xxxxxxxx., x.x.x.x.x., .x.x.x.x.., xxxxxxx..., .........., .........., .........., ....xxx..., null, null], [.xxxxxxxx., x.x.x.x.x., .x.x.x.x.., xxxxxxx..., .........., .........., .........., ....xxx..., .........., null], [.xxxxxxxx., x.x.x.x.x., .x.x.x.x.., xxxxxxx..., .........., .........., .........., ....xxx..., .........., ..........]]

时x，x，x，x，x，x，x，。]，...等等，但是我不知道为什么会发生这种情况或我的错误逻辑，谢谢！

Answer 1

我相信问题是由于您从文件中读取一行文本并期望将其神奇地 split splin到一个字符串数组中引起的。

public static String[][] originalBoardCreation()
{
  Scanner sc= MyUtils.readFile(inpFileName);

  width = sc.nextInt();
  height = sc.nextInt();  
  sc.nextLine();

  String[][] board = new String[width][height];

  while ( sc.hasNext() )
  {
    for ( int i = 0; i < board.length; i++ )
    {
      String line = sc.nextLine().trim();  // read the text line in
      char tiles[] = line.toCharArray();    // now split the line into an array

      for ( int j = 0; j < tiles.length; j++ )
      {
        board[i][j] = String.valueOf(tiles[j]);  // Now assign the elements to the current row on your board
      }
    }
  } 
  return board;
}

我没有测试过，但是类似的事情应该起作用。