获取重定向的URL

发布于 2025-02-13 00:58:55 字数 919 浏览 0 评论 0原文

嘿，我从“基础” URL的“我的代码”中获取重定向URL有问题

：

我在互联网中发现了很多tipps，但没有任何作用。始终获取我的“基本” URL，但它应该输出将其重定向到的URL。

有人有什么想法吗？

url = apiurl.de/apiexample'
        servers = session.get(url, headers=headers).result().json()['results']
        for server in servers:
            server_id = server['id']
            
            invite_url = f'apiurl.com/api'

            user_agent = 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_9_2) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/34.0.1847.131 Safari/537.36'
            
            s = requests.Session()
            s.headers['User-Agent'] = user_agent
            r = s.get(invite_url, allow_redirects=True, timeout=10)

            print(f'[redirected url]: {r.url}')

原文

Hey i have a problem with getting the redirect url from my "base" url

heres my code:

i found a lot of tipps in the internet but nothing really works. always get my "base" url but it should output the url it gets redirected to.

does someone have any idea?

url = apiurl.de/apiexample'
        servers = session.get(url, headers=headers).result().json()['results']
        for server in servers:
            server_id = server['id']
            
            invite_url = f'apiurl.com/api'

            user_agent = 'Mozilla/5.0 (Macintosh; Intel Mac OS X 10_9_2) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/34.0.1847.131 Safari/537.36'
            
            s = requests.Session()
            s.headers['User-Agent'] = user_agent
            r = s.get(invite_url, allow_redirects=True, timeout=10)

            print(f'[redirected url]: {r.url}')