试图预测预测值大于0.5，它将是正预测（1），低于0.5值为0，但在循环中存在问题

发布于 2025-02-13 05:17:51 字数 767 浏览 0 评论 0原文

训练模型后，评估dtype = float32上的预测。

y_pred = model.predict(x_test)
y_pred

array([[0.952564  ],
       [0.40119413],
       [0.8223132 ],
       ...,
       [0.03289893],
       [0.16677496],
       [0.882395  ]], dtype=float32)

result = model.evaluate(np.asarray(x_test), np.asarray(y_test))  
loss = result[0]
accuracy = result[1]
print(f"[+] Accuracy: {accuracy*100:.2f}%")

因此，为此，我有float32，但为正面＆amp; 0对于neg，为此，我有一些问题，所以我要这样做，将其float32到int32＆amp;一个循环，如果值大于0.5，则将其计为1＆amp;如果小于0.5，则计数为0表示负。我尝试的循环：

y_pred = model.predict(x_test)
y_pred ( for i in range(len(y_pred)):
  if y_pred[i][0] >= 0.5:
    y_pred[i][0] = int(1)
  else:
    y_pred[i][0] = 0



print(y_pred[0]) )

错误是：无效语法。

谁能帮忙解决这个问题？

原文

After training the model , evaluating prediction that is on dtype=float32.

y_pred = model.predict(x_test)
y_pred

array([[0.952564  ],
       [0.40119413],
       [0.8223132 ],
       ...,
       [0.03289893],
       [0.16677496],
       [0.882395  ]], dtype=float32)

result = model.evaluate(np.asarray(x_test), np.asarray(y_test))  
loss = result[0]
accuracy = result[1]
print(f"[+] Accuracy: {accuracy*100:.2f}%")

so , for this i have float32 but 1 for positive & 0 for neg, for this i have some issue , so i am trying to do, make it float32 to int32 & a loop that if value is greater than 0.5 then it will count as 1 & if less than 0.5 then count as 0 means neg.
the loop i tried :

y_pred = model.predict(x_test)
y_pred ( for i in range(len(y_pred)):
  if y_pred[i][0] >= 0.5:
    y_pred[i][0] = int(1)
  else:
    y_pred[i][0] = 0



print(y_pred[0]) )

error is : invalid syntax .

can anyone help to sort out this one ?

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心碎无痕… 2025-02-20 05:17:51

似乎您应该使用y_pred [0] [i]。该数组看起来只有一个子数组，因此应使用[0] [i]。另外，如果代码正是编写的，我认为

y_pred ( for i in range(len(y_pred)):

应该是

for i in range(len(y_pred)):

Seems like you should use y_pred[0][i]. The array looks to be 2d with only one sub array, so [0][i] should be used. Also, if the code is exactly what is written, i think