过滤nonn none null值来自Java中的对象

Question

我有一个带有某些端点的应用程序的弹簧靴，其中一个端点是搜索汽车选项，请参阅下面的

@PostMapping("/searchCarOptions")
public ResponseEntity<Cars> search(
        @Parameter(description = "some searchRequest") @RequestBody SearchRequest searchRequest) {

    if (searchRequest.getType() != null) {
        //dosomthing
    }
    
    if (searchRequest.getBrand() != null) {
        //dosomthing
    }
    
    if (searchRequest.getCountry() != null) {
        //dosomthing
    }
    
    if (searchRequest.getClient() != null) {
        //dosomthing
    }
    
    if (searchRequest.getAirco() != null) {
        //dosomthing
    }
    
    etc.....

    return ResponseEntity.ok(someService.search(searchRequest));
}

方法，可以将我的searchRequest放在方法中，然后返回填充的搜索条件，例如将其放入字符串中多变的？它将使代码清洁器。...

下面是我的模型

public class SearchRequest {

    private String type;
    private String brand;
    private LocalDate date;
    private String country;
    private String client;
    private String airco;
    private String transmission;
    private String seats;
    
    getters and setters
}

Answer 1

我从上面了解的是，您正在尝试丰富searchRequest，然后再将其传递给someService＃search。我认为您可以实施一些自定义的策略模式。让我们看看如何：

创建一个界面searchRequestenricher，如下所示，

public interface SearchRequestEnricher {
    boolean isApplicable(SearchRequest searchRequest);
    void enrich(SearchRequest searchRequest);
}

为每个字段创建searchRequestenricher实现（例如，我将仅在这里创建2个）

typeenricher

@Component
public class TypeEnricher implements SearchRequestEnricher{

    @Override
    public boolean isApplicable(SearchRequest searchRequest) {
        return searchRequest.getType() != null;
    }

    @Override
    public void enrich(SearchRequest searchRequest) {
        //your dosomething business logic
    }
}

brandenricher，

@Component
public class BrandEnricher implements SearchRequestEnricher{

    @Override
    public boolean isApplicable(SearchRequest searchRequest) {
        return searchRequest.getBrand() != null;
    }

    @Override
    public void enrich(SearchRequest searchRequest) {
        //your dosomething business logic
    }
}

现在您可以在控制器中以这种方式在控制器中使用这些富集

@RestController
public class SearchController {
    private List<SearchRequestEnricher> searchRequestEnrichers;
    
    @PostMapping("/searchCarOptions")
    public ResponseEntity<Cars> search(
            @Parameter(description = "some searchRequest") @RequestBody SearchRequest searchRequest) {
        //enrich your request
        searchRequestEnrichers.stream().filter(searchRequestEnricher -> searchRequestEnricher.isApplicable(searchRequest))
                .forEach(searchRequestEnricher -> searchRequestEnricher.enrich(searchRequest));
        //use enriched request
        return ResponseEntity.ok(someService.search(searchRequest));
    }
}

，您的控制器是干净的，并且不干净具有任何业务逻辑（因为它应该没有）。您正在遵循关注和单一责任原则的分离。如果在searchRequest中添加或删除额外的参数，则无需触摸控制器，并且想验证/富集它们。

希望这会有所帮助。