发电机中的迭代输入（）
现在，我正在研究Python课程，但是该任务中的数据是作为输入形成的，而不是作为功能的参数，例如在CodeWars中。
要编写生成器，我必须使用输入，这无法迭代。事实证明，此代码：（
dots = [input() for x in range(int(input()))]
parsedDots = [dot for dot in dots if not '0' in dot]
此代码应在只有零坐标的情况下列出一个列表）
是否有可能将这两个生成器组合到一个？
输入数据示例：
4
0 -1
1 2
0 9
-9 -5
Now I am working on a python course, but the data in the tasks there is formed as inputs, and not as arguments to the function, as for example in codewars.
To write generators, I have to use input, which cannot be iterated. It turns out this code:
dots = [input() for x in range(int(input()))]
parsedDots = [dot for dot in dots if not '0' in dot]
(This code should make a list where only inputs() without zero coordinate are taken into)
Is it possible, to combine this two generators into one?
Input data example:
4
0 -1
1 2
0 9
-9 -5
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评论（1）
您可以使用 Walrus Operator，：= < < /a>在3.8+中：3.8
pre-3.8，您能做的最好的就是将您的原始列表理解（急切地，将
list>）转换为发电机表达式（Lazy），因此您不会制作实际的list，直到您过滤掉垃圾后：略 的开销比Walrus解决方案高，但是峰值内存使用情况没有有意义的人均增加，并且自引入发电机表达式以来（2.4ish？），它在每种版本的Python上都起作用。
You can combine them using the walrus operator,
:=in 3.8+:Pre-3.8, the best you can do is convert your original list comprehension (eager, materializes a
list) to a generator expression (lazy), so you don't make an actuallistuntil after you've filtered out the garbage:That has slightly higher overhead than the walrus solution, but no meaningful per-item increase in peak memory usage, and it works on every version of Python since generator expressions were introduced (2.4ish?).