如何根据长期运行命令结果退出或重试

Question

我正在尝试监视long_running_command函数的输出（如果输出包含result ='good''，然后print wow wow < /代码>并返回。但是，直到long_running_command没有返回result ='good'继续尝试，直到达到max_try。 到目前为止一切都很好。但是，如果命令已经返回result ='失败'，则没有重试的点，我如何出错（打印nay）不重试？

以下是示例程序（最小工作问题声明）：

#!/bin/bash

MAX_TRY=5


#Simulating a fake long running command that may return good or failed randomly with a small delay
long_running_command()
{

    wait_time=$(shuf -i 1-5 -n 1)
    sleep "$wait_time"

    if [ "$path" -eq 1 ];then
        echo "result='good'"
    elif [ "$path" -eq 0 ];then
        echo "result='failed'"
    else
        echo "This path should never hit"
    fi

}



# Some external conditions cannot be controlled by me, faking it
#0 means fail
#1 means pass
path=$(shuf -i 0-1 -n 1)



check_result() {
    while [ $MAX_TRY -le 10 ];do
    if long_running_command |grep -qE 'result.*good' ;then
        echo "$(date): WOW"
        return 0 
    fi
        echo "$(date): Retrying...so far the output does not have good in it or perhaps its failed already"
    MAX_TRY=$((MAX_TRY + 1))
         
    done
    echo "$(date): NAY"
}

check_result

TLDR，如果命令返回失败或良好，我需要从重试循环中退出。稍后，根据结果打印`哇或否。

Answer 1

将输出保存在变量中。然后，您可以测试它是否包含result ='好'或result ='失败'。如果这两个，你都会重试。

check_result() {
    while [ $MAX_TRY -le 10 ]
    do
        output=$(long_running_command | grep -E "result='(good|failed)'")
        case "$output" in
            *good*) 
                # Return success immediately
                echo "$(date): WOW"
                return 0
                ;;
            *failed*)
                # No point in retrying
                break
                ;;
        esac
        MAX_TRY=$((MAX_TRY + 1))
    done
    echo "$(date): NAY"
    return 1
}