在Python中，是否有可能在没有范围的情况下运行一些代码？

发布于 2025-02-13 09:10:16 字数 284 浏览 0 评论 0原文

我最喜欢的调试工具之一是启动控制台的简短代码。但是，我有时会通过（大致）调试

try: 
    #my code
    ...
except:
    launch_console()

，这需要预测错误的位置。如果我将整个脚本包装在尝试/除外，则我将无法访问我正在调试的函数中的任何变量。

如果我可以运行该程序，并且只需在错误的情况下运行在不丢失范围的情况下运行，那将非常方便。我认为Spyder应该具有此功能，但它不起作用。

想知道是否有一些不错的方法！

原文

One of my favorite debug tools is a short piece of code which starts up a console. I sometimes debug by means of (roughly)

try: 
    #my code
    ...
except:
    launch_console()

However, this requires anticipating where the error will be. If I enclose the entire script in a try/except, I will not have access to any variables within the function I am debugging.

It would be magnificently convenient, if I could run the program and just automatically have launch_console() run in case of an error, without losing scope. I think spyder is supposed to have this functionality, but it does not work.

Wondering if there is some nice way to do this!

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