如何根据多个条件对不同输出的列表进行排序。反应

发布于 2025-02-13 07:23:33 字数 770 浏览 1 评论 0原文

我试图根据他们的分数对参赛者进行排序。如果分数相同，我想对它们进行对另一个值进行排序。

到目前为止 setSortedEntrants（props.event.entrants.sort（（（a，b）=＆gt;（A.Score＆lt; B.Score）？-1：1））;>

>>在当前的参赛者中分类分数。我想补充一点，以便如果分数匹配，我想在另一个值上对a.scorecard.back9score vs b.scorecard.back9score进行对那些进行

排序非常正确的

setSortedEntrant（props.event.entrants.sort（（（a，b）=＆gt;（a.score＆lt; b.score）？-1：A.Score ？scorecard.back9score＆lt;

b.score

1- if a.score is less than b.score, move up one
2 - if a.score equals b.score then if a.scoreCard.back9Score  is less than b.scoreCard.back9Score then move up one.
3 - otherwise if a.score > b.score move down one.

== 和scorecardback9score，数字

很明显，我出了错。

原文

I am trying to sort a list of entrants depending on their scores. If the score are the same, I then want to sort them on another value.

So far I have
setSortedEntrants(props.event.entrants.sort((a, b) => (a.score < b.score) ? -1 : 1));

which sorts the entrants on their current score. I want to add to this, so that if the scores match, I then want to sort those on another value a.scoreCard.back9Score vs b.scoreCard.back9Score

I have tried this but doest seem to be quite right

setSortedEntrants(props.event.entrants.sort((a, b) => (a.score < b.score) ? -1 : a.score === b.score ? a.scoreCard.back9Score < b.scoreCard.back9Score: -1 ? a.score > b.score : 1));

logic being,

1- if a.score is less than b.score, move up one
2 - if a.score equals b.score then if a.scoreCard.back9Score  is less than b.scoreCard.back9Score then move up one.
3 - otherwise if a.score > b.score move down one.

all values for score and scoreCardback9Score and numbers

Is there somewhere obvious I am going wrong.

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怀念你的温柔 2025-02-20 07:23:33

条件应如下。您放置了正确的代码缩进，然后可以找出三元运营商的匹配条款。

        setSortedEntrants(props.event.entrants.sort((a, b) => 
            (a.score < b.score) ? 
              -1 
               : (a.score === b.score ? 
                     (a.scoreCard.back9Score < b.scoreCard.back9Score ? 
                     -1 
                     : 1)
                 : 1)
            );

the condition should be as follows. You put the right code indentation, then you can figure out the matching clauses of ternary operator.

        setSortedEntrants(props.event.entrants.sort((a, b) => 
            (a.score < b.score) ? 
              -1 
               : (a.score === b.score ? 
                     (a.scoreCard.back9Score < b.scoreCard.back9Score ? 
                     -1 
                     : 1)
                 : 1)
            );

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