console.debug（）的包装器：如何用object.defineProperty（）覆盖字符串？

Question

我构建了一个用于伐木的课程，这使您可以关闭记录，但要将呼叫留在代码中。 （并使用正确的行和文件。）

基于此，我想要托多斯（Todos）的鲜艳色彩，但我设法仅着色'[todo]'，其余文本以默认的颜色保留。

class Logger {

    // Don't forget console needs to be set to 'All levels' to display debug. ;)

    public OFF = 0;
    public LOG = 1;
    // ...
    public ALL = 9;
    
    private level = 1;
    
    public constructor() {
        /*this.init();*/ // killed for testing
    }
    
    // This is the original method.
    // Color is fine, but wrong line and file.
    public todo(message?: string, ...optionalParams: any[]) {
        const css = 'background: #FF0000; color: #0000FF';
        optionalParams.length != 0
            ? console.debug('%c[TODO] '+message, css, optionalParams) 
            : console.debug('%c[TODO] '+message, css);
    }    
     
    // This overrides the todo method and gives the correct line and file,
    // but the color is destroyed.
    // And the optionalParams no longer an array.
    /*private*/ public init() { // public for testing.
        Object.defineProperty(this, "todo", {get: function () {
            return this.level >= this.LOG 
                ? console.debug.bind(console, '%c[TODO]', 'background: #FF0000; color: #0000FF') 
                : function(){};},
            configurable: true
        });     
    }
    
    public setLevel(level: Level) {
        this.level = level;
        this.init();
    }

}

// Test
const logger = new Logger();

logger.todo('normal todo().');
logger.todo('normal todo() with data.', 666, 777);

logger.init(); // This is why init is not called in constructor and public. ;)

logger.todo('modified todo().');
logger.todo('modified todo() with data.', 666, 777);

我还创建了一个 jsfiddle 与代码。

是否可以使用object.defineproperty为整个消息上色，如果是这样？