为什么当构造函数称为5次时，攻击函数仅一次称为一次？
我正在尝试了解有关C ++的更多信息，在此代码中，我正在分配一个A的数组（在这种情况下为5），我了解5 A将被分配...因此编译器将使Consenter称为约束5倍，但是，如果删除该数组仅一次称驱动器一次，所以我的问题是，为什么只有在具有5个A时才将其称为Destructor一次，他不应该将destructor称为5次？
我有此代码：
#include <iostream>
using namespace std;
class A {
public:
A() { std::cout << "IM in C'tor" << std::endl; };
~A() { std::cout << "IM in De'tor" << std::endl; }
};
int main()
{
A* a = new A[5];
delete a; // ingone the errors,the important thing is calling the
C'tor and D'tor`
return 0;
}
I'm trying to learn more about C++ ,int this code I'm allocating an array of A's (5 in this case), what I understand that 5 A's will be allocated ...so the compiler will call 5 times the constructer , but in case of deleting that array it calls the destructor one time only ,so my question is why does it call the destructor one time only when it has 5 A's , shouldn't he call the destructor 5 times??
I have this code :
#include <iostream>
using namespace std;
class A {
public:
A() { std::cout << "IM in C'tor" << std::endl; };
~A() { std::cout << "IM in De'tor" << std::endl; }
};
int main()
{
A* a = new A[5];
delete a; // ingone the errors,the important thing is calling the
C'tor and D'tor`
return 0;
}
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您需要使用
delete [] a来删除分配了new []的数组。如果这样做，您会看到正确的输出：You need to use
delete[] ato delete an array of things allocated withnew[]. If you do that, you'll see the correct output: