根据日期从同一列中减去值,如果结果为负,请继续使用结果

发布于 2025-02-13 10:23:56 字数 1399 浏览 0 评论 0 原文

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等待我真够勒 2025-02-20 10:23:56

这应该做到!

DROP TABLE YourTable

CREATE TABLE YourTable
(
    Date DATE,
    Value DECIMAL(10, 2)
)
GO

INSERT INTO YourTable
VALUES
('2019-04-12', '2178'),
('2019-05-31', '2178'),
('2020-06-30', '15244.5'),
('2021-09-20', '16498.34'),
('2022-02-02', '-16367.4')

ALTER TABLE YourTable
ADD RowNumber INT NULL
GO

ALTER TABLE YourTable
ADD CalculatedValue DECIMAL(10, 2) NULL
GO

UPDATE A
SET A.RowNumber = A.Ranks
FROM
(
    SELECT RowNumber, ROW_NUMBER() OVER (ORDER BY DATE ASC) AS Ranks
    FROM YourTable
    WHERE Value > 0
) A

UPDATE YourTable
SET CalculatedValue =
(
    SELECT SUM(Value)
    FROM YourTable
    WHERE Value < 0
) + Value
WHERE RowNumber = 1

DECLARE @i INT = 1
DECLARE @iMax INT =
(
    SELECT MAX(RowNumber)
    FROM YourTable
)

WHILE @i <= @iMax
BEGIN
    UPDATE A
    SET A.CalculatedValue = B.CalculatedValue + A.Value
    FROM YourTable A
    JOIN YourTable B ON
        A.RowNumber = @i
        AND B.RowNumber = @i - 1
SET @i = @i + 1
END

UPDATE YourTable
SET CalculatedValue = Value
WHERE RowNumber > 
(
    SELECT MIN(RowNumber)
    FROM YourTable
    WHERE CalculatedValue > 0
)

SELECT Date, CalculatedValue AS 'Value'
FROM YourTable
WHERE CalculatedValue >= 0
ORDER BY RowNumber

This should do it!

DROP TABLE YourTable

CREATE TABLE YourTable
(
    Date DATE,
    Value DECIMAL(10, 2)
)
GO

INSERT INTO YourTable
VALUES
('2019-04-12', '2178'),
('2019-05-31', '2178'),
('2020-06-30', '15244.5'),
('2021-09-20', '16498.34'),
('2022-02-02', '-16367.4')

ALTER TABLE YourTable
ADD RowNumber INT NULL
GO

ALTER TABLE YourTable
ADD CalculatedValue DECIMAL(10, 2) NULL
GO

UPDATE A
SET A.RowNumber = A.Ranks
FROM
(
    SELECT RowNumber, ROW_NUMBER() OVER (ORDER BY DATE ASC) AS Ranks
    FROM YourTable
    WHERE Value > 0
) A

UPDATE YourTable
SET CalculatedValue =
(
    SELECT SUM(Value)
    FROM YourTable
    WHERE Value < 0
) + Value
WHERE RowNumber = 1

DECLARE @i INT = 1
DECLARE @iMax INT =
(
    SELECT MAX(RowNumber)
    FROM YourTable
)

WHILE @i <= @iMax
BEGIN
    UPDATE A
    SET A.CalculatedValue = B.CalculatedValue + A.Value
    FROM YourTable A
    JOIN YourTable B ON
        A.RowNumber = @i
        AND B.RowNumber = @i - 1
SET @i = @i + 1
END

UPDATE YourTable
SET CalculatedValue = Value
WHERE RowNumber > 
(
    SELECT MIN(RowNumber)
    FROM YourTable
    WHERE CalculatedValue > 0
)

SELECT Date, CalculatedValue AS 'Value'
FROM YourTable
WHERE CalculatedValue >= 0
ORDER BY RowNumber

物价感观 2025-02-20 10:23:56

好的。根据假定的要求在这里吐痰

客户根据特定日期购买了未付的购买,将其放置了一个选项卡,然后负数表示付款。如果将付款适用于日期订单债务,则每个日期的剩余余额是多少?

create table t (
  dt date,
  val decimal(8,3)
)

insert t
values 
  ({d '2019-04-12'}, 2178)
, ({d '2019-05-31'}, 2178)
, ({d '2020-06-30'}, 15244.5)
, ({d '2021-09-20'}, 16498.34)
, ({d '2022-02-02'}, -16367.4)

;
with a as (
  select dt
  , val
  , SUM(val) OVER (ORDER BY case when val < 0 then 1 else 2 end, dt ROWS BETWEEN UNBOUNDED PRECEDING AND 1 PRECEDING) as oldbal
  from t
),
b as (
  select dt
  , val + case when oldbal < 0 then oldbal else 0 end as RemainingBalance
  from a
)
select dt as 'DATE'
, RemainingBalance as 'VALUE'
from b
where RemainingBalance > 0
order by dt
;

--  Correct values for comparison
select cast([DATE] as date) as 'DATE'
, VALUE
from (
  values 
    ({d '2020-06-30'}, 3233.1)
  , ({d '2021-09-20'}, 16498.34)
) q ([DATE], [VALUE])

https://dbfiddle.uk/?rdbms = sqlServer_2019&fiddle = 4DE0258C6E670D6D4D7E8B4F717EB82A

OK. Spitballing here based on an assumed requirement

A customer has racked up a tab based on unpaid purchases on specific dates, then the negative numbers indicate payments. If payments are applied to debts in date order, what is the remaining balance from each date?

create table t (
  dt date,
  val decimal(8,3)
)

insert t
values 
  ({d '2019-04-12'}, 2178)
, ({d '2019-05-31'}, 2178)
, ({d '2020-06-30'}, 15244.5)
, ({d '2021-09-20'}, 16498.34)
, ({d '2022-02-02'}, -16367.4)

;
with a as (
  select dt
  , val
  , SUM(val) OVER (ORDER BY case when val < 0 then 1 else 2 end, dt ROWS BETWEEN UNBOUNDED PRECEDING AND 1 PRECEDING) as oldbal
  from t
),
b as (
  select dt
  , val + case when oldbal < 0 then oldbal else 0 end as RemainingBalance
  from a
)
select dt as 'DATE'
, RemainingBalance as 'VALUE'
from b
where RemainingBalance > 0
order by dt
;

--  Correct values for comparison
select cast([DATE] as date) as 'DATE'
, VALUE
from (
  values 
    ({d '2020-06-30'}, 3233.1)
  , ({d '2021-09-20'}, 16498.34)
) q ([DATE], [VALUE])

https://dbfiddle.uk/?rdbms=sqlserver_2019&fiddle=4de0258c6e670d6d4d7e8b4f717eb82a

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