使用缓存时进行查询返回404

发布于 2025-02-13 09:36:57 字数 800 浏览 0 评论 0原文

在我的控制器中，我拥有

public function single($slug)
    {
        return view('post.single', [
            'country' => $this-> getPostBySlugCached($slug),
        ]);
    }

和缓存特征：

private function getPostBySlugCached(string $slug)
    {
        return Cache::tags(['post'])->remember('post:slug:'.$slug, CacheRemember::FOUR_WEEKS, function () use ($slug) {
            return Post::where('slug', $slug)
                ->firstOrFail();
        });
    }

但是如果我放入不退出的sl，我不会得到404，这是我期望的，鉴于我正在使用firstorfail（）。相反，我会发现错误，因为$ post在刀片视图中为null。是因为cache ::记住返回null？如果是这样，我该如何实现以使其返回404？

原文

In my controller I have

public function single($slug)
    {
        return view('post.single', [
            'country' => $this-> getPostBySlugCached($slug),
        ]);
    }

And in a cache trait:

private function getPostBySlugCached(string $slug)
    {
        return Cache::tags(['post'])->remember('post:slug:'.$slug, CacheRemember::FOUR_WEEKS, function () use ($slug) {
            return Post::where('slug', $slug)
                ->firstOrFail();
        });
    }

But what happens if I put in a slug that doesn't exit, I don't get a 404 which is what I would expect given I'm using firstOrFail(). Instead I get errors because $post in the blade view is null. Is that because Cache::remember returns null? If so, how can I achieve so that it will return a 404?

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め可乐爱微笑 2025-02-20 09:36:57

对您的控制器的较小更改

    public function single($slug)
    { 
        $country = $this-> getPostBySlugCached($slug);

        abort_if(!$country,404);

        return view('post.single', compact('country');
    }

small change to your controller

    public function single($slug)
    { 
        $country = $this-> getPostBySlugCached($slug);

        abort_if(!$country,404);

        return view('post.single', compact('country');
    }

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