程序无法处理错误

Question

1. 这是快速主机端口扫描仪的源代码...我添加了一些错误处理...但是该程序无法读取错误处理内容，而当主机无效时，它只是给出了正常的Python错误。 ..我在哪里弄错了？

2. 如何将此程序的输出打印到文本文件？ （我在最后尝试过，但它不起作用。

对任何帮助都非常感谢！

源代码：

#!/usr/bin/env python
import socket
import concurrent.futures
import subprocess
import sys
from datetime import datetime
    
# Clear the screen
subprocess.call('clear', shell=True)

# Ask for input
remoteServer = input("Enter a remote host to scan: ")
remoteServerIP  = socket.gethostbyname(remoteServer)

# Prints a banner with info on which host we are about to scan
print ("-" * 60)
print ("Please wait, scanning remote host", remoteServerIP)
print ("-" * 60)

# Check what time the scan started
t1 = datetime.now()

def scan(remoteServerIP, port):
    sock = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
    sock.settimeout(1)
    
    try:
        remoteServerIP  = socket.gethostbyname(remoteServer)
        result = sock.connect_ex((remoteServerIP, port))        
        if result == 0:
            print ("Port {}:      Open".format(port))
            sock.close()
            
    # We have also put in error handling for catching errors
    except KeyboardInterrupt:
        print ("You pressed Ctrl+C")
        sys.exit()

    except socket.gaierror:
        print ('Hostname could not be resolved. Exiting')
        sys.exit()

    except socket.error:
        print ("Host is not available",)
        sys.exit()

with concurrent.futures.ThreadPoolExecutor(max_workers=75) as executor:
    for port in range(1,1025):
        executor.submit(scan, remoteServerIP, port + 1)

# Checking the time again
t2 = datetime.now()

# Calculates the difference of time, to see how long it took to run the script
total =  t2 - t1

# Printing the information to screen
print ('Scanning Completed in: ', total)

#Text file
f = open('Hostreport.txt', 'a')
print(port,file=f)
f.close()

当前输出IM（当ertleing无效主机）：

输出SS

Answer 1

您没有处理错误！您的错误在此线上发生。除了块之外，不在尝试中

# Ask for input
remoteServer = input("Enter a remote host to scan: ")
remoteServerIP  = socket.gethostbyname(remoteServer)  # this one.