生锈:异步不同意
async fn learn_and_sing() {
// Wait until the song has been learned before singing it.
// We use `.await` here rather than `block_on` to prevent blocking the
// thread, which makes it possible to `dance` at the same time.
let song = learn_song().await;
sing_song(song).await;
}
async fn async_main() {
let f1 = learn_and_sing();
let f2 = dance();
// `join!` is like `.await` but can wait for multiple futures concurrently.
// If we're temporarily blocked in the `learn_and_sing` future, the `dance`
// future will take over the current thread. If `dance` becomes blocked,
// `learn_and_sing` can take back over. If both futures are blocked, then
// `async_main` is blocked and will yield to the executor.
futures::join!(f1, f2);
}
fn main() {
block_on(async_main());
}
它说
在此示例中,学习歌曲必须在唱歌之前发生,但是学习和唱歌都可以在跳舞的同时发生。
但是我不能明白这一点。我在Rust中写了一个简短的代码
async fn learn_song() -> &'static str {
println!("learn_song");
"some song"
}
#[allow(unused_variables)]
async fn sing_song(song: &str) {
println!("sing_song");
}
async fn dance() {
println!("dance");
}
async fn learn_and_sing() {
let song = learn_song().await;
std::thread::sleep(std::time::Duration::from_secs(1));
sing_song(song).await;
}
async fn async_main() {
let f1 = learn_and_sing();
let f2 = dance();
let f3 = learn_and_sing();
futures::join!(f1, f2, f3);
}
fn main() {
futures::executor::block_on(async_main());
}
,似乎所有异步在async_main
同步执行中的功能。
输出是
learn_song
sing_song
dance
learn_song
sing_song
,如果它们异步运行,我希望如果我添加了Learn_and_sing
的额外调用,我希望在输出中得到类似的东西
learn_song
dance
learn_song
sing_song
sing_song
,它会像同步函数中一样打印钢。
问题为什么?是否可以仅使用async/.await
和无线程制作真实的异步?
Here's the example from the Rust book.
async fn learn_and_sing() {
// Wait until the song has been learned before singing it.
// We use `.await` here rather than `block_on` to prevent blocking the
// thread, which makes it possible to `dance` at the same time.
let song = learn_song().await;
sing_song(song).await;
}
async fn async_main() {
let f1 = learn_and_sing();
let f2 = dance();
// `join!` is like `.await` but can wait for multiple futures concurrently.
// If we're temporarily blocked in the `learn_and_sing` future, the `dance`
// future will take over the current thread. If `dance` becomes blocked,
// `learn_and_sing` can take back over. If both futures are blocked, then
// `async_main` is blocked and will yield to the executor.
futures::join!(f1, f2);
}
fn main() {
block_on(async_main());
}
And it's says
In this example, learning the song must happen before singing the song, but both learning and singing can happen at the same time as dancing.
But I can't get this point. I wrote a short code in Rust
async fn learn_song() -> &'static str {
println!("learn_song");
"some song"
}
#[allow(unused_variables)]
async fn sing_song(song: &str) {
println!("sing_song");
}
async fn dance() {
println!("dance");
}
async fn learn_and_sing() {
let song = learn_song().await;
std::thread::sleep(std::time::Duration::from_secs(1));
sing_song(song).await;
}
async fn async_main() {
let f1 = learn_and_sing();
let f2 = dance();
let f3 = learn_and_sing();
futures::join!(f1, f2, f3);
}
fn main() {
futures::executor::block_on(async_main());
}
And it seems like all the async functions in the async_main
executed synchronously.
The output is
learn_song
sing_song
dance
learn_song
sing_song
If they run asynchronously, I would expect to get something like this in my output
learn_song
dance
learn_song
sing_song
sing_song
If I add an extra call of learn_and_sing
it would steel be printed like in a synchronous function.
The question Why so? Is it possible to make a real async using only async/.await
and no threads?
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就像Tkausl的评论所述,STD :: Thread :: Sleep select sheep sheck the the the the Thread Sleep,可以防止线程上的任何代码在睡眠期间执行。您可以使用 async_std ::在这种情况下,因为它是睡眠功能的异步版本。
Like tkausl's comment states, std::thread::sleep makes the whole thread sleep, which prevents any code on the thread from executing during the sleeping duration. You could use async_std::task::sleep in this situation, as it is an asynchronous version of the sleep function.