编写字节而无需填充
鉴于这两个数字（自Unix时期以来毫秒），1656773855233和1656773888716，我正在尝试将它们写入二进制对象。踢者是我想将它们写入11个字节对象。
如果我接受时间戳只能在2039年9月7日之前代表日期，则这些数字应分别适合41位。 2 41位数字适合88位（11比），超过6位。
我已经尝试了以下Python代码，作为实现这一目标的（相当天真的）方法：
receive_time=1656773855233
event_time=1656773888716
with open("test.bin", "wb") as f:
f.write(receive_time.to_bytes(6, "big"))
f.write(event_time.to_bytes(6, "big"))
print(f"{receive_time:08b}")
print(f"{event_time:08b}")
with open("test.bin", "rb") as f:
a = f.read()
print(" ".join(f"{byte:08b}" for byte in a))
该代码的输出非常清楚地表明test.bin文件为12个字节，因为每个时间戳都是填充的将7 0转换为字节时。
我将如何将时间戳写入test.bin而无需单独填充它们？
The end result should be something like 0000001100000011011111101101010110010000000000111000000110111111011010110100101011001100 or 3037ED5900381BF6B4ACC
EDIT: Question originally mentioned that a 41bit number could only represent dates before May 15th, 2109 if that number自Unix时期以来代表毫秒。正如Interjay正确指出的那样，这是错误的，41位数字仅代表69,7年，因此最大日期将是2039年9月7日。但是，一个42位数字可以代表一个代表日期的数字，该号码在2109年5月15日之前日期。
Given these 2 numbers (milliseconds since Unix epoch), 1656773855233 and 1656773888716, I'm trying to write them to a binary object. The kicker is that I want to write them to a 11 byte object.
If I accept that the timestamps can only represent dates before September 7th 2039, the numbers should each fit within 41bits. 2 41bit numbers fits within 88bit (11bytes) with 6 bits in excess.
I've tried the following python code, as a (rather naive) way to achieve this:
receive_time=1656773855233
event_time=1656773888716
with open("test.bin", "wb") as f:
f.write(receive_time.to_bytes(6, "big"))
f.write(event_time.to_bytes(6, "big"))
print(f"{receive_time:08b}")
print(f"{event_time:08b}")
with open("test.bin", "rb") as f:
a = f.read()
print(" ".join(f"{byte:08b}" for byte in a))
The output of the code very clearly shows that the test.bin file is 12 bytes, because each timestamp is padded with 7 0's when converted to bytes.
How would I go about writing the timestamps to test.bin without padding them individually?
The end result should be something like 0000001100000011011111101101010110010000000000111000000110111111011010110100101011001100 or 3037ED5900381BF6B4ACC
EDIT: Question originally mentioned that a 41bit number could only represent dates before May 15th, 2109 if that number represented milliseconds since the Unix epoch. That is wrong, as interjay correctly pointed out, a 41bit number would only represent 69,7 years and the max date would thus be September 7th, 2039. A 42bit number, however, can represent a number that represents dates before May 15th, 2109.
如果你对这篇内容有疑问，欢迎到本站社区发帖提问 参与讨论，获取更多帮助，或者扫码二维码加入 Web 技术交流群。
绑定邮箱获取回复消息
由于您还没有绑定你的真实邮箱，如果其他用户或者作者回复了您的评论，将不能在第一时间通知您！
发布评论
评论（1）
在将其转换为
bytes：Use a bit shift to combine both times into the same int, before converting that to
bytes: