无法自动passwordhasherinterface

Question

我正在尝试在“固定装置”类中自动passwordhasherinterface：

<?php
namespace App\DataFixtures;

use App\Model\User\Entity\User\Email;
use App\Model\User\Entity\User\Id;
use App\Model\User\Entity\User\Role;
use App\Model\User\Entity\User\User;
use Doctrine\Bundle\FixturesBundle\Fixture;
use Doctrine\Persistence\ObjectManager;
use Symfony\Component\PasswordHasher\PasswordHasherInterface;

class UserFixture extends Fixture
{
    private PasswordHasherInterface $hasher;

    public function __construct(PasswordHasherInterface $hasher)
    {
        $this->hasher = $hasher;
    }
    
    public function load(ObjectManager $manager): void
    {
        $hash = $this->hasher->hash("password");

        $user = User::signUpByEmail(
            Id::next(),
            new \DateTimeImmutable(),
            new Email("[email protected]"),
            $hash,
            "token"
        );

        $user->confirmSignUp();

        $user->changeRole(Role::admin());

        $manager->persist($user);
        $manager->flush();
    }
}

但是我有错误：

在DefacitionerRorexceptionpass.php行54： !!
!!无法自动服务“应用程序\ datafixtures \ userFixture”：参数“ $ hasher”
!!方法“ __construct（）”参考接口“ Symfony \ Component \ passwordh
!! ASHER \ passwordHasherInterface”但是没有这样的服务。您是否创建了
!!实现此接口的类？
!!

我的file services.yaml：

parameters:

services:
    # default configuration for services in *this* file
    _defaults:
        autowire: true      # Automatically injects dependencies in your services.
        autoconfigure: true # Automatically registers your services as commands, event subscribers, etc.

    # makes classes in src/ available to be used as services
    # this creates a service per class whose id is the fully-qualified class name
    App\:
        resource: '../src/'
        exclude:
            - '../src/DependencyInjection/'
            - '../src/Model/User/Entity/'
            - '../src/Kernel.php'

如何在Symfony 6.1中使用平原密码？ 为什么我会遇到这个错误？

Answer 1

没有一般passwordhasher。

您要么：

• 使用工厂生成特定的：例如symfony \ component \ compents \ passwordHasher \ hasher \ passwordHasherFactoryInterface
• 或您使用专用的密码hasher类：eg symfony \ component \ component \ component \ passwordHasher \ passwordHasher \ passwordHasher \ hasher \ hasher \ hasher \ userpasswordhasherinterface用于用户*。

使用工厂，您的代码看起来像这样：（未经测试）

//...
use Symfony\Component\PasswordHasher\Hasher\PasswordHasherFactoryInterface;


class UserFixture extends Fixture
{
    private PasswordHasherFactoryInterface $passwordHasherFactory;

    public function __construct(PasswordHasherFactoryInterface $hasherFactory)
    {
      $this->passwordHasherFactory = $passwordHasherFactory;
    }
    
    public function load(ObjectManager $manager): void
    {
        $passwordHasher = $this->passwordHasherFactory->getPasswordHasher(User::class);
        $hash = $passwordHasher->hash("password");

        $user = User::signUpByEmail(
            Id::next(),
            new \DateTimeImmutable(),
            new Email("[email protected]"),
            $hash,
            "token"
        );

        $user->confirmSignUp();

        $user->changeRole(Role::admin());

        $manager->persist($user);
        $manager->flush();
    }

只是为了重申，这些步骤是：

1. 安装软件包：作曲家要求Symfony/password-Hasher
3. 加载哈瑟
   • 加载userpasswordhasherinterface或
   • 加载passwordHasherFactoryInterface（请参阅示例）并获取passwordhasher

*：userpasswordhasherinterface的示例位于在这里。